College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Convert 3.50 x 103 cal to the equivalent number of (a) kilocalories (also known as Calories, used to describe the energy content of food) and (b) joules.
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- A styrofoam container used as a picnic cooler contains a block of ice at 0°C. If 564 g of ice melts in 1 hour, how much heat energy per second is passing through the walls of the container? The heat of fusion of ice is 3.33 x 10° J/kg. Answer in units of W.arrow_forward21.0 g of copper pellets are removed from a 300C oven and immediately dropped into 70.0 mL of water at 17.0C in an insulated cup. copper = 385 (J/kg K) water = 4190 (J/kg K) What will the new water temperature be? Express your answer with the appropriate units.arrow_forwardMuffins are taken out of the oven with a temperature of 200°F and are placed on a cooling rack with a room temperature of 70°F. After 15 minutes, the muffins have cooled to 170°F. If it is recommended to wait 30 minutes before eating, what temperature would the muffins be? Round the value of k to the nearest fourth decimal place.arrow_forward
- Luis and Salman are trying to increase the temperature of a substance by heating it. . What is the quantity of heat in kilojoules required to raise the temperature of 1.2 kg of the substance from3°C to 110 °C at a pressure of 1.0 atm? Please keep three significant figures. Useful information: Melting point = 293 K heat of fusion = 3.90 x 104 J/kg. boiling point is 423 K heat of vaporization 7.80 x 104 J/kg (at a pressure of 1.0 atm). The specific heats for the solid phase is 600 J/(kg K) The specific heats for the liquid phase is 1000 J/(kg K) The specific heats for the gaseous phase is 400 J/(kg K)arrow_forward314.0 kg copper bar is put into a smelter for melting. The initial temperature of the copper is 299.0 K. How much heat in kilojoules must the smelter produce to completely melt the copper bar? (The specific heat for copper is 386 J/kg•K, the heat of fusion for copper is 205 kJ/kg, and its melting point is 1357 K.)arrow_forwardWe know from Newton's Law of Cooling that the rate at which an object warms up is proportional to the difference between the ambient temperature of the room and the temperature of the object. The differential equation corresponding to this situation is given by y' = k(M – y) where k is a positive constant. The solution to this equation is given by y = M + (yo – M)e-kt , where yo is the initial temperature of the object. Suppose your Thanksgiving turkey is kept at a temperature of 40 degrees Fahrenheit until it is put into a 350 degree Fahrenheit oven. It takes 2 hours for the turkey to warm up to a safe eating temperature of 165 degrees Fahrenheit. Find the values of yo, M, and k, for this situation, rounding your answers to 3 decimal places. Yo= M = k= Regardless of your answers above, suppose the k value in this situation is k = 0.3. Find the initial rate of increase of the turkey's temperature as soon as it is placed in the oven. Round to 3 decimal places. degrees per hour.arrow_forward
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