Chemistry: The Molecular Nature of Matter and Change - Standalone book
Chemistry: The Molecular Nature of Matter and Change - Standalone book
7th Edition
ISBN: 9780073511177
Author: Martin Silberberg Dr., Patricia Amateis Professor
Publisher: McGraw-Hill Education
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Chapter 14, Problem 14.41P

(a)

Interpretation Introduction

Interpretation:

The condensed electron configurations for In, In+, In2+ and In3+ has to be written.

Concept Introduction:

The condensed electron configurations:

The arrangement or filling of electrons in the orbitals of atom in known as electron configuration. The heaver atoms contains more number of orbitals and electrons so we can’t able to write full electron configuration so this time we can writhe the nearest noble gas then followed remaining electron configuration is known as condensed electron configuration.

(a)

Expert Solution
Check Mark

Explanation of Solution

Atomic number of indium is 49, and nearest noble gas is krypton therefore,

The condensed electron configurations of In, In+, In2+ and In3+ are,

    In=[Kr]4d10,5s2,5p1In+=[Kr]4d10,5s2In2+=[Kr]4d10,5s1In3+=[Kr]4d10

(b)

Interpretation Introduction

Interpretation:

The magnetism of In, In+, In2+ and In3+ has to be given.

Concept Introduction:

Magnetism:

If an element contains unpaired of electrons, it is paramagnetic.

If an element does not contains unpaired of electrons, it is diamagnetic.

(b)

Expert Solution
Check Mark

Explanation of Solution

The condensed electron configurations of In, In+, In2+ and In3+ are,

    In=[Kr]4d10,5s2,5p1In+=[Kr]4d10,5s2In2+=[Kr]4d10,5s1In3+=[Kr]4d10

From the above electron configurations, In and In2+ are contains unpaired of electros so they are paramagnetic.

In+ and In3+ are doesn’t contains unpaired of electros so they are diamagnetic.

(c)

Interpretation Introduction

Interpretation:

The apparent oxidation state of In in InCl2  has to be given.

Concept Introduction:

Oxidation state:

The number of electrons lost or gain from an atom in the formation of molecule is known as oxidation number.

(c)

Expert Solution
Check Mark

Explanation of Solution

In generally Cl has -1 charge so the apparent oxidation state of In in InCl2  is,

    x+2(-1)=0x=2+In=2+

(c)

Interpretation Introduction

Interpretation:

The diamagnetism of InCl2  has to be explained.

Concept Introduction:

Oxidation state:

The number of electrons lost or gain from an atom in the formation of molecule is known as oxidation number.

(c)

Expert Solution
Check Mark

Explanation of Solution

The condensed electron configurations of In, In+, In2+ and In3+ are,

    In=[Kr]4d10,5s2,5p1In+=[Kr]4d10,5s2In2+=[Kr]4d10,5s1In3+=[Kr]4d10

From the above electron configurations, In and In2+ are contains unpaired of electros so they are paramagnetic.

In+ and In3+ are doesn’t contains unpaired of electros so they are diamagnetic.

In generally Cl has -1 charge so the apparent oxidation state of In in InCl2  is,

    x+2(-1)=0x=2+In=2+

From the above discussion, InCl2  contains half In+  and half In3+ ion therefore, InCl2  is diamagnetic.

