Find the heat loss through the wall.

Question

A double-pane glass window consists of two pieces of glass, each having athickness of 8 mm, with a thermal conductivity of k = 1.4 W⁄m ⋅ K . The twoglass panes are separated by an air gap of 10 mm, as shown in Figure 11.10 .Assuming the thermal conductivity of air to be k = 0.025 W⁄m ⋅ K , determinethe total R-value for this window. The total thermal resistance of the window is obtained by adding the resistance offered by each pane of glass and the air gap in the following manner:

Answer 1

Question

Chapter 11, Problem 11P

To determine

Find the heat loss through the wall.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

A double-pane glass window consists of two pieces of glass, each having athickness of 8 mm, with a thermal conductivity of k = 1.4 W⁄m ⋅ K . The twoglass panes are separated by an air gap of 10 mm, as shown in Figure 11.10 .Assuming the thermal conductivity of air to be k = 0.025 W⁄m ⋅ K , determinethe total R-value for this window. The total thermal resistance of the window is obtained by adding the resistance offered by each pane of glass and the air gap in the following manner:

12. Thermal efficiency using temperature values 13. Thermal efficiency using rc and k values

3. A 30 m steel tape is 2 mm too long at 20°C with a pull of 55 N. A rectangle is measured with this The sides are recorded as 144.95 m and 113.00 m. The average temperature during the measurement is 30°C with a pull of 55 N. Use coefficient of expansion of steel tape as a 0.0000116 m /°C. tape. a) Compute the actual length of tape during measurement. b) What is the true area? c) What is the error in area in sq.m.