World of Chemistry
World of Chemistry
7th Edition
ISBN: 9780618562763
Author: Steven S. Zumdahl
Publisher: Houghton Mifflin College Div
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Chapter 13, Problem 14A

(a)

Interpretation Introduction

Interpretation:

The volume of the gas and temperature at various conditions has to be calculated.

Concept Introduction:

Charles’s law: The volume of a given amount of gas is proportional to its temperature (in K) of the gas at constant pressure.

The relationship between volume of a gas and temperature is expressed as-

  VTor,VT = Constant When P is constant.

Charles’s law can also be expressed in mathematical form as-

  V1T1 = V2T2

In the above equation, V1 is initial volume and T1 is initial temperature, while  V2 is final or new volume and  T2 is final or new temperature.

(a)

Expert Solution
Check Mark

Answer to Problem 14A

Temperature = 167.38°C

Explanation of Solution

Given Information:

  V1=2.03 L

  T1= 24°C (273 + 24) K = 297 K

  V2= 3.01 L

Calculation:

  V2=V1×T2T1 =3.01L×297K2.03L=440.38K=167.38°C

(b)

Interpretation Introduction

Interpretation:

The volume of the gas and temperature at various conditions has to be calculated.

Concept Introduction:

Charles’s law: The volume of a given amount of gas is proportional to its temperature (in K) of the gas at constant pressure.

The relationship between volume of a gas and temperature is expressed as-

  VTor,VT = Constant When P is constant.

Charles’s law can also be expressed in mathematical form as-

  V1T1 = V2T2

In the above equation, V1 is initial volume and T1 is initial temperature, while  V2 is final or new volume and  T2 is final or new temperature.

(b)

Expert Solution
Check Mark

Answer to Problem 14A

Volume of the gas = 173.52 mL .

Explanation of Solution

Given Information:

  V1= 127 mLT1= 273 KT2= 373 K

Calculation:

  V2=V1×T2T1 =127mL×373K273K=173.52mL

(c)

Interpretation Introduction

Interpretation:

The volume of the gas and temperature at various conditions has to be calculated.

Concept Introduction:

Charles’s law: The volume of a given amount of gas is proportional to its temperature (in K) of the gas at constant pressure.

The relationship between volume of a gas and temperature is expressed as-

  VTor,VT = Constant When P is constant.

Charles’s law can also be expressed in mathematical form as-

  V1T1 = V2T2

In the above equation, V1 is initial volume and T1 is initial temperature, while  V2 is final or new volume and  T2 is final or new temperature.

(c)

Expert Solution
Check Mark

Answer to Problem 14A

Volume of the gas = 56.66 mL.

Explanation of Solution

Given Information:

  V1= 49.7 mLT1= 34°= (273 + 34) K = 307 KT2= 350 K

Calculation:

  V2=V1×T2T1 =49.7mL×350K307K=56.66mL

Chapter 13 Solutions

World of Chemistry

Ch. 13.2 - Prob. 4RQCh. 13.2 - Prob. 5RQCh. 13.2 - Prob. 6RQCh. 13.2 - Prob. 7RQCh. 13.2 - Prob. 8RQCh. 13.3 - Prob. 1RQCh. 13.3 - Prob. 2RQCh. 13.3 - Prob. 3RQCh. 13.3 - Prob. 4RQCh. 13.3 - Prob. 5RQCh. 13 - Prob. 1ACh. 13 - Prob. 2ACh. 13 - Prob. 3ACh. 13 - Prob. 4ACh. 13 - Prob. 5ACh. 13 - Prob. 6ACh. 13 - Prob. 7ACh. 13 - Prob. 8ACh. 13 - Prob. 9ACh. 13 - Prob. 10ACh. 13 - Prob. 11ACh. 13 - Prob. 12ACh. 13 - Prob. 13ACh. 13 - Prob. 14ACh. 13 - Prob. 15ACh. 13 - Prob. 16ACh. 13 - Prob. 17ACh. 13 - Prob. 18ACh. 13 - Prob. 19ACh. 13 - Prob. 20ACh. 13 - Prob. 21ACh. 13 - Prob. 22ACh. 13 - Prob. 23ACh. 13 - Prob. 24ACh. 13 - Prob. 25ACh. 13 - Prob. 26ACh. 13 - Prob. 27ACh. 13 - Prob. 28ACh. 13 - Prob. 29ACh. 13 - Prob. 30ACh. 13 - Prob. 31ACh. 13 - Prob. 32ACh. 13 - Prob. 33ACh. 13 - Prob. 34ACh. 13 - Prob. 35ACh. 13 - Prob. 36ACh. 13 - Prob. 37ACh. 13 - Prob. 38ACh. 13 - Prob. 39ACh. 13 - Prob. 40ACh. 13 - Prob. 41ACh. 13 - Prob. 42ACh. 13 - Prob. 43ACh. 13 - Prob. 44ACh. 13 - Prob. 45ACh. 13 - Prob. 46ACh. 13 - Prob. 47ACh. 13 - Prob. 48ACh. 13 - Prob. 49ACh. 13 - Prob. 50ACh. 13 - Prob. 51ACh. 13 - Prob. 52ACh. 13 - Prob. 53ACh. 13 - Prob. 54ACh. 13 - Prob. 55ACh. 13 - Prob. 56ACh. 13 - Prob. 57ACh. 13 - Prob. 58ACh. 13 - Prob. 59ACh. 13 - Prob. 60ACh. 13 - Prob. 61ACh. 13 - Prob. 62ACh. 13 - Prob. 63ACh. 13 - Prob. 64ACh. 13 - Prob. 65ACh. 13 - Prob. 66ACh. 13 - Prob. 67ACh. 13 - Prob. 68ACh. 13 - Prob. 69ACh. 13 - Prob. 70ACh. 13 - Prob. 1STPCh. 13 - Prob. 2STPCh. 13 - Prob. 3STPCh. 13 - Prob. 4STPCh. 13 - Prob. 5STPCh. 13 - Prob. 6STPCh. 13 - Prob. 7STPCh. 13 - Prob. 8STPCh. 13 - Prob. 9STPCh. 13 - Prob. 10STP
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