Chapter 12, Problem 14STP

Interpretation Introduction

Interpretation:

The mass of $75ml$ of $H_{2}S{O}_4$ needs to be determined.

Concept introduction:

Density of gas is proportional to mass inversely proportional to volume.

Answer to Problem 14STP

(B) $138gm$ is mass of $75ml$ of $H_{2}S{O}_4$.

Explanation of Solution

Density is given by following formula $D=\frac{M}{V}\frac{\left(Mass\right)}{\left(Volume\right)}$

$1.834g/mL=\frac{Mass}{75mL}$

Then mass can be calculated as follows:

$=1.834\frac{g}{\cancel{mL}}\times 75\cancel{mL}=138gof{H}_{2}S{O}_4$.

Thus, the mass is 138 g.