Explanation Given: The system of non-linear equations: { x y = 600 ( x + y ) 2 − 150 ( x − y ) 2 = 100 Formula Used: 1. ( a + b ) 2 = a 2 + 2 a b + b 2 2. ( a − b ) 2 = a 2 − 2 a b + b 2 3. Quadratic formula: Consider a quadratic equation a x 2 + b x + c = 0 , its solutions are given by: x = − b ± b 2 − 4 a c 2 a Calculations: Consider the system of equations: x y = 600 ............ (1) ( x + y ) 2 − 150 ( x − y ) 2 = 100 ............ (2) From equation (1), y = 600 x ............ (3) Substitute equation (3) in equation (2) ( x + 600 x ) 2 − 150 ( x − 600 x ) 2 = 100 x 2 + 1200 + 360000 x 2 − 150 ( x 2 − 1200 + 360000 x 2 ) = 100 ( x 2 − 150 x 2 ) + ( 1200 − 150 ( − 1200 ) ) + ( 360000 x 2 − 150 ( 36

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 1.3, Problem 53PS

To determine

To find:a positive solution (x>0,y>0) to the nearest tenths for the system.

{xy=600( x+y)2−150( x−y)2=100

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Chapter 1.3, Problem 52PS

Chapter 1.3, Problem 54PS

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Chapter 1 Solutions

Calculus

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a positive solution ( x > 0 , y > 0 ) to the nearest tenths for the system. { x y = 600 ( x + y ) 2 − 150 ( x − y ) 2 = 100

Solution Summary: The author explains how to find a positive solution for the given system of equations: cxy=600.

Concept explainers

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To find:a positive solution (x>0,y>0) to the nearest tenths for the system.

{xy=600( x+y)2−150( x−y)2=100

Want to see the full answer?

Chapter 1 Solutions

a positive solution ( x &gt; 0 , y &gt; 0 ) to the nearest tenths for the system. { x y = 600 ( x + y ) 2 − 150 ( x − y ) 2 = 100

Solution Summary: The author explains how to find a positive solution for the given system of equations: cxy=600.

Concept explainers

Videos

To find:a positive solution (x>0,y>0) to the nearest tenths for the system. {xy=600( x+y)2−150( x−y)2=100

Want to see the full answer?

Chapter 1 Solutions

a positive solution ( x > 0 , y > 0 ) to the nearest tenths for the system. { x y = 600 ( x + y ) 2 − 150 ( x − y ) 2 = 100

To find:a positive solution (x>0,y>0) to the nearest tenths for the system.

{xy=600( x+y)2−150( x−y)2=100