Chemistry: The Molecular Nature of Matter and Change - Standalone book
Chemistry: The Molecular Nature of Matter and Change - Standalone book
7th Edition
ISBN: 9780073511177
Author: Martin Silberberg Dr., Patricia Amateis Professor
Publisher: McGraw-Hill Education
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Chapter 15, Problem 15.101P

(a)

Interpretation Introduction

Interpretation:

The amino acid that possesses the given R group has to be named and the force that arises in the interaction of those groups has to be given.

  -CH2-SH with SH-CH2-

Concept Introduction:

Intermolecular forces:

The weaker forces that are formed between the molecules to bind together in groups are known as intermolecular forces or secondary bonds.  The intermolecular is generally defined by the term Vanderwaal forces.

Intermolecular forces in proteins:

  • The back bone of the protein chain forms by covalent peptide bonds.
  • The hydrogen bonds between C=O of one peptide bond and N-H of another peptide bond forms helical or sheet-like segments.
  • Polar and ionic side chains protrude into the surrounding cell fluid interacting with water through ion-dipole forces and hydrogen bonding.
  • Non-polar side chains interact through dispersion forces.
  • The -SH ends of two cysteine side chains forms a covalent -S-S- bond, a disulfide bridge.
  • Salt linkage is formed by oppositely charged ends of side chains -COO- and -NH3+.
  • The hydrogen bonds between side chains keeps the distant chain portions nearer.

(a)

Expert Solution
Check Mark

Explanation of Solution

The given R groups are

  -CH2-SH with SH-CH2-

The R groups belongs to the amino acid Cysteine.  The amino acid cysteine structure is

Chemistry: The Molecular Nature of Matter and Change - Standalone book, Chapter 15, Problem 15.101P , additional homework tip  1

The forces that are involved in the interaction of R groups of cysteine are disulfide bond (covalent bond).

(b)

Interpretation Introduction

Interpretation:

The amino acid that possesses the given R group has to be named and the force that arises in the interaction of those groups has to be given.

  -(CH2)4-NH3+ with O--C||O-CH2-

Concept Introduction:

Intermolecular forces:

The weaker forces that are formed between the molecules to bind together in groups are known as intermolecular forces or secondary bonds.  The intermolecular is generally defined by the term Vanderwaal forces.

Intermolecular forces in proteins:

  • The back bone of the protein chain forms by covalent peptide bonds.
  • The hydrogen bonds between C=O of one peptide bond and N-H of another peptide bond forms helical or sheet-like segments.
  • Polar and ionic side chains protrude into the surrounding cell fluid interacting with water through ion-dipole forces and hydrogen bonding.
  • Non-polar side chains interact through dispersion forces.
  • The -SH ends of two cysteine side chains forms a covalent -S-S- bond, a disulfide bridge.
  • Salt linkage is formed by oppositely charged ends of side chains -COO- and -NH3+.
  • The hydrogen bonds between side chains keeps the distant chain portions nearer.

(b)

Expert Solution
Check Mark

Explanation of Solution

The given R groups are

  -(CH2)4-NH3+ with O--C||O-CH2-

The R group -(CH2)4-NH3+  belongs to the amino acid Lysine and the R group O--C||O-CH2- belongs to the amino acid Aspartic acid.  The amino acids Lysine and Aspartic acid structures are

Chemistry: The Molecular Nature of Matter and Change - Standalone book, Chapter 15, Problem 15.101P , additional homework tip  2

The positively charged R group (-(CH2)4-NH3+ ) of Lysine is attracted by the negatively charged R group (O--C||O-CH2-) of Aspartic acid.  It forms the salt linkage.

(c)

Interpretation Introduction

Interpretation:

The amino acid that possesses the given R group has to be named and the force that arises in the interaction of that groups has to be given.

   -CH2-C||O-NH2- with HO-CH2-

Concept Introduction:

Intermolecular forces:

The weaker forces that are formed between the molecules to bind together in groups are known as intermolecular forces or secondary bonds.  The intermolecular is generally defined by the term Vanderwaal forces.

