Concept explainers
Common baker’s yeast (
a. Which colonies are prototrophic and which are auxotrophic? What growth information is used to makethese determinations?
b. Classify the nature of the mutations in colonies
c. What can you say about colony
Want to see the full answer?
Check out a sample textbook solutionChapter 12 Solutions
Genetic Analysis: An Integrated Approach (2nd Edition)
- You are studying a microorganism that contains a chloramphenicol acetyltransferase (CAT) enzyme, and looking for a clone of this microorganism that no longer contains the gene encoding CAT. Imagine you had an LB plate containing chloramphenicol. You streak an isolated colony of the Parent Strain and Clone A onto the same plate. Which of the following statements are true about the growth pattern after 24 hours in the incubator? Select all that apply? L-hlareeheticol LB chloremphenicel Parent Clune A Parent Clone A LD chlerephenicol 18 chloremphenitol Paremt Clone A Paront Clone A Plate A is the expected growth pattern as clone A should grow in the LB plate with chloramphenicol Plate B is the expected growth pattern as LB plate with chloramphenicol parent strain should grow in the Plate B is the expected growth pattern as clone A should not grow in the LB plate with chloramphenicol Plate A is the expected growth pattern as the parent strain should not grow in the LB plate with…arrow_forwardA pure culture of an unknown bacterium was streaked onto plates of a variety of media. You notice that the colony morphologyis strikingly different on plates of minimal media with glucose compared to that seen on trypticase soy agar plates. How can you explain these differences in colony morphology? Also, describe what happens when a nonsense mutation is introduced into the gene encoding transposase within a transposon and why is it more likely that insertions or deletions will be more detrimental to a cell than point mutations?arrow_forwardA research group is studying a bacterium X that binds to mucosal cells in the lung and invades. Wildtype X has an LD50 value of 10 bacteria when administered to mice by inhalation. Using transposon mutagenesis, the researchers have isolated two mutants of X that they call Xmut1 and Xmut2, both of which have LD50 values of 105 when inhaled by mice. However, in tissue culture cells, Xmut1 can invade the cells just as well as wild-type X, while Xmut2 cannot. Provide a possible explanation for these results.arrow_forward
- Assume you have successfully cloned a small (200 bp) fragment of DNA into the polylinker region of a pUC18 cloning vector. Describe the appearance of transformed colonies you would expect to see on each of the following plates: plain media, media containing ampicillin, media containing tetracycline, media containing ampicillin and X-Gal.arrow_forwardpZERO®-1 is a 2808 bp cloning vector from Invitrogen. This vector allows effective selection of positive recombinants via disruption of the lethal gene, ccdB. Besides the lethal gene, it has an additional Zeocin resistance gene for tighter screening control. The Zeocin resistance gene in this vector is certainly more advantageous over ampicillin resistance gene. Give its THREE (3) advantages.arrow_forwardThe following two strains of E. coli are crossed with each other: Hfr pan* thi* ala* and F¯pan¯ thi¯ ala¯ It was shown that the pan marker entered last in interrupted conjugation experiments. By spreading the bacteria from these experiments on different selection media, the following results (in number of colonies) were obtained: MM + Gluc IM + Gluc + ala MM + Gluc + thi MM + Gluc + thi + ala 280 281 286 339 Give the number of each phenotypic class and justify your answer. Determine the order of the genes. What are the genetic distances between the different loci? Abbreviations: Gluc: glucose; Ala: alanine; Thi: thiamine; Pan: pantothenic acid.arrow_forward
- Determine the map distances between the genes.arrow_forwardMatch the following Conjugation terms with the most appropriate description in the image: F- recombinant F- strain F+ strain HFR strainarrow_forwardOrder the following experimental steps to identify auxotrophic mutants in Saccharomyces Cerevisiae that cannot sythesize their own Leucine. an option can be selected more than once. step 1: Step 2: Step 3: Step 4: Step 5: Step 6:arrow_forward
- E. coli cells are simultaneously infected with two strains of phage λ. One strain has a mutant host range, is temperature sensitive, and produces clear plaques (genotype h st c); another strain carries the wildtype alleles (genotype h+ st+ c+). Progeny phages are collected from the lysed cells and are plated on bacteria. The following numbers of different progeny phages are obtained: Progeny phage genotype Number of plaques h+ c+ st+ 321 h c st 338 h+ c st 26 h c+ st+ 30 h+ c st+ 106 h c+ st 110 h+ c+ st 5 h c st+ 6 a. Determine the order of the three genes on the phage chromosome. b. Determine the map distances between the genes. c. Determine the coefficient of coincidence and the interferencearrow_forwardGiven what we've discussed in class, what will be most likely outcome if you conjugate an streptomycin resistant ampicillin sensitive methionine auxotroph E. coli strain (engineered to be pir+) that is F- with a streptomycin sensitive non-HFR methionine prototroph strain that is F- and RP4+ but contains pUC18? Colonies on minimal media + ampicillin +streptomycin plates No colonies on minimal media +ampicillin +streptomycin platesarrow_forwardIn E. coli, the gene bioD+ encodes an enzyme involved in biotin synthesis, and galK+ encodes an enzyme involved in galactose utilization. An E. coli strain that contained wild-type versions of both genes was infected with P1 phage, and then a P1 lysate was obtained. This lysate was used totransduce (infect) a strain that was bioD− and galK−. The cellswere plated on a medium containing galactose as the sole carbonsource for growth to select for transduction of the galK+ gene.This medium also was supplemented with biotin. The resultingcolonies were then restreaked on a medium that lacked biotin tosee if the bioD+ gene had been cotransduced. The following resultswere obtained:What information do you know based onthe question and your understanding of the topic?arrow_forward
- Biology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage Learning