(II) The human leg can be compared to a physical pendulum, with a “natural” swinging period al which walking is easiest. Consider the leg as two rods joined rigidly together at the knee; the axis for the leg is the hip joint. The length of each rod is about the same, 55 cm. The upper rod has a mass of 7.0 kg and the lower rod has a mass of 4.0 kg. ( a ) Calculate the natural swinging period of the system. ( b ) Check your answer by standing on a chair and measuring the time for one or more complete back-and-forth swings. The effect of a shorter leg is a shorter swinging period, enabling a faster “natural” stride.
(II) The human leg can be compared to a physical pendulum, with a “natural” swinging period al which walking is easiest. Consider the leg as two rods joined rigidly together at the knee; the axis for the leg is the hip joint. The length of each rod is about the same, 55 cm. The upper rod has a mass of 7.0 kg and the lower rod has a mass of 4.0 kg. ( a ) Calculate the natural swinging period of the system. ( b ) Check your answer by standing on a chair and measuring the time for one or more complete back-and-forth swings. The effect of a shorter leg is a shorter swinging period, enabling a faster “natural” stride.
(II) The human leg can be compared to a physical pendulum, with a “natural” swinging period al which walking is easiest. Consider the leg as two rods joined rigidly together at the knee; the axis for the leg is the hip joint. The length of each rod is about the same, 55 cm. The upper rod has a mass of 7.0 kg and the lower rod has a mass of 4.0 kg. (a) Calculate the natural swinging period of the system. (b) Check your answer by standing on a chair and measuring the time for one or more complete back-and-forth swings. The effect of a shorter leg is a shorter swinging period, enabling a faster “natural” stride.
If the maximum speed of the mass attached to a spring, oscillating on a frictionless table, was increased, what characteristics of the rotating disk would need to be changed?
*12–176. The car travels around the circular track with a
constant speed of 20 m/s. Determine the car's radial and
transverse components of velocity and acceleration at the
instant 0 = 7/4 rad.
12–177. The car travels around the circular track such that
its transverse component is 0 = (0.006/2) rad, where t is in
seconds. Determine the car's radial and transverse
components of velocity and acceleration at the instant t=4 s.
r = (400 cos 0) m
The center of gravity of a simple pendulum of mass m and length L is located at the pendulum bob, a distance L from the pivot point. The center of gravity of a uniform rod of the same mass m and length 2L pivoted at one end is also a distance L from the pivot point. Compared to the period of the simple pendulum, is the period of this uniform rod (i) longer; (ii) shorter; or (iii) the same?
Chapter 14 Solutions
Physics for Scientists and Engineers with Modern Physics
Sears And Zemansky's University Physics With Modern Physics
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