Chapter 14.3, Problem 28R

To determine

The new volume of the balloon.

Answer to Problem 28R

The new volume of the balloon is $5.08\text{L}$ .

Explanation of Solution

Given info:

Initial temperature of balloon, $T_1=25°\text{C}=\left(25°\text{C}+273\right)\text{K}=298\text{K}$

Final temperature of balloon, $T_2=30°\text{C}=\left(30°\text{C}+273\right)\text{K}=303\text{K}$

Initial size of the balloon, $V_1=5\text{L}$

Formula Used:

Write the expression to calculate the new volume of the balloon using Charles’s law.

  $V_2=\frac{T_2{V}_1}{T_1}$

Where,

• The new volume of the balloon is $V_2$ .

Calculation:

Substitute all the values in the above expression.

  $\begin{array}{c}{V}_2=\frac{\left(303\text{K}\right)\left(5\text{L}\right)}{298\text{K}}\\ =5.08\text{L}\end{array}$

Conclusion:

Thus, the new volume of the balloon is $5.08\text{L}$ .