Concepts of Genetics (12th Edition)
Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 14, Problem 32ESP

Three independently assorting genes (A, B, and C) are known to control the following biochemical pathway that provides the basis for flower color in a hypothetical plant:

Chapter 14, Problem 32ESP, Three independently assorting genes (A, B, and C) are known to control the following biochemical

Three homozygous recessive mutations are also known, each of which interrupts a different one of these steps. Determine the phenotypic results in the F1 and F2 generations resulting from the P1 crosses of true-breeding plants listed here:

  1. (a) speckled (AABBCC) × yellow (AAbbCC)
  2. (b) yellow (AAbbCC) × green (AABBcc)
  3. (c) colorless (aaBBCC) × green (AABBcc)
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Multiple crosses were made between true-breeding lines of black and yellow Labrador retrievers. All the F1 progeny were yellow. When these progeny were intercrossed, they produced an F2 consisting of 121 yellow, 9 black and 30 chocolate.   What epistatic ratio and what kind of epistasis is approximated in the F2?     Propose a biochemical pathway for coat color in Labrador retrievers based on the type of epistasis.     Correlate each genotype with the phenotype that would occur in your pathway. Also show the frequency of each genotype. A-B- A-bb aaB- aabb
Two morphotypes of the newly discovered plant in Mt. Banahaw de Lucban were tested for linkage of three genes such as the presence of tendril (t+), dense trichomes (d+), and the presence of secretory cells (sc+). The loci for the mutant genes have been mapped and are separated by the following map distances: t and d = 20CM; d and sc = 12CM. The interference between these genes is 0.4. The first morphotype is located at the lower elevation and is characterized by the absence of tendril, sparse trichome, and absence of secretory cells. On the other hand, the second morphotype is located at the higher elevation and is characterized by the presence of tendril, dense trichome, and presence of secretory cells. Further genetic analysis showed that the morphotypes were true breeding. The two morphotypes were intercrossed and the resulting F1 is testcrossed with the first morphotype. The cross resulted in 1800 progeny. Give the genotypes, phenotypes, and the expected numbers of phenotypes in…
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Chapter 14 Solutions

Concepts of Genetics (12th Edition)

Ch. 14 - During translation, what molecule bears the codon?...Ch. 14 - The chain of eukaryotic hemoglobin is composed of...Ch. 14 - Assuming that each nucleotide in an mRNA is 0.34...Ch. 14 - Summarize the steps involved in charging tRNAs...Ch. 14 - To carry out its role, each transfer RNA requires...Ch. 14 - What are isoaccepting tRNAs? Assuming that there...Ch. 14 - When a codon in an mRNA with the sequence 5-UAA-3...Ch. 14 - Discuss the potential difficulties of designing a...Ch. 14 - Prob. 13PDQCh. 14 - Prob. 14PDQCh. 14 - The synthesis of flower pigments is known to be...Ch. 14 - The study of biochemical mutants in organisms such...Ch. 14 - Explain why the one-gene: one-enzyme concept is...Ch. 14 - Why is an alteration of electrophoretic mobility...Ch. 14 - Prob. 19PDQCh. 14 - Prob. 20PDQCh. 14 - Prob. 21PDQCh. 14 - Prob. 22PDQCh. 14 - Several amino acid substitutions in the and ...Ch. 14 - Define and compare the four levels of protein...Ch. 14 - What are the two common types of protein secondary...Ch. 14 - How do covalent disulfide bonds, hydrogen bonds...Ch. 14 - Prob. 27PDQCh. 14 - List three different types of posttranslational...Ch. 14 - Prob. 29PDQCh. 14 - How does an enzyme function? Why are enzymes...Ch. 14 - Prob. 31PDQCh. 14 - Three independently assorting genes (A, B, and C)...Ch. 14 - How would the results vary in cross (a) of Problem...Ch. 14 - Deep in a previously unexplored South American...Ch. 14 - Many antibiotics are effective as drugs to fight...Ch. 14 - The flow of genetic information from DNA to...Ch. 14 - Prob. 37ESP
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