Chapter 12, Problem 42A

Interpretation Introduction

Interpretation:

The geometric structure of $C{H}_4$ is to be drawn and the bond angle is to be written.

Concept introduction:

Structure of molecule can be drawn using VSEPR theory. The total number of bonding and non-bonding pairs of electrons tells about the geometry of the molecule.

The valence electrons are the electrons present in outermost shell.

Answer to Problem 42A

Geometric structure is tetrahedral.

4 pairs of electrons are surrounding the carbon in $C{H}_4$ .

The bond angle of $H-C-H$ is $109\text{'}28\text{'}\text{'}$

Explanation of Solution

Lewis structure of $C{H}_4$is:

  

Structure shows in $C{H}_4$ central atom carbon has four bond pairs and no lone pair. In total it has 4 pairs of electrons. Thus, its geometry is tetrahedral according to VSEPR theory.

Thus, 4 pairs of electrons are surrounding the carbon in $C{H}_4$ .

A normal tetrahedral geometry has bond angle of $109\text{'}28\text{'}\text{'}$

Conclusion

Thus, $C{H}_4$ is tetrahedral.