INTRODUCTION TO CHEMISTRY(LL)-W/CONNECT
5th Edition
ISBN: 9781260264920
Author: BAUER
Publisher: MCG
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Chapter 13, Problem 110QP
(a)
Interpretation Introduction
Interpretation:
A balanced equation showing the acid and its conjugate base in equilibrium is to be written.
(b)
Interpretation Introduction
Interpretation:
The way in which the given buffer system prevents large
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Propionic acid, HC3H5O2, has Ka= 1.34 x 10–5.
(a) What is the molar concentration of H3O+ in 0.15 M HC3H5O2 and the pH of the solution?
(b) What is the Kb value for the propionate ion, C3H5O2–?
(c) Calculate the pH of 0.15 M solution of sodium propionate, NaC3H5O2.
(d) Calculate the pH of solution that contains 0.12 M HC3H5O2 and 0.25 M NaC3H5O2.
4. How does the pH of each of the following solutions change when 5.0 mL of 1.0 M NaOH (a
strong base) is added? Fill in the table. Give your answers with 2 decimals.
Initial pH
Final pH after adding NaOH
Solution
(a) 100.0 ml water
(b)
(c)
100.0 mL 0.150 M HNO2 (a weak acid)
(Given: Ka = 4.5 × 10-4)
100.0 mL solution of 0.150 M HNO2 and
0.100 M NaNO₂
a) What is the pH of a buffer solution that is made by dissolving 125.5 g of sodium benzoate and 166.9g of benzoic acid in 500 mL of water?
(b) What is the pH if you added 26.7 mL of 2.22 M NaOH to 254 mL of the buffer solution from above?
(c) What is the pH if you added 32.8 mL of 3.36 M HCl to 354 mL of the buffer solution from above?
Dont
Chapter 13 Solutions
INTRODUCTION TO CHEMISTRY(LL)-W/CONNECT
Ch. 13 - How do acids and bases differ from other...Ch. 13 - Prob. 2QCCh. 13 - Prob. 3QCCh. 13 - Prob. 4QCCh. 13 - Prob. 5QCCh. 13 - Prob. 6QCCh. 13 - Prob. 1PPCh. 13 - Prob. 2PPCh. 13 - Prob. 3PPCh. 13 - Prob. 4PP
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- Write the chemical equation and the expression for the equilibrium constant, and calculate Kb for the reaction of each of the following ions as a base. (a) sulfate ion (b) citrate ionarrow_forwardFor conjugate acidbase pairs, how are Ka and Kb related? Consider the reaction of acetic acid in water CH3CO2H(aq)+H2O(l)CH3CO2(aq)+H3O+(aq) where Ka = 1.8 105 a. Which two bases are competing for the proton? b. Which is the stronger base? c. In light of your answer to part b. why do we classify the acetate ion (CH3CO2) as a weak base? Use an appropriate reaction to justify your answer. In general, as base strength increases, conjugate acid strength decreases. Explain why the conjugate acid of the weak base NH3 is a weak acid. To summarize, the conjugate base of a weak acid is a weak base and the conjugate acid of a weak base is a weak acid (weak gives you weak). Assuming Ka for a monoprotic strong acid is 1 106, calculate Kb for the conjugate base of this strong acid. Why do conjugate bases of strong acids have no basic properties in water? List the conjugate bases of the six common strong acids. To tie it all together, some instructors have students think of Li+, K+, Rb+, Cs+, Ca2+, Sr2+, and Ba2+ as the conjugate acids of the strong bases LiOH, KOH. RbOH, CsOH, Ca(OH)2, Sr(OH)2, and Ba(OH)2. Although not technically correct, the conjugate acid strength of these cations is similar to the conjugate base strength of the strong acids. That is, these cations have no acidic properties in water; similarly, the conjugate bases of strong acids have no basic properties (strong gives you worthless). Fill in the blanks with the correct response. The conjugate base of a weak acid is a_____base. The conjugate acid of a weak base is a_____acid. The conjugate base of a strong acid is a_____base. The conjugate acid of a strong base is a_____ acid. (Hint: Weak gives you weak and strong gives you worthless.)arrow_forwardGiven that Ka's for hydrofluoric acid (HF) and boric acid (H3BO3) are 6.3 x 10-4 and 5.4 x 10-10, respectively, calculate the pH of the following solutions: (a) The mixture from adding 50 mL 0.2 M HF to 50 mL 0.5 M sodium borate (NaH2BO3). (b) The mixture from adding an additional 150 mL 0.2 M HF to the solution in (a), i.e., a total of 200 mL 0.2 M HF was added to 50 mL 0.5 M NaH2BO3.arrow_forward
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- For each of the following cases, decide whether the pH is less than 7, equal to 7, or greater than 7. (a) Equal volumes of 0.10 M acetic acid, CH3CO2H, and 0.10 M KOH are mixed. (b) 25 mL of 0.015 M NH3 is mixed with 25 mL of 0.015 M HCl. (c) 150 mL of 0.20 M HNO3 is mixed with 75 mL of 0.40 M NaOH.arrow_forwardYou are asked to prepare a pH = 3.00 buffer starting from 2.00 L of 0.025 M solution of benzoic acid (C6H5COOH). (a) What is the pH of the benzoic acid solution prior to adding sodium benzoate? (hint: write the reaction equation for the acid dissociation and then use the equilibrium constant expression to calculate [H + ]) (b) How many grams of sodium benzoate should be added to prepare the buffer? Neglect the small volume change that occurs when the sodium benzoate is added.(hint: use the equilibrium constant expression to calculate [C6H5COO− ] in the buffer)arrow_forwardAn important component of blood is the buffer combination of bicarbonate ion and carbonic acid. Consider blood with a pH of 7.42. (a) What is the ratio of [H2CO3] to [HCO3− ]?(b) What does the pH become if 14% of the bicarbonate ions are converted to carbonic acid? (c) What does the pH become if 26% of the carbonic acid molecules are converted to bicarbonate ions?arrow_forward
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