Intermolecular forces in proteins:

  • The back bone of the protein chain forms by covalent peptide bonds.
  • The hydrogen bonds between C=O of one peptide bond and N-H of another peptide bond forms helical or sheet-like segments.
  • Polar and ionic side chains protrude into the surrounding cell fluid interacting with water through ion-dipole forces and hydrogen bonding.
  • Non-polar side chains interact through dispersion forces.
  • The -SH ends of two cysteine side chains forms a covalent -S-S- bond, a disulfide bridge.
  • Salt linkage is formed by oppositely charged ends of side chains -COO- and -NH3+.
  • The hydrogen bonds between side chains keeps the distant chain portions nearer.

(c)

Expert Solution
Check Mark

Explanation of Solution

The given R groups are

   -CH2-C||O-NH2 with HO-CH2-

The R group  -CH2-C||O-NH2 belongs to the amino acid Asparagine and the R group  HO-CH2- belongs to the amino acid Serine.  The amino acids Asparagine and Serine structures are

Chemistry: The Molecular Nature of Matter and Change - Standalone book, Chapter 15, Problem 15.101P , additional homework tip  3

The R groups -NH2 and -OH forms the hydrogen bonding.

(d)

Interpretation Introduction

Interpretation:

The amino acid that possesses the given R group has to be named and the force that arises in the interaction of that groups has to be given.

Chemistry: The Molecular Nature of Matter and Change - Standalone book, Chapter 15, Problem 15.101P , additional homework tip  4

Concept Introduction:

Intermolecular forces:

The weaker forces that are formed between the molecules to bind together in groups are known as intermolecular forces or secondary bonds.  The intermolecular is generally defined by the term Vanderwaal forces.

Intermolecular forces in proteins:

  • The back bone of the protein chain forms by covalent peptide bonds.
  • The hydrogen bonds between C=O of one peptide bond and N-H of another peptide bond forms helical or sheet-like segments.
  • Polar and ionic side chains protrude into the surrounding cell fluid interacting with water through ion-dipole forces and hydrogen bonding.
  • Non-polar side chains interact through dispersion forces.
  • The -SH ends of two cysteine side chains forms a covalent -S-S- bond, a disulfide bridge.
  • Salt linkage is formed by oppositely charged ends of side chains -COO- and -NH3+.
  • The hydrogen bonds between side chains keeps the distant chain portions nearer.

(d)

Expert Solution
Check Mark

Explanation of Solution

The given R groups are

Chemistry: The Molecular Nature of Matter and Change - Standalone book, Chapter 15, Problem 15.101P , additional homework tip  5

The R group -C|CH3-CH3 belongs to the amino acid Valine and the R group C6H5-CH2- belongs to the amino acid Phenylalanine.  The amino acids Valine and Phenylalanine structures are

Chemistry: The Molecular Nature of Matter and Change - Standalone book, Chapter 15, Problem 15.101P , additional homework tip  6

The R groups -C|CH3-CH3 and C6H5-CH2- are non-polar and the interaction occurs by dispersion forces.

