Chemistry: The Molecular Nature of Matter and Change - Standalone book
Chemistry: The Molecular Nature of Matter and Change - Standalone book
7th Edition
ISBN: 9780073511177
Author: Martin Silberberg Dr., Patricia Amateis Professor
Publisher: McGraw-Hill Education
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Chapter 15, Problem 15.116P

(a)

Interpretation Introduction

Interpretation:

The hydrolysis of a 100.00-g sample of peptide forms the given individual amounts of amino acids (molar mass in g/mol are given in parentheses).

  3.00 g of glycine (75.07)               0.90 g of alanine (89.10)3.70 g of valine (117.15)               6.90 g of proline (115.13)7.30 g of serine (105.10)               86.00 g of arginine (174.21)

Why the total mass of amino acids exceeds the mass of peptide has to be given.

(a)

Expert Solution
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Explanation of Solution

The peptides are formed by the amino acid units.  Amino acids combines together to form the amide bonds of peptides.  The amide bond is formed by the loss of water molecule from amine group of one amino acid and carboxylic acid group of another amino acid.

Chemistry: The Molecular Nature of Matter and Change - Standalone book, Chapter 15, Problem 15.116P

As the loss of water molecule occurs in the formation of peptide, the mass of peptide is less than that of total mass of amino acids.

(b)

Interpretation Introduction

Interpretation:

The hydrolysis of a 100.00-g sample of peptide forms the given individual amounts of amino acids (molar mass in g/mol are given in parentheses).

  3.00 g of glycine (75.07)               0.90 g of alanine (89.10)3.70 g of valine (117.15)               6.90 g of proline (115.13)7.30 g of serine (105.10)               86.00 g of arginine (174.21)

The relative numbers of amino acids in the peptide has to be given.

Concept Introduction:

The relative numbers can be calculated by converting the mass in to moles and by dividing the moles with smallest number.

(b)

Expert Solution
Check Mark

Explanation of Solution

The given amounts of amino acids are

  3.00 g of glycine (75.07)               0.90 g of alanine (89.10)3.70 g of valine (117.15)               6.90 g of proline (115.13)7.30 g of serine (105.10)               86.00 g of arginine (174.21)

The mass of amino acids is converted to moles by using the equation

  moles = mass (g)molar mass (g/mol)

Glycine:

  moles = 3.00 g75.07 g/mol          = 0.0399627 mol   

Alanine:

  moles = 0.90 g89.10 g/mol          = 0.010101010 mol   

Valine:

  moles = 3.70 g117.15 g/mol          = 0.0315834 mol   

Proline:

  moles = 6.90 g115.13 g/mol          = 0.0599323 mol   

Serine:

  moles = 7.30 g105.10 g/mol          = 0.0694577 mol   

Arginine:

  moles = 86.00 g174.21 g/mol          = 0.493657 mol   

The moles obtained can be divided by the smallest number to get the relative number.

The smallest number is 0.010101010 mol of alanine.

  Glycine  :  0.0399627 mol0.010101010 mol = 4Alanine  :  0.010101010 mol0.010101010mol  =1Valine    :  0.0315834 mol0.010101010 mol   =3Proline   :  0.0599323 mol0.010101010 mol   =6Serine     :  0.0694577 mol0.010101010 mol   =7Arginine  :  0.493657 mol0.010101010 mol  =49

The relative numbers of amino acids are calculated.

(c)

Interpretation Introduction

Interpretation:

The hydrolysis of a 100.00-g sample of peptide forms the given individual amounts of amino acids (molar mass in g/mol are given in parentheses).

  3.00 g of glycine (75.07)               0.90 g of alanine (89.10)3.70 g of valine (117.15)               6.90 g of proline (115.13)7.30 g of serine (105.10)               86.00 g of arginine (174.21)

The minimum molar mass of the peptide has to be given.

Concept Introduction:

The minimum molar mass of peptide can be calculated by adding the products of moles of each amino acid with their molar mass to get the amount of amino acids and the water molecules mass is eliminated from the mass of amino acids to get the molar mass of peptide.

(c)

Expert Solution
Check Mark

Explanation of Solution

The minimum molar mass of the peptide is calculated as

  mass of 70 moles of amino acids = (4×75.07 g/mol)+(1×89.09 g/mol)+(3×117.15 g/mol)                                                       +(6×115.13g/mol)+(7×105.09 g/mol)+(49×174.20 g/mol)                                                   = 10,703.59 g

70 Moles of amino acids are linked by 69 peptide bonds.  For the formation of one peptide bond, one water molecule is removed.  Thus, for 69 peptide bonds 69 water molecules are removed.

  mass of H2O eliminated = (69 mol H2O)(18.02 g H2O1 mol H2O)                                       = 1243.38 g

The minimum molar mass of peptide bond is calculated by subtracting the mass of water molecules from the mass of amino acids.

  minimum mass of peptide = 10,703.59g - 1243.38g                                         = 9,460 g/mol 

The minimum mass of peptide is 9,460 g/mol.

