Chapter 14.3, Problem 17AYU

To determine

To find: $f\left(-8\right)$ and $f\left(-4\right)$.

Answer to Problem 17AYU

$f\left(-8\right)=0;f\left(-4\right)=2$

Explanation of Solution

Given:

Calculation:

Since $f\left(x\right)$ intersects $x\text{-axis}$ at $x=-8$; the value of $f\left(x\right)$ at $x=-8$ is zero.

Since $f\left(x\right)$ takes the value 2 at $x=-4$; therefore $f\left(x\right)=2$ at $x=-4$.