BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)
10th Edition
ISBN: 9781305967359
Author: STARR
Publisher: CENGAGE L
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Chapter 13, Problem 9SA
Assuming complete dominance, crosses between two dihybrid F1 pea plant, which are offspring from a cross
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Assuming complete dominance, the F1 generation from a monohybrid cross between to parents that are both homozygous (PP x Pp) will always
result in offspring (mark all that apply)
a. in a 1:3:1 ratio
b. with identical phenotype
C. in a 1:2:1 ratio
O d. with identical genotype
In a parental cross between a true-breeding, homozygous purple-flowered pea plant and a true breeding homozygous white-flowered plant, the F1 generation will
A. all be white
B. 3: 1 ratio of white to purple
C. 3: 1 ratio of purple to white
D. all be purple
The offspring of the cross AA × aa are______ . a. all AA c. all Aa b. all aa d. half are AA and half are aa
Chapter 13 Solutions
BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)
Ch. 13 - A heterozygous individual has _______ for a trait...Ch. 13 - An organisms observable traits constitute its...Ch. 13 - In genetics, F stands for filial, which means...Ch. 13 - The offspring of the cross AAaa are ________. a....Ch. 13 - The second-generation offspring of a cross between...Ch. 13 - Refer to question 4. Assuming complete dominance,...Ch. 13 - Independent assortment means _______. a. alleles...Ch. 13 - A testcross is a way to determine _________. a....Ch. 13 - Assuming complete dominance, crosses between two...Ch. 13 - The probability of a crossover occurring between...
Ch. 13 - True or false? All traits are inherited in a...Ch. 13 - One gene that affects three traits is an example...Ch. 13 - ________ in a trait is indicated by a bell curve.Ch. 13 - The phenotype of individuals heterozygous for...Ch. 13 - Match the terms with the best description. ___...Ch. 13 - Mendel crossed a true-breeding pea plant with...Ch. 13 - Assuming that independent assortment occurs during...Ch. 13 - Determine the predicted genotype frequencies among...Ch. 13 - Prob. 4GPCh. 13 - A single allele gives rise to the HbS form of...Ch. 13 - In sweet pea plant, an allele for purple flowers...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Choose the correct answer. 1.What are the phenotypes of the offspring that results from a cross between snapdragon plants that produce red (RR) and pink (Rr) flowers? (Incomplete dominance) * a. 75% red, 25% pink b. 50% red, 50% pink c. 50% red, 25% pink, 25% white d. 75% pink, 25% red 2. In Dalmatian dogs, the spotted condition (S) is dominant over non-spotted (s). A litter of 8 pups were found—four spotted and four non-spotted. Based on the appearance of the pups, what are the genotypes of the parents? * a. Ss and Ss b. SS and ss c. Ss and ss d. ss and ss 3.The allele for brown eye (B) is dominant to that of blue eye (b). A brown-eyed man with a blue-eyed mother marries a blue-eyed woman. What is the probability that the first child is blue-eyed? * a. 25% b. 75% c. 50% d. 100% 4.The gene for green seed coat (G) is dominant to the gene for yellow seed coat (g). A plant with a yellow seed coat is crossed with a plant with a green seed coat. Eight of the offspring had yellow…arrow_forwardAssuming no gene linkage, in a dihybrid cross ofAABB x aabb with AaBb F1 heterozygotes, what is the ratio of the F1 gametes (AB, aB,Ab, ab) that will give rise to the F2 offspring? a. 1:1:1:1 b. 1:3:3:1 c. 1:2:2:1 d. 4:3:2:1arrow_forwardYellow Dominant pea Seed with unknown genotype (YY or Yy) is test-crossed with green homozygous recessive pea seed (yy). After the test cross, the genotype of yellow dominant seed is Yy. What was the result of Cross that confirmed the genotype as Yy? a. All green seeds b. 50% yellow and 50% green seeds (½ : ½). c. All yellow seeds d. 75% yellow and 25% green seeds (3:1)arrow_forward
- In garden pea plants, an inflated pod shape (I) is dominant over a pinched pod (i). The cross between two true breeding inflated pods can be represented by Select one: a. IiIi b. iiii c. IIII d. IIii e. Iiiiarrow_forwardT = Tall t = short pollen from a tall pea plant T T eggs from a tall pea plant T TT TT t Tt Tt In the square shown, which of the following is true about the offspring resulting from the cross? Multiple Choice a. Half are expected to be short. b. All are expected to be tall. c. All are expected to be short. d. All are expected to be of medium height.arrow_forwardRefer to question 5. Assuming complete dominance, the F2 generation will show a phenotypic ratio of______ . a. 3:1 b. 9:1 c. 1:2:1 d. 9:3:3:1arrow_forward
- In incomplete dominance, one alle is not fully dominant over another, so the heterozygous phenotype is _______. A. an intermediate blend between the two homozygous phenotypes B. the same as homozygous recessive phenotype C. the same as the homozygous dominant phenotypearrow_forwardA Tt plant is crossed to a tt plant. What is the expected ratio of phenotypesfor offspring from this cross?a. 3 tall : 1 dwarfb. 1 tall : 1 dwarfc. 1 tall : 3 dwarfd. 2 tall : 1 dwarfarrow_forwardA condition in which both alleles of a heterozygous condition are expressed as a blending of traits is ______. a incomplete dominance b sex-linked c transformation d crossing overarrow_forward
- The Camelia flower exhibits codominance with flowers being red, white, or white and red spotted. Determine the probability that a red flower crossed with a white and red flower will have a white offspring. O a. 0% O b. 50% O c. 25% O d. 75% e. 100%arrow_forwardQuestion 7/28 A tall pea plant is crossed with a short pea plant. All of the offspring that are produced are tall. Two of these tall offspring are crossed. The Punnett square for this second cross is shown below. TT 25% Tt 25% Tt 25% tt 25% What can be concluded from this cross? Tall pea plants can only produce tall offspring. B Tall pea plants can only produce short offspring.arrow_forwardA test cross is performed to determine if a specific individual is a carrier. The results generate a 50/50 ratio of phenotypes. The test subject is therefore ________. A. Unable to reproduce B. Homozygous recessive C. Not following the rules of Mendelian genetics D. Homozygous dominant E. Heterozygousarrow_forward
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