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Based on observations, the speed of a jogger can be approximated by the relation
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Vector Mechanics For Engineers
- applied mechanics 2arrow_forwardI need help with this question please. thank youarrow_forwardmoments = 0) in order to determine a force or moment requires a complete free body diagram. Absence of a free body diagram may result in a grade of 'O' for the problem. %3D 1. The acceleration of a particle is directly proportional to time, t, i.e., a = at where a is a constant. At t = 0 s, the position of the particle is -150 mm. Knowing that v = 200 mm/s and x = 75 mm whent = 3 s, determine the position and velocity when t = 5 s.arrow_forward
- The acceleration of a particle moving along the x-axis is given by the relation a = kt m/s?., where k is a constant, and i is in seconds. Supposed that v = -10 m/s, x = x, when / = 0 and x = 0, v = 0 when t = 6 s, determine (a) the value of the constants k and x,, (b) the position as a function of t. %3Darrow_forwardDr. Wang was doing donuts (i.e. driving in a circle) in his car over the weekend and used his iPhone to measure the acceleration he experienced (this is a true story). The plot below shows the lateral acceleration recorded by his iPhone. Knowing that he was maintaining a constant speed and that the radius of his donuts was 10 meters, determine how fast he was driving and approximately how many donuts (laps) did he completed in the 6 seconds shown?arrow_forward3) Two particles, A & B, move along parallel rectilinear paths. At t=0 the particles are directly opposite one another. Particle A moves according to SA = 12t² - 4t³ inches and particle B moves with a constant speed of 12 inches/ second. (a) Determine the relative position of A with respect to B at t = 1 second. (b) Determine the relative velocity of A with respect to B at t = 1 second. ANS. SA/B = -4 inches VA/B = 0 inches/secarrow_forward
- Q#1: A motorist enters a freeway at 30 ft/s and accelerates uniformly to 60 ft/s. From the odometer in the car, the motorist knows that she traveled 550 ft while accelerating. Determine the acceleration of the car.arrow_forwardStarting from rest, a bicyclist travels around a horizontal circular path, p= 10 m, at a speed of (0.09t2 + 0.1t) m/s, where t is in seconds. Part A Determine the magnitude of his velocity when he has traveled s = 3 m. Express your answer to three significant figures and include the appropriate units. HA ? Value Units v = Submit Request Answer Part B Determine the magnitude of his acceleration when he has traveled s = 3 m. Express your answer to three significant figures and include the appropriate units. HẢ Value Units a = Submit Request Answerarrow_forwardA test track for automobiles has a portion with a specific profile described by y = h (1 - cos()) where h = 0.20 m and w= 2 m, and where the argument of the cosine function is understood to be in radians. A car travels in the positive x direction with a constant x component of velocity equal to 100 km/h. Modeling the car as a point moving along the given profile, determine the velocity and acceleration (expressed in m/s and m/s², respectively) of the car for x = 25 m. (Round the final answers to four decimal places. Include a minus sign if necessary.) y Ĵ î The velocity of the car is ( The acceleration of the car is + j) m/s. 3) m/s².arrow_forward
- An object of mass 2 kg is subjected to a varying force, and it moves along a straight line with time dependent acceleration. The acceleration of the object is given by à(t) = [(2t3 + +2)1 + (1.5t - 0.5)}] m/s, where t is time in seconds. Initially, the object is at rest (initial velocity = 0, t = 0). Determine the magnitude of the velocity of the object at t = 4 seconds.arrow_forwarde V:.. | %A£ ]n. Time left 0:19:30 Automobile A and B are initially 30 m apart travelling in adjacent highway lanes at speeds VA = 14.4 km/hr., VB = 23.4 km/hr. at t = 0.0. Knowing that automobile A has a constant acceleration of 0.8 m/s2 and automobile B has a constant deceleration of 0.4 m/s2. The speed of B when it is overtaken by A is: A Side view 73.579 m/s 34.621 m/s 11.564 m/s 2.718 m/s 43.578 m/s IIarrow_forwardA particle moves along a straight line with acceleration a = 0.2*v2 where Vis the velocity (m/s) the velocity at x=4.9 m is knowing that t=0 ,x=0, Vo=1.1 m/s Select one: O A. 2.89 О В. 3.65 O C. 1.90 O D. 2.51 ОЕ. 3.27 Clear my choice the acceleration at t=4.9 s is Select one: O A. 0.25 О В. 0.10 OC.0.31 OD. 0.22 O E. 0.16 the velocity at t=4.9 s is Select one: O A. 5.02 ОВ. 1.23 OC. 2.37 OD. 3.13 O E. 4.07 the acceleration at x=4.9 m is Select one: O A. 0.20 О В. О.14 OC.0.28 OD. 0.00 O E. 0.47arrow_forward
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