Organic Chemistry: Principles and Mechanisms (Second Edition)
2nd Edition
ISBN: 9780393663556
Author: Joel Karty
Publisher: W. W. Norton & Company
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Question
Chapter 12, Problem 12.35P
Interpretation Introduction
Interpretation:
The reason for the given order of relative reaction rates of electrophilic addition of
Concept introduction:
Molecular bromine undergoes anti addition across a
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Explain why methyl alcohol reacts with HBr faster than other primary alcohols?
H3C
CH3
H3C
NA C→XT
Br
Br₂
CH₂Cl₂
H3C
Electrophilic addition of bromine, Br₂, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic
intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH₂Cl₂.
CH3
Br
In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion
to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the
bromonium ion so that a product with anti stereochemistry is formed.
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Arrow-pushing Instructions
Br
CH3
H3C
CH3
Define the Mechanism of the Radical Addition of HBr to an Alkene ?
Chapter 12 Solutions
Organic Chemistry: Principles and Mechanisms (Second Edition)
Ch. 12 - Prob. 12.1PCh. 12 - Prob. 12.2PCh. 12 - Prob. 12.3PCh. 12 - Prob. 12.4PCh. 12 - Prob. 12.5PCh. 12 - Prob. 12.6PCh. 12 - Prob. 12.7PCh. 12 - Prob. 12.8PCh. 12 - Prob. 12.9PCh. 12 - Prob. 12.10P
Ch. 12 - Prob. 12.11PCh. 12 - Prob. 12.12PCh. 12 - Prob. 12.13PCh. 12 - Prob. 12.14PCh. 12 - Prob. 12.15PCh. 12 - Prob. 12.16PCh. 12 - Prob. 12.17PCh. 12 - Prob. 12.18PCh. 12 - Prob. 12.19PCh. 12 - Prob. 12.20PCh. 12 - Prob. 12.21PCh. 12 - Prob. 12.22PCh. 12 - Prob. 12.23PCh. 12 - Prob. 12.24PCh. 12 - Prob. 12.25PCh. 12 - Prob. 12.26PCh. 12 - Prob. 12.27PCh. 12 - Prob. 12.28PCh. 12 - Prob. 12.29PCh. 12 - Prob. 12.30PCh. 12 - Prob. 12.31PCh. 12 - Prob. 12.32PCh. 12 - Prob. 12.33PCh. 12 - Prob. 12.34PCh. 12 - Prob. 12.35PCh. 12 - Prob. 12.36PCh. 12 - Prob. 12.37PCh. 12 - Prob. 12.38PCh. 12 - Prob. 12.39PCh. 12 - Prob. 12.40PCh. 12 - Prob. 12.41PCh. 12 - Prob. 12.42PCh. 12 - Prob. 12.43PCh. 12 - Prob. 12.44PCh. 12 - Prob. 12.45PCh. 12 - Prob. 12.46PCh. 12 - Prob. 12.47PCh. 12 - Prob. 12.48PCh. 12 - Prob. 12.49PCh. 12 - Prob. 12.50PCh. 12 - Prob. 12.51PCh. 12 - Prob. 12.52PCh. 12 - Prob. 12.53PCh. 12 - Prob. 12.54PCh. 12 - Prob. 12.55PCh. 12 - Prob. 12.56PCh. 12 - Prob. 12.57PCh. 12 - Prob. 12.58PCh. 12 - Prob. 12.59PCh. 12 - Prob. 12.60PCh. 12 - Prob. 12.61PCh. 12 - Prob. 12.62PCh. 12 - Prob. 12.63PCh. 12 - Prob. 12.64PCh. 12 - Prob. 12.1YTCh. 12 - Prob. 12.2YTCh. 12 - Prob. 12.3YTCh. 12 - Prob. 12.4YTCh. 12 - Prob. 12.5YTCh. 12 - Prob. 12.6YTCh. 12 - Prob. 12.7YTCh. 12 - Prob. 12.8YTCh. 12 - Prob. 12.9YTCh. 12 - Prob. 12.10YTCh. 12 - Prob. 12.11YTCh. 12 - Prob. 12.12YT
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- Cyclopropane decomposes fairly rapidly at moderate temperatures whereas cyclohexane is quite stable. Why is this the case?arrow_forwardCH3 CH3 Br- Br2 .CH3 CH2Cl2 CH3 H3C H3C Br Electrophilic addition of bromine, Brɔ, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH,Cl,. In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions CH3 CH3 CH3 CH3 H3C H3C :Br: :Br:arrow_forward2-chloropropane is a major product of the reaction of chlorine with propane under ultraviolet light. Write the mechanism for this reaction including the initiation step and the two propagation steps.arrow_forward
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