Chapter 15, Problem 80E

Interpretation Introduction

Interpretation:

For ${\text{Ba(OH)}}_2$, correct expression of solubility product $\left({\text{K}}_{\text{sp}}\right)$ is to be determined with help of concentration of ions dissolves in the solvent.

Concept Introduction:

The solubility product $\left({\text{K}}_{\text{sp}}\right)$ expression for any compound is the mathematical product of the concentration of their constituent ions raised to the power of their stoichiometric coefficient.

Solubility product has a unit of concentration $\text{M}$ or $\frac{\text{mol}}{\text{liter}}$.

For the given chemical equation $\text{A + B }\to \text{ C +}\text{}\text{D}$, the solubility product is given by ${\text{K}}_{\text{sp}}\text{ = }\left[\text{C}\right]\left[\text{D}\right]$.

If the solvent has some ions that present in the salt dissolve in the solvent in such case solubility of salt decreases.