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Chapter 15 Solutions

Chemistry: The Molecular Nature of Matter and Change - Standalone book

Ch. 15.4 - Prob. 15.4BFPCh. 15.4 - Prob. 15.5AFPCh. 15.4 - Prob. 15.5BFPCh. 15.4 - Prob. 15.6AFPCh. 15.4 - Prob. 15.6BFPCh. 15.4 - Prob. 15.7AFPCh. 15.4 - Prob. 15.7BFPCh. 15.6 - Prob. B15.4PCh. 15.6 - Prob. B15.5PCh. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Silicon lies just below carbon in Group 4A(14) and...Ch. 15 - What is the range of oxidation states for carbon?...Ch. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Define each type of isomer: (a) constitutional;...Ch. 15 - Prob. 15.9PCh. 15 - Prob. 15.10PCh. 15 - Prob. 15.11PCh. 15 - How does an aromatic hydrocarbon differ from a...Ch. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.24PCh. 15 - Draw structures from the following names, and...Ch. 15 - Prob. 15.26PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32PCh. 15 - Prob. 15.33PCh. 15 - Prob. 15.34PCh. 15 - Prob. 15.35PCh. 15 - Prob. 15.36PCh. 15 - Prob. 15.37PCh. 15 - Prob. 15.38PCh. 15 - Prob. 15.39PCh. 15 - Prob. 15.40PCh. 15 - Determine the type of each of the following...Ch. 15 - Prob. 15.42PCh. 15 - Prob. 15.43PCh. 15 - Prob. 15.44PCh. 15 - Prob. 15.45PCh. 15 - Prob. 15.46PCh. 15 - Prob. 15.47PCh. 15 - Prob. 15.48PCh. 15 - Prob. 15.49PCh. 15 - Prob. 15.50PCh. 15 - Prob. 15.51PCh. 15 - Prob. 15.52PCh. 15 - Prob. 15.53PCh. 15 - Prob. 15.54PCh. 15 - Prob. 15.55PCh. 15 - Prob. 15.56PCh. 15 - Prob. 15.57PCh. 15 - Prob. 15.58PCh. 15 - Prob. 15.59PCh. 15 - Prob. 15.60PCh. 15 - Prob. 15.61PCh. 15 - Prob. 15.62PCh. 15 - Prob. 15.63PCh. 15 - Prob. 15.64PCh. 15 - Prob. 15.65PCh. 15 - Prob. 15.66PCh. 15 - Prob. 15.67PCh. 15 - Prob. 15.68PCh. 15 - Prob. 15.69PCh. 15 - Prob. 15.70PCh. 15 - Prob. 15.71PCh. 15 - Prob. 15.72PCh. 15 - Prob. 15.73PCh. 15 - Prob. 15.74PCh. 15 - Prob. 15.75PCh. 15 - Prob. 15.76PCh. 15 - Prob. 15.77PCh. 15 - Prob. 15.78PCh. 15 - Prob. 15.79PCh. 15 - Prob. 15.80PCh. 15 - Prob. 15.81PCh. 15 - Prob. 15.82PCh. 15 - Prob. 15.83PCh. 15 - Prob. 15.84PCh. 15 - Prob. 15.85PCh. 15 - Prob. 15.86PCh. 15 - Prob. 15.87PCh. 15 - What is the key structural difference between...Ch. 15 - Protein shape, function, and amino acid sequence...Ch. 15 - What linkage joins the monomers in each strand of...Ch. 15 - What is base pairing? How does it pertain to DNA...Ch. 15 - RNA base sequence, protein amino acid sequence,...Ch. 15 - Prob. 15.93PCh. 15 - Prob. 15.94PCh. 15 - Draw the structure of each of the following...Ch. 15 - Prob. 15.96PCh. 15 - Write the sequence of the complementary DNA strand...Ch. 15 - Prob. 15.98PCh. 15 - Prob. 15.99PCh. 15 - Prob. 15.100PCh. 15 - Prob. 15.101PCh. 15 - Amino acids have an average molar mass of 100...Ch. 15 - Prob. 15.103PCh. 15 - Prob. 15.104PCh. 15 - Some of the most useful compounds for organic...Ch. 15 - Prob. 15.106PCh. 15 - Prob. 15.107PCh. 15 - Prob. 15.108PCh. 15 - Prob. 15.109PCh. 15 - Prob. 15.110PCh. 15 - Prob. 15.111PCh. 15 - Prob. 15.112PCh. 15 - The polypeptide chain in proteins does not exhibit...Ch. 15 - Prob. 15.114PCh. 15 - Prob. 15.115PCh. 15 - Prob. 15.116PCh. 15 - Prob. 15.117PCh. 15 - Wastewater from a cheese factory has the following...Ch. 15 - Prob. 15.119P
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