Chapter 13, Problem 13.85P

Interpretation Introduction

Interpretation:

The molar mass of second gas when time is taken by it and nitrogen gas to effuse is $\text{54}\text{.3 min}$ and $\text{30 min}$ respectively has to be calculated.

Concept Introduction:

The relation between time and molar mass that holds true when pressure conditions remain same is as follows:

  $\frac{t_{\text{B}}}{t_{\text{A}}}={\left(\frac{M_{\text{B}}}{M_{\text{A}}}\right)}^{1/2}$

Here

$t_{\text{B}}$ represent effusion time taken by of gas B.

$t_{\text{A}}$ represent effusion time taken of gas A.

${\text{Rate}}_{\text{A}}$ represent rate of effusion of gas A.

${\text{Rate}}_{\text{B}}$ represent rate of effusion of gas B.

$M_{\text{B}}$ represent molar mass of gas B.

$M_{\text{A}}$ represent molar mass of gas A.