Integrated Science
7th Edition
ISBN: 9780077862602
Author: Tillery, Bill W.
Publisher: Mcgraw-hill,
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 13, Problem 2PEA
To determine
The distance of the spacecraft from the earth
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
(a) How long in seconds does it take a radio signal to travel 180 km from a transmitter to a receiving antenna? (b) We see a full Moon by reflected sunlight. How much earlier did the light that enters our eye leave the Sun? The Earth – Moon and Earth – Sun distances are 3.8x105 km and 1.5 × 108 km, respectively. (c) What is the round-trip travel time in seconds for light between Earth and a spaceship at a 6.8 × 107 km distance from Earth? (d) Suppose astronomers observe a supernova about 7300 light-years (ly) distant. How long ago in years did the explosion actually occur?
An alien spaceship, passing through our solar system, observes us by reflected sunlight from earth’s surface. We know the escape velocity from earth’s surface is vesc = √(2GME/RE). Suppose we can (magically) compress earth radius to a very small size RS so that the escape velocity equals the speed of light c. In that case, nothing, not even light, can escape earth’s gravity and the alien spaceship will observe us as a “dark black hole”! What would be the value of RS? (RS is called the Schwarzschild radius.)
a) 8.8 cm
b) 8.8 mm
c) 8.8 m
A star is 12.2 ly (light-years) from Earth.
HINT
(a)
At what constant speed (in m/s) must a spacecraft travel on its journey to the star so that the Earth–star distance measured by an astronaut onboard the spacecraft is 4.36 ly?
m/s
(b)
What is the journey's travel time in years as measured by a person on Earth?
NO SCIENTIFIC NOTATION ANSWERS THANK YOU
Chapter 13 Solutions
Integrated Science
Ch. 13.1 - Prob. 1SCCh. 13.1 - Prob. 2SCCh. 13.1 - Prob. 3SCCh. 13.1 - Prob. 4SCCh. 13.1 - Prob. 5SCCh. 13.2 - Prob. 6SCCh. 13.2 - Prob. 7SCCh. 13.3 - Prob. 8SCCh. 13.3 - Prob. 9SCCh. 13.3 - Prob. 10SC
Ch. 13 - Describe the protoplanet nebular model of the...Ch. 13 - What are the basic differences between the...Ch. 13 - Prob. 3CQCh. 13 - Prob. 4CQCh. 13 - Prob. 5CQCh. 13 - Prob. 6CQCh. 13 - Prob. 7CQCh. 13 - Prob. 8CQCh. 13 - Prob. 9CQCh. 13 - Prob. 10CQCh. 13 - Prob. 11CQCh. 13 - Prob. 12CQCh. 13 - Prob. 13CQCh. 13 - Prob. 14CQCh. 13 - Prob. 15CQCh. 13 - Prob. 16CQCh. 13 - Prob. 17CQCh. 13 - Prob. 18CQCh. 13 - Prob. 19CQCh. 13 - What are the significant similarities and...Ch. 13 - Prob. 21CQCh. 13 - Prob. 22CQCh. 13 - Prob. 23CQCh. 13 - Prob. 24CQCh. 13 - Prob. 25CQCh. 13 - Prob. 1PEACh. 13 - Prob. 2PEACh. 13 - Prob. 3PEACh. 13 - Prob. 4PEACh. 13 - Prob. 5PEACh. 13 - Prob. 6PEACh. 13 - Prob. 1PEBCh. 13 - Prob. 2PEBCh. 13 - Prob. 3PEBCh. 13 - Prob. 4PEBCh. 13 - Prob. 5PEBCh. 13 - Prob. 6PEB
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- An alien spaceship, passing through our solar system, observes us by reflected sunlight from earth’s surface. We know the escape velocity from earth’s surface is vesc = √(2GME/RE). Suppose we can (magically) compress earth radius to a very small size RS so that the escape velocity equals the speed of light c. In that case, nothing, not even light, can escape earth’s gravity and the alien spaceship will observe us as a “dark black hole”! What would be the value of RS? (RS is called the Schwarzschild radius.)arrow_forwardThe Global Positioning System (GPS) relies on very accurate atomic clocks aboard a network of 24 satellites, each of which orbits the Earth in 12 hours. To provide a resolution better than 1 meter on Earth, the clocks must not gain or lose more than 3 ns in 12 hours. That is, the clocks must be accurate to 3 x 10-⁹ s/(12 hr) = 7 × 10-14 The satellites move at a speed v = 3.9 km/s in circular orbits. Is it necessary for GPS receivers on Earth to account for special relativistic effects?arrow_forwardThe crew of an enemy spacecraft attempts to escape from your spacecraft by moving away from you at 0.283 of the speed of light. But all is not lost! You launch a space torpedo toward the foe at 0.351 of the speed of light with respect to you. (a) at what speed in kilometers per second does the enemy crew observe the torpedo approaching its spacecraft? (b) Is this more or less than the classical limit? Use the Galilean transform to prove this. (c) What if the torpedo is launched at the speed of light? At what speed in kilometers per second does the enemy crew observe the torpedo approaching its spacecraft? (Show all work.) (d) How fast would the second craft have to be going to measure the torpedoes speed as 10% greater than the classical limit. (Assume the torpedo is launched at the original speed, 0.351 of the speed of light.)arrow_forward
