Production and Operations Analysis, Seventh Edition
7th Edition
ISBN: 9781478623069
Author: Steven Nahmias, Tava Lennon Olsen
Publisher: Waveland Press, Inc.
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Chapter 13.4, Problem 18P
Summary Introduction
Interpretation:
Level of redundancy
Concept Introduction:
The objective of optimal policy is to determine the value of ‘t’that minimizes the total cost of maintenance and replacement over an infinite horizon. A replacement cycle is the time between successive replacements.
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A local military base maintains a variety of different equipment. One of these is a sensitive radardevice that signals incursion of enemy planes into American airspace. Breakdowns of the device occur completely at random at an average rate of three per year. The equipment is generally repaired the same day that it fails. Determine the following:a. The probability that the time between two successive failures is less than one month.
A product engineer has developed the following equation for the cost of a system component: C = (10P)2, where C is the cost in dollars and P is the probability that the component will operate as expected. The system is composed of 3 identical components, all of which must operate for the system to operate. The engineer can spend $254 for the 3 components. What is the largest component probability that can be achieved? (Do not round your intermediate calculations. Round your final answer to 4 decimal places.) Probability 0.8466
Chapter 13 Solutions
Production and Operations Analysis, Seventh Edition
Ch. 13.1 - Prob. 3PCh. 13.1 - Prob. 4PCh. 13.1 - Prob. 5PCh. 13.1 - Prob. 6PCh. 13.2 - Prob. 7PCh. 13.2 - Prob. 9PCh. 13.3 - Prob. 13PCh. 13.3 - Prob. 14PCh. 13.4 - Prob. 15PCh. 13.4 - Prob. 16P
Ch. 13.4 - Prob. 17PCh. 13.4 - Prob. 18PCh. 13.4 - Prob. 19PCh. 13.4 - Prob. 20PCh. 13.6 - Prob. 21PCh. 13.6 - Prob. 22PCh. 13.6 - Prob. 23PCh. 13.6 - Prob. 24PCh. 13.6 - Prob. 25PCh. 13.7 - Prob. 26PCh. 13.7 - Prob. 27PCh. 13.7 - Prob. 28PCh. 13.7 - Prob. 30PCh. 13.7 - Prob. 31PCh. 13.7 - Prob. 32PCh. 13.7 - Prob. 33PCh. 13.7 - Prob. 34PCh. 13.8 - Prob. 35PCh. 13.8 - Prob. 36PCh. 13.8 - Prob. 37PCh. 13.8 - Prob. 38PCh. 13.8 - Prob. 39PCh. 13.8 - Prob. 40PCh. 13.8 - Prob. 41PCh. 13 - Prob. 42APCh. 13 - Prob. 43APCh. 13 - Prob. 44APCh. 13 - Prob. 45APCh. 13 - Prob. 46APCh. 13 - Prob. 48APCh. 13 - Prob. 49APCh. 13 - Prob. 51APCh. 13 - Prob. 52APCh. 13 - Prob. 53AP
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