a.
Total mechanical energy and momentum of the system before collision.
a.
Answer to Problem 22PP
Total mechanical energy before collision is 4361.6 J and momentum before collision is
Explanation of Solution
Given:
Mass of both hockey player,
Velocity of first hockey player,
Velocity of second hockey player,
Formula used:
Kinetic energy can be obtained by:
Momentum can be obtained by:
Where, m is the mass and v is the velocity.
Calculation:
Total kinetic energy before collision is:
Momentum before collision is
b.
Velocity of players after collision.
b.
Answer to Problem 22PP
6.8 m/s
Explanation of Solution
Given:
Mass of both hockey player,
Velocity of first hockey player,
Velocity of second hockey player,
Formula Used:
Let velocity of players after collision is v m/s
As there is no external force is applied therefore momentum will be conserved.
Calculations:
Conclusion:
So, velocity of hockey players after collision is
c.
Kinetic energy decreased in collision.
c.
Answer to Problem 22PP
Kinetic energy decreased by 153.76 J in collision.
Explanation of Solution
Given:
Mass of both hockey player,
Velocity of first hockey player,
Velocity of second hockey player,
Formula Used:
Kinetic energy can be obtained by:
Calculations:
Velocity of hockey players after collision is 6.8 m/s.
Therefore, kinetic energy after collision is
From part (a) kinetic energy before collision is 4361.6 J
Therefore, loss of kinetic energy in collision is:
Chapter 11 Solutions
Glencoe Physics: Principles and Problems, Student Edition
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Physics: Principles with Applications
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