At atmospheric pressure, how much energy is required to heat 47.0 g of H2O(s) at -10.0◦C to H2O(g) at 129.0◦C? specific heat ice - 2093 J/kg C latent heat of fusion - 334*10^3 J/kg specific heat water - 4184 J/kg C latent heat of vaporization - 2260*10^3 J/kg specific heat vapor - 2010 J/kg C These values are approximate and fine to use. Please show all work.

The temperature of a 5.00-kg lead brick is increased by 525 C°. If the specific heat capacity of lead is 128 J/(kg.C°), what is the increase in the mass of the lead brick when it has reached its final temperature? O 5.80 × 10- -11 kg O 9.12 × 10-11 kg O 1.60 × 10-12 kg O 3.73 × 10-12 kg O 2.80 × 10-12 kg

A student obtains the following data in a calorimetry experiment designed to measure the specific heat of aluminum. Initial temperature of water and calorimeter 70.3°C Mass of water 0.402 kg Mass of calorimeter 0.04 kg Specific heat of calorimeter 0.60 kJ/kg.°C Initial temperature of aluminum Mass of aluminum Final temperature of mixture (a) Use these data to determine the specific heat of aluminum. J/kg. °C (b) Is your result within 15% of 900 J/kg . °C? Yes No Need Help? 26.8°C 0.199 kg 66.4°C Read It

When it rains, water vapor in the air condenses into liquid water, and energy is released. (a) How much energy is released when 0.0318 m (1.25 inch) of rain falls over an area of 2.59×106 m² (one square mile)? (b) If the average energy needed to heat one home for a year is 1.50x1011 J, how many homes could be heated for a year with the energy determined in part (a)? (a) Number (b) Number i i Units Units >

What is the ratio of the energy required to warm 125 g of Ice (0.0 \deg C) to body temperature (37 \deg C) to warming the same amount of water through the same temperature change? Answer format is the number Eice/Ewater = (2 significant figures) Latent Heat of Fusion of Water: 335, 000 J/kg Specific Heat Capacity of Water: 4186 J/kg/\deg C

Measurement of specific heat of metals Aluminum Cupper Mass of inner cup of calorimeter mcal, g 50 50 Specific heat of calorimeter Ccal, cal/(g °C) Specific heat of water Cw, cal/(g °C) 0.217 0.217 1.00 1.00 Mass of metal Mm, g 80 140 Mass of inner cup + water mcal + Mw, g 220 240 Mass of water Mw, g 170 190 Initial temperature of calorimeter and water to, °C Initial temperature of metal tm, °C 22 22 100 100 Final equilibrium temperature tr, °C 30 26 Thermal energy gain by calorimeter and water Qgain, cal Specific heat of metal Cm, cal/(g °C) Standard specific heat of metal Cst , cal/(g °C) 0.217 0.093 |% error Thermal energy lost = Thermal energy gained Thermal energy Q = cmAt %3D %3D Specific heat C |Thermal energy lost by metal = Thermal energy gained by (water + calorimeter) %3D EmMm(tm-tf)=(ccatMeat +CwMw)(tp- to) %3D (Ccaimcal+ Cymw)(tf- to). Gm = %3D Mm(tm - t;) |