McDougal Littell Jurgensen Geometry: Student Edition Geometry
McDougal Littell Jurgensen Geometry: Student Edition Geometry
5th Edition
ISBN: 9780395977279
Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Publisher: Houghton Mifflin Company College Division
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Chapter 12.5, Problem 5CE

(a).

To determine

To find:The ratios of volumes of two similar sphere.

(a).

Expert Solution
Check Mark

Answer to Problem 5CE

The ratios of volumes of two similar sphere is 1:8 .

Explanation of Solution

Given information:

The volumes of two similar spheres are 2πm3 and 16πm3 respectively.

Calculation:

Let, the two volumes be V1 and V2 .

Expression of given two volumes of similar spheres in ratio is:

  V1V2=2πm316πm3

To find the ratio of volumes, divide the numerator and denominator of the above expression by 2 .

  V1V2=2πm3÷216πm3÷2=18

Therefore, the volume ratio of two similar spheres in reduced form is 1:8 .

(b).

To determine

To find:The ratios of diameters of two similar sphere.

(b).

Expert Solution
Check Mark

Answer to Problem 5CE

The ratios of diameters of two similar sphere is 1:2 .

Explanation of Solution

Given information:

The volumes of two similar spheres are 2πm3 and 16πm3 respectively.

Calculation:

The ratio of the corresponding sides of any two similar geometric figures is termed as Scale factor. Let, the diameters of sphere be d1 and d2 .

As calculated in part(a), The value of V1 is 1 and V2 is 8 .

The theorem of similar solids states that if the scale factor of two similar solids is a:b , then the ratio of their volumes is a3:b3 .

Expression to determine the ratio of diameters from volumes of spheresusing the above theorem is:

  V1V2=(d1d2)3

Substitute 1 for V1 and 8 for V2 in the above expression.

  18=(d1d2)3

To determine the ratio of diameters, apply cube root at both sides in the above expression.

  183=(d1d2)33d1d2=12

Therefore, the ratio of diameter of two similar sphere is 1:2 .

(c).

To determine

To find:The ratios of areas of two similar spheres.

(c).

Expert Solution
Check Mark

Answer to Problem 5CE

The ratios of areas of two similar spheres is 1:4 .

Explanation of Solution

Given information:

The volumes of two similar spheres are 2πm3 and 16πm3 respectively.

Calculation:

As calculated in part(b), The value of d1 is 1 and d2 is 2 .

The theorem of similar solids states that if the scale factor of two similar solids is a:b , then the ratio of base areas, the lateral areas and total areas is a2:b2 .

Expression to determine theratio of area of spheresfrom the above theorem is:

  area=(scalefactor)2a1a2=(d1d2)2

Substitute 1 for d1 and 2 for d2 in the above expression.

  a1a2=(12)2=1×12×2=14

Therefore, the ratios of areas of two similar spheres is 1:4 .

