BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)
10th Edition
ISBN: 9781305967359
Author: STARR
Publisher: CENGAGE L
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Chapter 13, Problem 11SA
True or false? All traits are inherited in a Mendelian pattern.
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Mendelian Genetics and Non-Mendelian Genetics: Huntington’s disease, a neurodegenerative genetic disorder that typically becomes noticeable in middle age, is due to an autosomal dominant allele. Sickle cell anemia, on the other hand, is a genetic blood disorder due to a recessive allele. Jillian is a carrier of the allele for sickle cell anemia but has no sign of any neurodegenerative disorder in her family. She married Jacobwhose father died of Huntington’s disease. His mother, however, is not inflicted with that condition. Neither of his parents exhibit sickle cell anemia.
1. Give the genotypes of Jillian and Jacob.
Assuming that they will have 4 children, what is the probability that:
2. all their children will be normal?
3. they will have a son with Huntington’s disease?
4. they will have a daughter inflicted with both conditions
Neo-Mendelian Genetics: Complete dominance and overdominance
Huntington’s disease, a neurodegenerative genetic disorder that typically becomes noticeable in middle age, is due to an autosomal dominant allele. Sickle cell anemia, on the other hand, is a genetic blood disorder due to a recessive allele. Mary is a carrier of the allele for sickle cell anemia but has no sign of any neurodegenerative disorder in her family. She married Paul whose father died of Huntington’s disease. His mother, however, is not inflicted with that condition. Neither of his parents exhibits sickle cell anemia.
What are the genotypes of Mary and Paul?
If they plan to have four children, what is the probability that:
all their children will be normal? ____________
they will have a son with Huntington’s disease? ___________
they will have a daughter inflicted with both conditions?____________
Mendelian Genetics [6F.R]:Question 1
In rabbits, grey fur (G) is dominant to white fur (g) and black eyes (B)
are dominant to red eyes (b). A male rabbit with the genotype GgBb is
crossed with a female rabbit with the genotype ggbb. What percent of
the offspring will have white fur and red eyes?
Select one:
25%
50%
100%
0%
1000
Chapter 13 Solutions
BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)
Ch. 13 - A heterozygous individual has _______ for a trait...Ch. 13 - An organisms observable traits constitute its...Ch. 13 - In genetics, F stands for filial, which means...Ch. 13 - The offspring of the cross AAaa are ________. a....Ch. 13 - The second-generation offspring of a cross between...Ch. 13 - Refer to question 4. Assuming complete dominance,...Ch. 13 - Independent assortment means _______. a. alleles...Ch. 13 - A testcross is a way to determine _________. a....Ch. 13 - Assuming complete dominance, crosses between two...Ch. 13 - The probability of a crossover occurring between...
Ch. 13 - True or false? All traits are inherited in a...Ch. 13 - One gene that affects three traits is an example...Ch. 13 - ________ in a trait is indicated by a bell curve.Ch. 13 - The phenotype of individuals heterozygous for...Ch. 13 - Match the terms with the best description. ___...Ch. 13 - Mendel crossed a true-breeding pea plant with...Ch. 13 - Assuming that independent assortment occurs during...Ch. 13 - Determine the predicted genotype frequencies among...Ch. 13 - Prob. 4GPCh. 13 - A single allele gives rise to the HbS form of...Ch. 13 - In sweet pea plant, an allele for purple flowers...
