Chapter 13.1, Problem 5PP

To determine

To Calculate:The area of steelplate.

Answer to Problem 5PP

  $\text{ 8}{\text{.9×10}}^{\text{-2}}{\text{m}}^{\text{2}}$

Explanation of Solution

Given data:

Pressure $\text{P = 5}{\text{.0×10}}^{\text{4}}\text{Pa}$

Mass, $m\text{= 454 kg}$

Formula used:

A force (per unit area) that acts on any object is defined by pressure. Pressure on any object is calculated by using formula

  $P=\frac{F_g}{A}=\frac{mg}{A}$

  $A=\frac{mg}{P}$

Where, F = force, A = Area, mass = m , g = gravity

Calculation:

Now by putting the given values informula $A=\frac{mg}{P}$ ,

  $\text{=}\frac{\text{(454}\text{kg)(9}\text{.80}{\text{m/s}}^{\text{2}}\text{)}}{\text{5}{\text{.0×10}}^{\text{4}}\text{Pa}}$

  $\text{=8}{\text{.9×10}}^{\text{-2}}{\text{m}}^{\text{2}}$

Conclusion:

The steel plate area is $\text{8}{\text{.9×10}}^{\text{-2}}{\text{m}}^{\text{2}}$ .