Chapter 12 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 12.1 - Prob. 1WECh. 12.1 - Prob. 2WECh. 12.1 - Prob. 3WECh. 12.1 - Prob. 4WECh. 12.1 - Prob. 5WECh. 12.1 - Prob. 6WECh. 12.1 - Prob. 7WECh. 12.1 - Prob. 8WECh. 12.1 - Prob. 9WECh. 12.1 - Prob. 10WECh. 12.1 - Prob. 11WECh. 12.1 - Prob. 12WECh. 12.1 - Prob. 13WECh. 12.1 - Prob. 14WECh. 12.1 - Prob. 15WECh. 12.1 - Prob. 16WECh. 12.1 - Prob. 17WECh. 12.1 - Prob. 18WECh. 12.1 - Prob. 19WECh. 12.1 - Prob. 20WECh. 12.1 - Prob. 21WECh. 12.1 - Prob. 22WECh. 12.1 - Prob. 23WECh. 12.1 - Prob. 24WECh. 12.1 - Prob. 25WECh. 12.1 - Prob. 26WECh. 12.1 - Prob. 27WECh. 12.1 - Prob. 28WECh. 12.1 - Prob. 29WECh. 12.1 - Prob. 30WECh. 12.1 - Prob. 31WECh. 12.1 - Prob. 32WECh. 12.1 - Prob. 33WECh. 12.1 - Prob. 34WECh. 12.1 - Prob. 35WECh. 12.1 - Prob. 36WECh. 12.1 - Prob. 37WECh. 12.1 - Prob. 38WECh. 12.1 - Prob. 39WECh. 12.1 - Prob. 40WECh. 12.1 - Prob. 1CCh. 12.1 - Prob. 2CCh. 12.1 - Prob. 3ECh. 12.2 - Prob. 1CECh. 12.2 - Prob. 2CECh. 12.2 - Prob. 3CECh. 12.2 - Prob. 4CECh. 12.2 - Prob. 5CECh. 12.2 - Prob. 6CECh. 12.2 - Prob. 7CECh. 12.2 - Prob. 8CECh. 12.2 - Prob. 9CECh. 12.2 - Prob. 10CECh. 12.2 - Prob. 11CECh. 12.2 - Prob. 12CECh. 12.2 - Prob. 13CECh. 12.2 - Prob. 14CECh. 12.2 - Prob. 15CECh. 12.2 - Prob. 16CECh. 12.2 - Prob. 17CECh. 12.2 - Prob. 18CECh. 12.2 - Prob. 1WECh. 12.2 - Prob. 2WECh. 12.2 - Prob. 3WECh. 12.2 - Prob. 4WECh. 12.2 - Prob. 5WECh. 12.2 - Prob. 6WECh. 12.2 - Prob. 7WECh. 12.2 - Prob. 8WECh. 12.2 - Prob. 9WECh. 12.2 - Prob. 10WECh. 12.2 - Prob. 11WECh. 12.2 - Prob. 12WECh. 12.2 - Prob. 13WECh. 12.2 - Prob. 14WECh. 12.2 - Prob. 15WECh. 12.2 - Prob. 16WECh. 12.2 - Prob. 17WECh. 12.2 - Prob. 18WECh. 12.2 - Prob. 19WECh. 12.2 - Prob. 20WECh. 12.2 - Prob. 21WECh. 12.2 - Prob. 22WECh. 12.2 - Prob. 23WECh. 12.2 - Prob. 24WECh. 12.2 - Prob. 25WECh. 12.2 - Prob. 26WECh. 12.2 - Prob. 27WECh. 12.2 - Prob. 28WECh. 12.2 - Prob. 29WECh. 12.2 - Prob. 30WECh. 12.2 - Prob. 31WECh. 12.2 - Prob. 32WECh. 12.2 - Prob. 1CCh. 12.2 - Prob. 2CCh. 12.2 - Prob. 3CCh. 12.2 - Prob. 4CCh. 12.2 - Prob. 1MRECh. 12.2 - Prob. 2MRECh. 12.2 - Prob. 3MRECh. 12.2 - Prob. 4MRECh. 12.2 - Prob. 5MRECh. 12.2 - Prob. 6MRECh. 12.2 - Prob. 7MRECh. 12.2 - Prob. 8MRECh. 12.2 - Prob. 9MRECh. 12.2 - Prob. 10MRECh. 