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Chapter 14 Solutions

Chemistry: The Molecular Nature of Matter and Change - Standalone book

Ch. 14 - Prob. 14.11PCh. 14 - Prob. 14.12PCh. 14 - Prob. 14.13PCh. 14 - Prob. 14.14PCh. 14 - Prob. 14.15PCh. 14 - Prob. 14.16PCh. 14 - Prob. 14.17PCh. 14 - Prob. 14.18PCh. 14 - Prob. 14.19PCh. 14 - Prob. 14.20PCh. 14 - Prob. 14.21PCh. 14 - Prob. 14.22PCh. 14 - Prob. 14.23PCh. 14 - Prob. 14.24PCh. 14 - Prob. 14.25PCh. 14 - Prob. 14.26PCh. 14 - Prob. 14.27PCh. 14 - Prob. 14.28PCh. 14 - Prob. 14.29PCh. 14 - Prob. 14.30PCh. 14 - Prob. 14.31PCh. 14 - Prob. 14.32PCh. 14 - Prob. 14.33PCh. 14 - Prob. 14.34PCh. 14 - Prob. 14.35PCh. 14 - Prob. 14.36PCh. 14 - Prob. 14.37PCh. 14 - Prob. 14.38PCh. 14 - Prob. 14.39PCh. 14 - Prob. 14.40PCh. 14 - Prob. 14.41PCh. 14 - Prob. 14.42PCh. 14 - Prob. 14.43PCh. 14 - Prob. 14.44PCh. 14 - Prob. 14.45PCh. 14 - Prob. 14.46PCh. 14 - Give explanations for the large drops in melting...Ch. 14 - Prob. 14.48PCh. 14 - Prob. 14.49PCh. 14 - Prob. 14.50PCh. 14 - Prob. 14.51PCh. 14 - Prob. 14.52PCh. 14 - Prob. 14.53PCh. 14 - Prob. 14.54PCh. 14 - Prob. 14.55PCh. 14 - Prob. 14.56PCh. 14 - Prob. 14.57PCh. 14 - Prob. 14.58PCh. 14 - Prob. 14.59PCh. 14 - Prob. 14.60PCh. 14 - Prob. 14.61PCh. 14 - Prob. 14.62PCh. 14 - Prob. 14.63PCh. 14 - Prob. 14.64PCh. 14 - Prob. 14.65PCh. 14 - Prob. 14.66PCh. 14 - Prob. 14.67PCh. 14 - Prob. 14.68PCh. 14 - Prob. 14.69PCh. 14 - Prob. 14.70PCh. 14 - Prob. 14.71PCh. 14 - Prob. 14.72PCh. 14 - Prob. 14.73PCh. 14 - Prob. 14.74PCh. 14 - Prob. 14.75PCh. 14 - Prob. 14.76PCh. 14 - Prob. 14.77PCh. 14 - Prob. 14.78PCh. 14 - Prob. 14.79PCh. 14 - Prob. 14.80PCh. 14 - Prob. 14.81PCh. 14 - Prob. 14.82PCh. 14 - Prob. 14.83PCh. 14 - Prob. 14.84PCh. 14 - Prob. 14.85PCh. 14 - Prob. 14.86PCh. 14 - Prob. 14.87PCh. 14 - Prob. 14.88PCh. 14 - Prob. 14.89PCh. 14 - Prob. 14.90PCh. 14 - Prob. 14.91PCh. 14 - Prob. 14.92PCh. 14 - Prob. 14.93PCh. 14 - Prob. 14.94PCh. 14 - Prob. 14.95PCh. 14 - Prob. 14.96PCh. 14 - Prob. 14.97PCh. 14 - Prob. 14.98PCh. 14 - Prob. 14.99PCh. 14 - Prob. 14.100PCh. 14 - Prob. 14.101PCh. 14 - Prob. 14.102PCh. 14 - Prob. 14.103PCh. 14 - Prob. 14.104PCh. 14 - Xenon tetrafluoride reacts with antimony...Ch. 14 - Prob. 14.106PCh. 14 - Prob. 14.107PCh. 14 - Prob. 14.108PCh. 14 - Prob. 14.109PCh. 14 - Prob. 14.110PCh. 14 - Prob. 14.111PCh. 14 - Prob. 14.112PCh. 14 - Prob. 14.113PCh. 14 - Prob. 14.114PCh. 14 - Prob. 14.115PCh. 14 - Prob. 14.116PCh. 14 - Prob. 14.117PCh. 14 - Prob. 14.118PCh. 14 - Prob. 14.119PCh. 14 - Prob. 14.120PCh. 14 - Prob. 14.121PCh. 14 - Prob. 14.122PCh. 14 - Prob. 14.123PCh. 14 - Prob. 14.124PCh. 14 - Prob. 14.125PCh. 14 - Prob. 14.126PCh. 14 - Prob. 14.127PCh. 14 - Prob. 14.128PCh. 14 - Prob. 14.129PCh. 14 - Prob. 14.130PCh. 14 - Prob. 14.131PCh. 14 - Prob. 14.132PCh. 14 - Prob. 14.133PCh. 14 - Prob. 14.134PCh. 14 - Hydrogen peroxide can act as either an oxidizing...
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