Concept explainers
(a)
Whichlimit can be evaluated by using direct substitution. Thenevaluate or approximate each limit.
(a)

Answer to Problem 40E
This limit can be evaluated using direct substitution. Value of limx→0x2sinx2=0
Explanation of Solution
Given info:
limx→0xcosx
Formula used:
If f(x) becomes arbitrarily close to a unique number L as approaches c fromeither side, then the limit of f(x) as approaches c is L. This is written as
limx→cf(x)=L
Calculation:
We have
limx→0xcosx
Substituting directly,
limx→0xcosx=0cos0=0
This limit can be evaluated using direct substitution. Value of limx→0xcosx=0
Conclusion:
Thus,this limit can be evaluated using direct substitution. Value of limx→0xcosx=0
(b)
Whichlimit can be evaluated by using direct substitution. Thenevaluate or approximate each limit.
(b)

Answer to Problem 40E
This limit cannot be evaluated using direct substitution. Value of limx→01−cosxx2=12
Explanation of Solution
Given info:
limx→01−cosxx2
Formula used:
If f(x) becomes arbitrarily close to a unique number L as approaches c fromeither side, then the limit of f(x) as approaches c is L. This is written as
limx→cf(x)=L
Calculation:
We have
limx→01−cosxx2
Substituting directly,
limx→01−cosxx2=1−cos002=00
This limit cannot be evaluated using direct substitution.
Value of
limx→01−cosxx2=limx→02sin2(x2)x2=2limx→0sin(x2)x×sin(x2)xlimx→01−cosxx2=2limx→0sin(x2)2×x2×limx→0sin(x2)2×x2limx→01−cosxx2=24limx→0sin(x2)x2×limx→0sin(x2)x2limx→01−cosxx2=12×1×1limx→01−cosxx2=12
Conclusion:
Thus,this limit cannot be evaluated using direct substitution. Value of limx→01−cosxx2=12
Chapter 12 Solutions
EBK PRECALCULUS W/LIMITS
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