Explanation Given: The triangle form by the lines y = 5 , 3 y − 4 x = 11 , 12 x + 5 y = 25 The equation of lines, y = 5 , 3 y − 4 x = 11 , 12 x + 5 y = 25 First find the intersection of all three lines. Intersection of y = 5 and 3 y − 4 x = 11 3 ( 5 ) − 4 x = 11 − 4 x = 11 − 15 − 4 x = − 4 x = 1 Point of intersection: A ( 1 , 5 ) Intersection of y = 5 and 12 x + 5 y = 25 12 x + 5 ( 5 ) = 25 12 x = 0 x = 0 Point of intersection: B ( 0 , 5 ) Intersection of 3 y − 4 x = 11 and 12 x + 5 y = 25 − 4 x + 3 y = 11 ] × 3 12 x + 5 y = 25 − 12 x + 9 y = 33 12 x + 5 y = 25 14 y = 58 y = 58 14 y = 29 7 x = 5 14 Point of intersection: C ( 5 14 , 29 7 <

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 1, Problem 10SP

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To find: The perimeter and area of triangle form by three line.

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Chapter 1, Problem 9SP

Chapter 1, Problem 11SP

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Chapter 1 Solutions

Calculus

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The perimeter and area of triangle form by three line.

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Chapter 1 Solutions