- Suppose a satellite has a mass of 1950 kg and is orbiting at 7.9 km/s. Use the approximation that y 1+(1/2)(c) at low velocities. Randomized Variables m = 1950 kg v = 7.9 km/s Part (a) What is the relativistic momentum of the satellite in kilogram meters per second? Part (b) Find the fractional difference between the relativistic and non-relativistic momenta, (p - Pnr)/Pnr (p-Par Por= Gra Dedi Potearrow_forwardA star is 40.0 light-years from Earth (1 light-year is the distance that light travels in 1 year).(a) How far would you measure this distance to be if you traveled it in a spaceship moving at1.00 x 10^8 m/s? (b) How long would the trip last (for you)?arrow_forwardA cosmic ray travels 60 km through the earth’s atmosphere in 400 μs, as measured by experimenters on the ground. How long does the journey take according to the cosmic ray?arrow_forward
- A highway patrol officer uses a device that measures the speed of vehicles by bouncing radar off them and measuring the Doppler shift. The outgoing radar has a frequency of 95 GHz and the returning echo from a truck has a frequency 16.6 kHz higher. How fast in km/h is the truck moving? Note that there are two Doppler shifts in echoes. Be certain not to round off until the end of the problem, because the effect is small. Round your answer to two decimal places.arrow_forwardesc a) 10 points) Gravitational Time Dilation. The escape velocity from the surface (radius r) of a star or planet of mass M is given by the formula v = (2GM/r). Use this expression to write the time-dilation fraction, At/t, in terms of the ratio of vesc to the speed of light, c. Hint: This is just a simple exercise in substitution. 5.98 x 1024 kg b) (10 points) Extra Lifetime on the Surface of Earth. The Earth has mass MEarth and radius REarth 6.38 x 10 m. What is the fractional time-dilation (At/t) for someone on the Earth's surface? How much longer (At) is a typical lifetime on the surface of Earth, compared to someone in deep space, far away from Earth? Assume a typical human life span of t = 80 years. Iarrow_forward(a) How long does it take a radio signal to travel 150 km from a transmitter to a receiving antenna? (b) We see a full Moon by reflected sunlight. How much earlier did the light that enters our eye leave the Sun? The Earth–Moon and Earth–Sun distances are 3.8 *10^5 km and 1.5* 10^8 km, respectively. (c) What is the round-trip travel time for light between Earth and a spaceship orbiting Saturn, 1.3*10^9 km distant? (d) The Crab nebula, which is about 6500 light-years (ly) distant, is thought to be the result of a supernova explosion recorded by Chinese astronomers in A.D. 1054. In approximately what year did the explosion actually occur? (When we look into the night sky, we are effectively looking back in time.)arrow_forward
- The speed of light is exactly e = 299792458 m - s1. (Also written 299, 792, 458 m - s-1 or 2.99792458 × 10°m - s1. This is exact because it is the definition of the metre.) It takes light 8.3 minutes to get from the sun to the earth. Assuming that the earth's orbit is exactly circular (an approximation) and that its speed is constant, and using the data in this question, calculate the speed of the earth in its orbit around the sun in km · hr. Practise writing your conversions clearly using the 'multiply by 1' technique. Speed of the earth =_ km per hour. Write your answer in standard (not scientific) notation, i.e. without using exponents, and without using commas. However, remember to use the correct number of significant figures. (Hint: which is the least precise of the given data?) Do not include units.arrow_forwardThe energy of a moving object is given by the equation of E= 12??212mv2 . What is the constant? What type of variation is this? If the energy is 16 joules and the mass is 1 kg (kilogram), what is the velocity?arrow_forwardA star has an element in its atmosphere that normally emits a line of frequency fs = 7.5 x 10^14 vib/s. If astronomers measure the frequency of this line to be fo = 7.7 x 10^14 vib/s, then how fast are the Earth and this star traveling relative to each other? Remember that the correct equation for the speed v is given by v = [(fo^2 - fs^2) / (fo^2 + fs^2)] c Remember fo^2 means "fo squared."arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning