Chapter 12, Problem 62A

Interpretation Introduction

Interpretation:

The molecules having bent shape are to be identified and their geometries are to be compared.

Concept introduction:

Structure of molecule can be drawn using VSEPR theory. The total number of bonding and non-bonding pairs of electrons tells about the geometry and molecular structure of the molecule.

Answer to Problem 62A

All the four molecules $O_3$ , $H_{2}O$ , $S{O}_2$ and $OC{l}_2$ have bent shape.

All bent molecules don’t have same geometry.

Explanation of Solution

Geometry depends on both bonding and non-bonding pairs of electrons. But shape depends on only bonding pairs of electrons. Thus, molecules having same bonding pairs always have same shape but they may have different geometry depending on number of non-bonding pairs of electrons.

Like $O_3$ has bent shape but trigonal planar geometry

  $H_{2}O$ has bent shape but tetrahedral geometry

  $S{O}_2$ has bent shape but trigonal planar geometry

  $OC{l}_2$ has bent shape but tetrahedral geometry

Conclusion

Thus, molecules having same shape can have different geometry.