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Chapter 15 Solutions

Chemistry: The Molecular Nature of Matter and Change - Standalone book

Ch. 15.4 - Prob. 15.4BFPCh. 15.4 - Prob. 15.5AFPCh. 15.4 - Prob. 15.5BFPCh. 15.4 - Prob. 15.6AFPCh. 15.4 - Prob. 15.6BFPCh. 15.4 - Prob. 15.7AFPCh. 15.4 - Prob. 15.7BFPCh. 15.6 - Prob. B15.4PCh. 15.6 - Prob. B15.5PCh. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Silicon lies just below carbon in Group 4A(14) and...Ch. 15 - What is the range of oxidation states for carbon?...Ch. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Define each type of isomer: (a) constitutional;...Ch. 15 - Prob. 15.9PCh. 15 - Prob. 15.10PCh. 15 - Prob. 15.11PCh. 15 - How does an aromatic hydrocarbon differ from a...Ch. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.24PCh. 15 - Draw structures from the following names, and...Ch. 15 - Prob. 15.26PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32PCh. 15 - Prob. 15.33PCh. 15 - Prob. 15.34PCh. 15 - Prob. 15.35PCh. 15 - Prob. 15.36PCh. 15 - Prob. 15.37PCh. 15 - Prob. 15.38PCh. 15 - Prob. 15.39PCh. 15 - Prob. 15.40PCh. 15 - Determine the type of each of the following...Ch. 15 - Prob. 15.42PCh. 15 - Prob. 15.43PCh. 15 - Prob. 15.44PCh. 15 - Prob. 15.45PCh. 15 - Prob. 15.46PCh. 15 - Prob. 15.47PCh. 15 - Prob. 15.48PCh. 15 - Prob. 15.49PCh. 15 - Prob. 15.50PCh. 15 - Prob. 15.51PCh. 15 - Prob. 15.52PCh. 15 - Prob. 15.53PCh. 15 - Prob. 15.54PCh. 15 - Prob. 15.55PCh. 15 - Prob. 15.56PCh. 15 - Prob. 15.57PCh. 15 - Prob. 15.58PCh. 15 - Prob. 15.59PCh. 15 - Prob. 15.60PCh. 15 - Prob. 15.61PCh. 15 - Prob. 15.62PCh. 15 - Prob. 15.63PCh. 15 - Prob. 15.64PCh. 15 - Prob. 15.65PCh. 15 - Prob. 15.66PCh. 15 - Prob. 15.67PCh. 15 - Prob. 15.68PCh. 15 - Prob. 15.69PCh. 15 - Prob. 15.70PCh. 15 - Prob. 15.71PCh. 15 - Prob. 15.72PCh. 15 - Prob. 15.73PCh. 15 - Prob. 15.74PCh. 15 - Prob. 15.75PCh. 15 - Prob. 15.76PCh. 15 - Prob. 15.77PCh. 15 - Prob. 15.78PCh. 15 - Prob. 15.79PCh. 15 - Prob. 15.80PCh. 15 - Prob. 15.81PCh. 15 - Prob. 15.82PCh. 15 - Prob. 15.83PCh. 15 - Prob. 15.84PCh. 15 - Prob. 15.85PCh. 15 - Prob. 15.86PCh. 15 - Prob. 15.87PCh. 15 - What is the key structural difference between...Ch. 15 - Protein shape, function, and amino acid sequence...Ch. 15 - What linkage joins the monomers in each strand of...Ch. 15 - What is base pairing? How does it pertain to DNA...Ch. 15 - RNA base sequence, protein amino acid sequence,...Ch. 15 - Prob. 15.93PCh. 15 - Prob. 15.94PCh. 15 - Draw the structure of each of the following...Ch. 15 - Prob. 15.96PCh. 15 - Write the sequence of the complementary DNA strand...Ch. 15 - Prob. 15.98PCh. 15 - Prob. 15.99PCh. 15 - Prob. 15.100PCh. 15 - Prob. 15.101PCh. 15 - Amino acids have an average molar mass of 100...Ch. 15 - Prob. 15.103PCh. 15 - Prob. 15.104PCh. 15 - Some of the most useful compounds for organic...Ch. 15 - Prob. 15.106PCh. 15 - Prob. 15.107PCh. 15 - Prob. 15.108PCh. 15 - Prob. 15.109PCh. 15 - Prob. 15.110PCh. 15 - Prob. 15.111PCh. 15 - Prob. 15.112PCh. 15 - The polypeptide chain in proteins does not exhibit...Ch. 15 - Prob. 15.114PCh. 15 - Prob. 15.115PCh. 15 - Prob. 15.116PCh. 15 - Prob. 15.117PCh. 15 - Wastewater from a cheese factory has the following...Ch. 15 - Prob. 15.119P
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