Chapter 12.1, Problem 25WE

To determine

To find: the weight.

Answer to Problem 25WE

The weight is $1.8\text{kg}$ .

Explanation of Solution

Given information:

A brick with dimensions $\text{20cm,10cm,5cm}$ weighs $\text{1}\text{.2}$ kg. another brick dimensions $\text{25cm,15cm,4cm}$ .

Calculation: to find the weight, first find the volume of the first brick,

  $\begin{array}{l}{v}_1=20·10·5\\ v_1=1000\text{ [simplify]}\end{array}$

So for the $1{\text{cm}}^3$ , weight of material,

  $\begin{array}{l}1000{\text{cm}}^3=1.2\text{kg}\\ 1{\text{cm}}^3=0.0012\text{kg [divide]}\end{array}$

Now, find the volume of the another brick,

  $\begin{array}{l}{v}_2=25·15·4\\ v_2=1500\text{ [simplify]}\end{array}$

Thus, the weight of the brick is,

  $1500·0.0012kg=1.8\text{kg}$