Chapter 14, Problem 28Ci

(a)

Interpretation Introduction

Interpretation : The neutralization reaction for HCl and $\text{Mg}{\left(\text{OH}\right)}_{\text{2}}$ needs to be determined.

Concept Introduction : When an acid and base react in a reaction, they neutralize each other and results in the formation of salt and water.

(b)

Interpretation Introduction

Interpretation : The neutralization reaction for HCl and $\text{Al}{\left(\text{OH}\right)}_3$ needs to be determined.

Concept Introduction : When an acid and base react in a reaction, they neutralize each other and results in the formation of salt and water.

(c)

Interpretation Introduction

Interpretation : The pH of the HCl solution needs to be determined.

Concept Introduction : The acid base reaction is also called as neutralization reaction. It is a reaction of acid and base that results the formation of salt and water. The acidic and basic nature of substances can be checked with the help of pH of solution. The pH can be calculated as follows:

  $\text{pH}=-\log \left[{\text{H}}^{+}\right]$

Here, $\left[{\text{H}}^{+}\right]$ is hydrogen ion concentration.

(d)

Interpretation Introduction

Interpretation : The volume of HCl solution required for $\text{Mg}{\left(\text{OH}\right)}_2$ needs to be calculated.

Concept Introduction : The molarity of the solution is defined as number of moles of solute in 1 L of the solution. It is mathematically represented as follows:

  $M=\frac{n}{V\left(L\right)}$

Here, n is number of moles, V is volume of solution in L.

(e)

Interpretation Introduction

Interpretation : The volume of HCl solution required for $\text{Al}{\left(\text{OH}\right)}_{\text{3}}$ needs to be calculated.

Concept Introduction : The molarity of the solution is defined as number of moles of solute in 1 L of the solution. It is mathematically represented as follows:

  $M=\frac{n}{V\left(L\right)}$

Here, n is number of moles, V is volume of solution in L.