Organic Chemistry
Organic Chemistry
7th Edition
ISBN: 9780321803221
Author: Paula Y. Bruice
Publisher: Prentice Hall
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Chapter 1.4, Problem 15P

(a)

Interpretation Introduction

Interpretation: The appropriate formal charge of each atoms in given species should be given.

Concept introduction:

  • Formal charge = the number of valence electron – the number of electrons the atom has to itself (the entire lone pair electron and one – half of the bonding electrons).
  • Lewis structure indicates which atom is bonded together and show lone pairs and formal charge.
  • Formal charge: It is the electrostatic charge that would reside on an atom in a molecule or polyatomic ion if all bonding electron are shared equally between pairs of atoms.
  • Formal charge calculation: The formal charge for atom in a molecule or ion is calculated based on the Lewis structure of the molecule or ion by following the given equation below:
  • Formal charge calculation of molecule or ion =NVE-{LPE+12(BE)

(b)

Interpretation Introduction

Interpretation: The appropriate formal charge of each atoms in given species should be given.

Concept introduction:

  • Lone-pair electrons are valence electrons that are not used in bonding.
  • A proton is positively charged hydrogen ion. A hybrid ion is a negatively charged hydrogen ion.
  • Formal charge = the number of valence electron – the number of electrons the atom has to itself (the entire lone pair electron and one – half of the bonding electrons).
  • Lewis structure indicates which atom is bonded together and show lone pairs and formal charge.
  • When the atom is neutral, C form 2 bonds, N forms 3 bonds O forms 2 bonds and H or a halogen forms 1 bond.
  • A carbocation has a positively charge carbon, a carbon has a negatively charge carbon and a radical has an unpaired electron.

(c)

Interpretation Introduction

Interpretation: The appropriate formal charge of each atoms in given species should be given.

Concept introduction:

  • Lone-pair electrons are valence electrons that are not used in bonding.
  • A proton is positively charged hydrogen ion. A hybrid ion is a negatively charged hydrogen ion.
  • Formal charge = the number of valence electron – the number of electrons the atom has to itself (the entire lone pair electron and one – half of the bonding electrons).
  • Lewis structure indicates which atom is bonded together and show lone pairs and formal charge.
  • When the atom is neutral, C form 2 bonds, N forms 3 bonds O forms 2 bonds and H or a halogen forms 1 bond.
    • A carbocation has a positively charge carbon, a carbon has a negatively charge carbon and a radical has an unpaired electron

(d)

Interpretation Introduction

Interpretation: The appropriate formal charge of each atoms in given species should be given.

Concept introduction:

  • Lone-pair electrons are valence electrons that are not used in bonding.
  • A proton is positively charged hydrogen ion. A hybrid ion is a negatively charged hydrogen ion.
  • Formal charge = the number of valence electron – the number of electrons the atom has to itself (the entire lone pair electron and one – half of the bonding electrons).
  • Lewis structure indicates which atom is bonded together and show lone pairs and formal charge.
  • When the atom is neutral, C form 2 bonds, N forms 3 bonds O forms 2 bonds and H or a halogen forms 1 bond.
  • A carbocation has a positively charge carbon, a carbon has a negatively charge carbon and a radical has an unpaired electron.

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Chapter 1 Solutions

Organic Chemistry

Ch. 1.3 - After examining the potential maps for LiH, HF,...Ch. 1.4 - An atom with a formal charge does not necessarily...Ch. 1.4 - Prob. 15PCh. 1.4 - a. Draw two Lewis structure for C2H6O. b. Draw...Ch. 1.4 - Draw the lone-pair electrons that are not shown in...Ch. 1.4 - Prob. 19PCh. 1.4 - Which of the atoms in the molecular models in...Ch. 1.4 - Prob. 21PCh. 1.5 - Draw the following orbitals: a. 3s orbital b. 4s...Ch. 1.6 - Prob. 23PCh. 1.6 - Indicate the kind of molecular orbital (, , , or )...Ch. 1.7 - What orbitals are used to form the 10 sigma bonds...Ch. 1.7 - Explain why a bond formed by overlap of s orbital...Ch. 1.9 - Put n number in each of the blanks: a. __ s...Ch. 1.11 - Predict the approximate bond angles in a. the...Ch. 1.11 - According to the potential map for the ammonium...Ch. 1.12 - Prob. 32PCh. 1.13 - a. What are the relative lengths and strengths of...Ch. 1.13 - Prob. 35PCh. 1.14 - Prob. 36PCh. 1.15 - Which of the bond in a carbon-oxygen double bond...Ch. 1.15 - Would you expect a CC bond formed by sp2sp2...Ch. 1.15 - Caffeine is a natural insecticide found in the...Ch. 1.15 - Prob. 41PCh. 1.15 - Predict the approximate bond angles for a. the CNC...Ch. 1.16 - If the dipole moment of CH3F is 1.847 D and the...Ch. 1.16 - Account for the difference in the shape and color...Ch. 1.16 - What of the following molecules would you expect...Ch. 1 - Prob. 46PCh. 1 - Prob. 47PCh. 1 - What is the hybridization of all the atoms (other...Ch. 1 - Draw the condensed structure of a compound that...Ch. 1 - Predict the approximate bond angles: a. the CNH...Ch. 1 - Prob. 51PCh. 1 - Draw a Lewis structure for each of the following:...Ch. 1 - 53. What is the hybridization of each of the...Ch. 1 - Rank the bonds from most polar. a. CO, CF, CN b....Ch. 1 - Draw a Lewis structure for each of the following:...Ch. 1 - What is the hybridization of the indicated atom in...Ch. 1 - Prob. 57PCh. 1 - Prob. 58PCh. 1 - Draw the missing lone-pair electrons and assigns...Ch. 1 - a. Which of the indicated bonds in each molecule...Ch. 1 - For each of the following molecules, indicate the...Ch. 1 - Draw a Lewis structure for each of the following:...Ch. 1 - Rank the following compounds from highest dipole...Ch. 1 - In which orbitals are the lone pairs in nicotine?Ch. 1 - Prob. 65PCh. 1 - Prob. 66PCh. 1 - a. Which of the species have bond angles of 109.5?...Ch. 1 - Prob. 68PCh. 1 - Which compound has a larger dipole moment: CH3Cl...Ch. 1 - Prob. 70PCh. 1 - Prob. 71PCh. 1 - Explain why CH3Cl has a greater dipole moment than...Ch. 1 - Prob. 73P
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