Chapter 14.3, Problem 18AYU

To determine

To find: $f\left(2\right)$ and $f\left(6\right)$.

Answer to Problem 18AYU

Does not exist or a hole; $f\left(6\right)=\text{ 2}$.

Explanation of Solution

Given:

Calculation:

Since $f\left(x\right)$ is not defined at $x=2$; the value of $f\left(x\right)$ does not exist at $x=2$. In fact there is a hole at $x=2$.

Since $f\left(x\right)$ takes the value 2 at $x=6$; therefore $f\left(6\right)=2$.