12.3 - Prob. 1CECh. 12.3 - Prob. 2CECh. 12.3 - Prob. 3CECh. 12.3 - Prob. 4CECh. 12.3 - Prob. 5CECh. 12.3 - Prob. 6CECh. 12.3 - Prob. 7CECh. 12.3 - Prob. 8CECh. 12.3 - Prob. 1WECh. 12.3 - Prob. 2WECh. 12.3 - Prob. 3WECh. 12.3 - Prob. 4WECh. 12.3 - Prob. 5WECh. 12.3 - Prob. 6WECh. 12.3 - Prob. 7WECh. 12.3 - Prob. 8WECh. 12.3 - Prob. 9WECh. 12.3 - Prob. 10WECh. 12.3 - Prob. 11WECh. 12.3 - Prob. 12WECh. 12.3 - Prob. 13WECh. 12.3 - Prob. 14WECh. 12.3 - Prob. 15WECh. 12.3 - Prob. 16WECh. 12.3 - Prob. 17WECh. 12.3 - Prob. 18WECh. 12.3 - Prob. 19WECh. 12.3 - Prob. 20WECh. 12.3 - Prob. 21WECh. 12.3 - Prob. 22WECh. 12.3 - Prob. 23WECh. 12.3 - Prob. 24WECh. 12.3 - Prob. 25WECh. 12.3 - Prob. 26WECh. 12.3 - Prob. 27WECh. 12.3 - Prob. 28WECh. 12.3 - Prob. 29WECh. 12.3 - Prob. 30WECh. 12.3 - Prob. 31WECh. 12.3 - Prob. 32WECh. 12.3 - Prob. 33WECh. 12.3 - Prob. 34WECh. 12.3 - Prob. 35WECh. 12.3 - Prob. 36WECh. 12.3 - Prob. 37WECh. 12.3 - Prob. 38WECh. 12.3 - Prob. 39WECh. 12.3 - Prob. 40WECh. 12.3 - Prob. 1CCh. 12.3 - Prob. 1ST1Ch. 12.3 - Prob. 2ST1Ch. 12.3 - Prob. 3ST1Ch. 12.3 - Prob. 4ST1Ch. 12.3 - Prob. 5ST1Ch. 12.3 - Prob. 6ST1Ch. 12.3 - Prob. 7ST1Ch. 12.3 - Prob. 8ST1Ch. 12.3 - Prob. 1CKCh. 12.3 - Prob. 2CKCh. 12.3 - Prob. 3CKCh. 12.3 - Prob. 4CKCh. 12.4 - Prob. 1CECh. 12.4 - Prob. 2CECh. 12.4 - Prob. 3CECh. 12.4 - Prob. 4CECh. 12.4 - Prob. 5CECh. 12.4 - Prob. 6CECh. 12.4 - Prob. 7CECh. 12.4 - Prob. 8CECh. 12.4 - Prob. 9CECh. 12.4 - Prob. 1WECh. 12.4 - Prob. 2WECh. 12.4 - Prob. 3WECh. 12.4 - Prob. 4WECh. 12.4 - Prob. 5WECh. 12.4 - Prob. 6WECh. 12.4 - Prob. 7WECh. 12.4 - Prob. 8WECh. 12.4 - Prob. 9WECh. 12.4 - Prob. 10WECh. 12.4 - Prob. 11WECh. 12.4 - Prob. 12WECh. 12.4 - Prob. 13WECh. 12.4 - Prob. 14WECh. 12.4 - Prob. 15WECh. 12.4 - Prob. 16WECh. 12.4 - Prob. 17WECh. 12.4 - Prob. 18WECh. 12.4 - Prob. 19WECh. 12.4 - Prob. 20WECh. 12.4 - Prob. 21WECh. 12.4 - Prob. 22WECh. 12.4 - Prob. 23WECh. 12.4 - Prob. 24WECh. 12.4 - Prob. 25WECh. 12.4 - Prob. 26WECh. 12.4 - Prob. 27WECh. 12.4 - Prob. 28WECh. 12.4 - Prob. 29WECh. 12.4 - Prob. 30WECh. 12.4 - Prob. 31WECh. 12.4 - Prob. 32WECh. 12.4 - Prob. 33WECh. 12.4 - Prob. 34WECh. 12.4 - Prob. 1CCh. 12.4 - Prob. 1CKCh. 12.4 - Prob. 2CKCh. 12.4 - Prob. 3CKCh. 12.4 - Prob. 4CKCh. 12.4 - Prob. 1AECh. 12.4 - Prob. 2AECh. 12.4 - Prob. 1BECh. 12.4 - Prob. 2BECh. 12.4 - Prob. 3BECh. 12.4 - Prob. 1MRECh. 12.4 - Prob. 2MRECh. 12.4 - Prob. 3MRECh. 12.4 - Prob. 4MRECh. 12.4 - Prob. 5MRECh. 12.4 - Prob. 6MRECh. 