Understanding Our Universe
3rd Edition
ISBN: 9780393614428
Author: PALEN, Stacy, Kay, Laura, Blumenthal, George (george Ray)
Publisher: W.w. Norton & Company,
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Chapter 12, Problem 28QAP
To determine
The reason why star becomes more luminous when the protons in the core runs out; the reason why surface temperature of star cool down.
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Using solar units, we find that a star has 4 times the luminosity of the Sun, a mass 1.25 times the mass of the Sun, and a surface temperature of 4090 K (take the Sun's surface temperature to be 5784 K for the sake of this problem). This means the star has a radius of.................... solar radii and is a .................... star (use the classification).
A red giant star might have radius = 104 times the solar radius,
and luminosity = 1730 times solar luminosity.
Use the data given below to calculate the temperature
at the surface of the red giant star.
Data:
solar radius R = 7 x 108 meters
solar luminosity L = 4 x 1026 watts
Stefan-Boltzmann constant
a = 5.67 x 10-8 W m² K-4
(in K)
A: 1226 OB: 1434 OC: 1678 OD: 1963 OE: 2297 OF: 2688 OG: 3145 OH: 3679
A star with a radius 1.5 times that of the Sun has a surface temperature T=9,000 K. Calculate the luminosity of this star and express your answer in units of the Solar luminosity (the Solar luminosity = 3.84 x 1026 W and the Solar radius = 7 x 108 m)
Chapter 12 Solutions
Understanding Our Universe
Ch. 12.1 - Prob. 12.1CYUCh. 12.2 - Prob. 12.2CYUCh. 12.3 - Prob. 12.3CYUCh. 12.4 - Prob. 12.4CYUCh. 12.5 - Prob. 12.5CYUCh. 12.6 - Prob. 12.6CYUCh. 12 - Prob. 1QAPCh. 12 - Prob. 2QAPCh. 12 - Prob. 3QAPCh. 12 - Prob. 4QAP
Ch. 12 - Prob. 5QAPCh. 12 - Prob. 6QAPCh. 12 - Prob. 7QAPCh. 12 - Prob. 8QAPCh. 12 - Prob. 9QAPCh. 12 - Prob. 10QAPCh. 12 - Prob. 11QAPCh. 12 - Prob. 12QAPCh. 12 - Prob. 13QAPCh. 12 - Prob. 14QAPCh. 12 - Prob. 15QAPCh. 12 - Prob. 16QAPCh. 12 - Prob. 17QAPCh. 12 - Prob. 18QAPCh. 12 - Prob. 19QAPCh. 12 - Prob. 20QAPCh. 12 - Prob. 21QAPCh. 12 - Prob. 22QAPCh. 12 - Prob. 23QAPCh. 12 - Prob. 24QAPCh. 12 - Prob. 25QAPCh. 12 - Prob. 26QAPCh. 12 - Prob. 27QAPCh. 12 - Prob. 28QAPCh. 12 - Prob. 29QAPCh. 12 - Prob. 30QAPCh. 12 - Prob. 32QAPCh. 12 - Prob. 33QAPCh. 12 - Prob. 34QAPCh. 12 - Prob. 35QAPCh. 12 - Prob. 36QAPCh. 12 - Prob. 37QAPCh. 12 - Prob. 38QAPCh. 12 - Prob. 39QAPCh. 12 - Prob. 40QAPCh. 12 - Prob. 42QAPCh. 12 - Prob. 43QAPCh. 12 - Prob. 44QAPCh. 12 - Prob. 45QAP
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- A star begins its life with a mass of 5 MSunbut ends its life as a white dwarf with a mass of 0.8 MSun. List the stages in the star’s life during which it most likely lost some of the mass it started with. How did mass loss occur in each stage?arrow_forwardThe text says a star does not change its mass very much during the course of its main-sequence lifetime. While it is on the main sequence, a star converts about 10% of the hydrogen initially present into helium (remember it’s only the core of the star that is hot enough for fusion). Look in earlier chapters to find out what percentage of the hydrogen mass involved in fusion is lost because it is converted to energy. By how much does the mass of the whole star change as a result of fusion? Were we correct to say that the mass of a star does not change significantly while it is on the main sequence?arrow_forwardIf the surface Temperature of a star was about 11000.0 K instead of 7000.0 K what is the ratio of power per square meter of the 11000.0 K star compared to power per square meter of the 7000.0 K star? How many times greater is the magnitude of power per square meter of the 11000.0 K star compared to the 7000.0 K stararrow_forward
- Many of the bright stars in the night sky are highly luminous normal blue stars (such as Acrux), and others are blue giants (such as Rigel) or red giants (such as Betelgeuse). Generally, such stars have a luminosity of 103 to 105 times that of our Sun! Ignoring any effects from our atmosphere, how bright would a star with a luminosity of 8380 solar luminosities be if it were located 620 light years from Earth? (You will need to convert some values.) W/m² For comparison, if you were 1 meter from a regular 100 W light bulb, the brightness would be 7.96 W/ m². (Since stars are not this bright, your answer should be considerably less!) Kind of amazing you can see these things, isn't it?arrow_forwardIf our Sun has a temperature of 6000 K and a luminosity of 1 Solar Luminosity, what is the luminosity of another star the same size as the Sun, yet which has a surface temperature of 12 000 K ?arrow_forward(a) The surface temperature of a star is 25,000 K and it has a luminosity about 1% that of our Sun. What kind of star is it? (B) The surface temperature of a star is 3,000 K and it has a luminosity about 104 time that of our Sun. What kind of star is it?arrow_forward
- If a star has a surface temperature 2 times lower than the Sun's and a luminosity the same as the Sun, how many times larger is the star than the Sun? (If it is smaller by a factor of 8, you would write 0.125 because 1/8=0.125)arrow_forward= A star population is composed of stars with masses in the range between 1M and 150M. The initial mass function is = 0 (M/M)-2.3, where o (Mo). The luminosity of a star = (M/M) 3.3. Calculate the percentage of the total luminosity of the stars in the population which is produced by stars with mass between 120M and 150M. scales with its mass as L/Larrow_forwardThe surface of a star usually has the highest temperature O True O Falsearrow_forward
- 7 The luminosity class of a star tells an astronomer: O how long ago the star formed O whether the star is a supergiant, a giant, or a main-sequence star O none of these answers O whether the star is close to us or far away O whether or not the star is surrounded by planets #m 3 с $ 4 % 5 6 & O 7 Carrow_forwardA star with a radius 1.5 times that of the Sun has a surface temperature T=9,000 K. Calculate the luminosity of this star and express your answer in units of the Solar luminosityarrow_forwardIf a star has a radius 2 times larger than the Sun's and a luminosity 1/4th that of the Sun, how many times higher is the star's temperature than that of the Sun? (If it is smaller by a factor of 8, you would write 0.125 because 1/8=0.125)arrow_forward
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