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- Cystic fibrosis is an autosomal disease that mainly affects the white population, and 1 in 20 whites are heterozygotes. Genetic testing can diagnose heterozygotes. Should a genetic screening program for cystic fibrosis be instituted? Should the federal government fund it? Should the program be voluntary or mandatory, and why?arrow_forwardThis pedigree (Pedigree #2) illustrates the inheritance of a simple Mendelian trait. If individuals III- 5 and III-6 have children, what are the chances that the children would have this disorder? 0% 1/4 2/3 O 1/6 ㅇㅁarrow_forwardTrue False One heritable factors such as recessive form could mask the presence of the alternate allele which is in dominant form A Punnett square is used to predict the genotype and the phenotype of an offspring after a genetic cross. Mendel's law of dominance states that "when parents with pure and contrasting traits are crossed together, only one form of trait appears in the next generation." A homozygous individual could have a "Ee" as genotype DNA has a ribose sugar. G..pdf rerarrow_forward
- Mendel's Laws of Inheritance Menders Success Menders approach to the study of heredity was effective for several reasons. Foremost was his choice of experimental subject, the pea plant Pisum sativum. Monohybrid Crosses Mendel began by studying monohybrid crosses— those between parents that differed in a single characteristic. The principle of segregation (Mendel's first law) states that each individual diploid organism possesses two alleles for any particular characteristic. These two alleles segregate (separate) when gametes are formed, and one allele goes into each gamete. Furthermore, the two alleles segregate into gametes in equal proportions.The concept of dominance that, when two different alleles are present in a genotype, only the trait of the dominant allele is observed in the phenotype. Multiple-Loci Crosses Dihybrid Crosses In addition to his work on monohybrid crosses, Mendel also crossed varieties of peas that differed in two characteristics (dihybrid crosses).…arrow_forwardThis question will test your Mendelian genetics knowledge! On a piece of paper, construct TWO Punnett squares (set up both of your Punnett squares like the example square provided below). In this classic Mendelian genetics cross, you will start with a female cat from a PURE BREEDING brown furred population. You mate this female with a male cat selected from a PURE BREEDING yellow furred population. BROWN fur is the dominant allele. In your first Punnett square, show the P generation cross, with the F1 generation results. Be sure to label this as your P generation cross! Use the correct genotype symbols, as used in standard dominant / recessive allele systems, to show all genotypes. In your second Punnett square, do a monohybrid cross of the F1 generation, to show the expected F2 generation results. Be sure to use the correct genotype symbols. Next to BOTH of your Punnett Squares, write out the expected genotype and phenotype ratios for the offspring generations. Use the TERMS used to…arrow_forwardWhat phenotypes in what ratio would be expected in the F2 generation of the cross with the following information: The genotype of homozygous black, long haired rabbit is BBhh The genotype of homozygous brown, short haired rabbit is bbHH The gamete of homozygous black, long haired rabbit is Bh The gamete of homozygous brown, short haired rabbit is bH F1 progeny is BbHh (heterozygous black, short haired rabbit)arrow_forward
- a app.edulastic.com .. Question 1/4 > NEXT Mendel crossed wrinkle-seeded (rr) plants with pure round-seeded plants (RR). What percentage of the resulting generation had wrinkled seeds?arrow_forwardMendelian Genetics F2 Cross: Yellow, Round x Green, Round GgWw x ggWW Character: Pea color & shape Use Punnett square and fork-line method to check the possible offspring. Show and interpret all the possible genotypes and phenotypes of the offspringsarrow_forwardI just want an explanation of what is in bold please. Lab Introduction: A dihybrid cross is a cross between individuals that involves two pairs of contrasting traits. To Predict the results of a dihybrid, cross all possible combinations of the four alleles from each parent must be considered. You will examine a dihybrid cross involving both color and texture. Purple (P), is dominate to yellow (p), and smooth texture (S) is dominant to wrinkled (s). Both parent plants are heterozygous for both traits. Review genetics and the use of Punnett squares in a biology text before doing this experiment.MATERIALS: Assume you have ear of Corn. You need a heterozygous X heterozygous 9:3:3:1, purple/yellow, starchy/sweet. PROCEDURE: From above please write out: The crop The parental (P) cross phenotype, genotype, gametes The F1 progeny Genotype and Phenotype Cross between two F1 Selfed testcross The F1 gametes The expected F2 results, genotype, phenotype, genotypic ratio, phenotypic ratio. 1.…arrow_forward
- List four modified Mendelian ratios that you can think of.arrow_forwardCan you curl your tongue? Tongue-curling in humans (T) is a dominant genetic trait. Derek can curl his tongue but his wife, Ashley, cannot. All nine of their children can curl their tongues. Complete the Punnett square based on the genotypes they most likely have.arrow_forwardWe have crossed true-breeding flies today. Wild type to mutant. Their phenotypes were wt and vg se. (Let’s not worry about males and females for now, just assume both genes are autosomal, which is normal in a Mendelian experiment). The results of a cross are phenotypes. I will be asking you for numbers or a ratio of phenotype numbers you expect to see in the offspring from this cross. To answer this, you’ll need to start with the genotypes of parents, then write their gametes, then write the offspring genotypes, then get the phenotypes based on them. Predict the results of this cross: In case both mutations are recessive; In case both mutations are dominant; In case vestigial wings are recessive and the sepia eyes are dominant.arrow_forward
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