Chapter 15, Problem 27CR

Interpretation Introduction

Interpretation:

One equivalent of an acid is to be defined. An equivalent of a base is to be explained. The relation between the equivalent weight of an acid or a base and the substance’s molar mass is to be explained. An example of an acid and a base that have equivalent weights equal to their molar masses is to be stated. An example of an acid and a base that have equivalent weights that are not equal to their molar masses is to be given. The normal solution of an acid or a base is to be defined. The relation between the normality of an acid or a base solution and its molarity is to be explained. An example of a solution that has equal normality and molarity, and an example of a solution that have different normality and molarity is to be stated.

Concept Introduction:

The molarity of a solution is the molar concentration of the solution; it measures the number of moles of solute dissolved in one liter of the solution. The formula for molarity is given as,

$\text{M}=\frac{\text{n}}{\text{V}}$

Where,

• $\text{n}$ represents the number of moles of the solute.
• $\text{V}$ represents the volume of the solution.

The normality of a solution is referred as the gram equivalent weight of a solute dissolved in one liter of the solution. The normality of solution is given as:

$\text{N}=\frac{{\text{n}}_{\text{eq}}}{\text{V}}$

Where,

• ${\text{n}}_{\text{eq}}$ represents the number of equivalents of the solute.
• $\text{V}$ represents the volume of the solution.