12.5 - Prob. 1CECh. 12.5 - Prob. 2CECh. 12.5 - Prob. 3CECh. 12.5 - Prob. 4CECh. 12.5 - Prob. 5CECh. 12.5 - Prob. 6CECh. 12.5 - Prob. 7CECh. 12.5 - Prob. 8CECh. 12.5 - Prob. 9CECh. 12.5 - Prob. 10CECh. 12.5 - Prob. 11CECh. 12.5 - Prob. 12CECh. 12.5 - Prob. 13CECh. 12.5 - Prob. 1WECh. 12.5 - Prob. 2WECh. 12.5 - Prob. 3WECh. 12.5 - Prob. 4WECh. 12.5 - Prob. 5WECh. 12.5 - Prob. 6WECh. 12.5 - Prob. 7WECh. 12.5 - Prob. 8WECh. 12.5 - Prob. 9WECh. 12.5 - Prob. 10WECh. 12.5 - Prob. 11WECh. 12.5 - Prob. 12WECh. 12.5 - Prob. 13WECh. 12.5 - Prob. 14WECh. 12.5 - Prob. 15WECh. 12.5 - Prob. 16WECh. 12.5 - Prob. 17WECh. 12.5 - Prob. 18WECh. 12.5 - Prob. 19WECh. 12.5 - Prob. 20WECh. 12.5 - Prob. 21WECh. 12.5 - Prob. 22WECh. 12.5 - Prob. 23WECh. 12.5 - Prob. 24WECh. 12.5 - Prob. 25WECh. 12.5 - Prob. 26WECh. 12.5 - Prob. 27WECh. 12.5 - Prob. 28WECh. 12.5 - Prob. 29WECh. 12.5 - Prob. 1ST2Ch. 12.5 - Prob. 2ST2Ch. 12.5 - Prob. 3ST2Ch. 12.5 - Prob. 4ST2Ch. 12.5 - Prob. 5ST2Ch. 12.5 - Prob. 6ST2Ch. 12.5 - Prob. 1CKCh. 12.5 - Prob. 2CKCh. 12.5 - Prob. 3CKCh. 12.5 - Prob. 4CKCh. 12.5 - Prob. 5CKCh. 12.5 - Prob. 6CKCh. 12.5 - Prob. 1AECh. 12.5 - Prob. 2AECh. 12.5 - Prob. 1BECh. 12 - Prob. 1ECh. 12 - Prob. 2ECh. 12 - Prob. 3ECh. 12 - Prob. 4ECh. 12 - Prob. 5ECh. 12 - Prob. 6ECh. 12 - Prob. 1CRCh. 12 - Prob. 2CRCh. 12 - Prob. 3CRCh. 12 - Prob. 4CRCh. 12 - Prob. 5CRCh. 12 - Prob. 6CRCh. 12 - Prob. 7CRCh. 12 - Prob. 8CRCh. 12 - Prob. 9CRCh. 12 - Prob. 10CRCh. 12 - Prob. 11CRCh. 12 - Prob. 12CRCh. 12 - Prob. 13CRCh. 12 - Prob. 14CRCh. 12 - Prob. 15CRCh. 12 - Prob. 16CRCh. 12 - Prob. 17CRCh. 12 - Prob. 18CRCh. 12 - Prob. 19CRCh. 12 - Prob. 1CTCh. 12 - Prob. 2CTCh. 12 - Prob. 3CTCh. 12 - Prob. 4CTCh. 12 - Prob. 5CTCh. 12 - Prob. 6CTCh. 12 - Prob. 7CTCh. 12 - Prob. 8CTCh. 12 - Prob. 9CTCh. 12 - Prob. 10CTCh. 12 - Prob. 11CTCh. 12 - Prob. 12CTCh. 12 - Prob. 13CTCh. 12 - Prob. 14CTCh. 12 - Prob. 15CTCh. 12 - Prob. 16CTCh. 12 - Prob. 1CURCh. 12 - Prob. 2CURCh. 12 - Prob. 3CURCh. 12 - Prob. 4CURCh. 12 - Prob. 5CURCh. 12 - Prob. 6CURCh. 12 - Prob. 7CURCh. 12 - Prob. 8CURCh. 12 - Prob. 9CURCh. 12 - Prob. 10CURCh. 12 - Prob. 11CURCh. 12 - Prob. 12CURCh. 12 - Prob. 13CURCh. 12 - Prob. 14CURCh. 12 - Prob. 15CURCh. 12 - Prob. 16CURCh. 12 - Prob. 17CURCh. 12 - Prob. 18CURCh. 12 - Prob. 19CURCh. 12 - Prob. 20CUR
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