Explanation Given information: Onthe 12th of the month, the reservoir held 200 milliongallons of water; on the 21st, it held only 164 milliongallons. Calculation: Assumption is made that represents the number of days and W(t) represents amount of water. Initially, Let the reservoir loses the water at a constant rate, T=12 and W(0)=200 After 9 days, T=21, W(21)=164. Hence the two points are (12,200), (21,164). The slope is calculated as follows, y 2 − y 1 x 2 − x 1 = m ∴ m = 164 − 200 21 − 12 = − 36 9 = − 4 The general equation of line passing through point (x 1 ,y 1 ) with the slope m is, y − y 1 = m ( x − x 1 ) ∴</

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Question

Chapter 1.3, Problem 50PS

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To calculate the quantity of water in the reservoir on the 8^t^h of the month.

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Chapter 1.3, Problem 49PS

Chapter 1.3, Problem 51PS

Chapter 1 Solutions

Calculus

Ch. 1.1 - Prob. 1PS Ch. 1.1 - Prob. 2PS Ch. 1.1 - Prob. 3PS Ch. 1.1 - Prob. 4PS Ch. 1.1 - Prob. 5PS Ch. 1.1 - Prob. 6PS Ch. 1.1 - Prob. 7PS Ch. 1.1 - Prob. 8PS Ch. 1.1 - Prob. 9PS Ch. 1.1 - Prob. 10PS

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