Chapter 12.3, Problem 20WE

a.

To determine

To determine which container contains more

Answer to Problem 20WE

The can contains more.

Explanation of Solution

Given: Consider thegiven information,

Radius of cylinder = 5cm

Height of cylinder = 10cm

Radius of cone = 4cm

Height of cone = 6cm

Formula Used:

Volume of the cylinder = $\pi r^{2}h$

Volume of the cone = $\frac{1}{3}\pi r^{2}h$

As the volume of the can is more than the volume of the bottle, so the can contains more than the bottle.

b.

To determine

To determine the volume of can and bottle

Answer to Problem 20WE

The volume of can and bottle is $785$ $c{m}^3$ and $150.72$ $c{m}^3$

Explanation of Solution

Given: Consider thegiven information,

Radius of cylinder = 5cm

Height of cylinder = 10cm

Radius of cone = 4cm

Height of cone = 6cm

  $\pi \approx 3.14$

Calculation: The volume of the can and the bottle is,

Volume of can = $3.14\times {(5)}^2\times 10$ = $785$ $c{m}^3$

Volume of bottle = $(3.14\times {(4)}^2\times 10)+(\frac{1}{3}\times 3.14\times {(4)}^2\times 6)$ = $150.72$ $c{m}^3$

Conclusion:

The volume of can and bottle is $785$ $c{m}^3$ and $150.72$ $c{m}^3$