Introduction To Statistics And Data Analysis
6th Edition
ISBN: 9781337793612
Author: PECK, Roxy.
Publisher: Cengage Learning,
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 10.7, Problem 75E
A study of hospitalized patients who develop pneumonia reported that 1 in 5 (20%) are readmitted to the hospital within 30 days after discharge (“Comparison of Therapist-Directed and Physician Directed Respiratory Care in COPD Subjects with Acute Pneumonia,” Respiratory Care [2015]: 151–154).
The study reported that 15 out of n = 162 hospital patients who had been treated for pneumonia using a respiratory therapist protocol were readmitted to the hospital within 30 days after discharge. These data can be used to decide if the proportion readmitted is less than 0.20.
- a. What hypotheses should be tested?
- b. Discuss whether the conditions necessary for a large-sample hypothesis test for one proportion are satisfied.
- c. The exact binomial test can be used even in cases when the
sample size condition for the large-sample test is met. Use the output at the bottom of the page from the Shiny app “Exact Binomial Test for One Proportion” to carry out an exact binomial test for one proportion, using the null hypothesis that the population proportion of subjects who will be readmitted to a hospital within 30 days after following a respiratory therapist protocol for treatment of pneumonia is equal to 1/5 = 0.2.Output for Exercise 10.75
- d. Calculate the P-value for the same hypotheses using the large-sample approach for testing one population proportion. Compare this P-value to the P-value obtained in Part (b). Would the same conclusion be reached in either case? Explain.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A diabetic nurse seeks to assess the prevalence of type 2 diabetes among women in a population (age 18 to 80 years). She conveniently sampled 100 women attending antenatal care and asked them whether they had hypertension. Of the 100 pregnant women sampled, 50 consented to take part in the study and 1 had diabetes. Based on this finding, the nurse concluded that “the prevalence of diabetes among women in the population is low (2%).”
A) Do you agree with the conclusion made by the diabetic nurse? Justify in not more than 100 words?
B) Would you have conducted such a study differently if you had all the resources at hand (Describe in not more than 75 words).
Colonoscopy is a medical procedure that is designed to find and remove precancerous lesions in the colon before they become cancerous. The article “Association of Colonoscopy and Death from Colorectal Cancer” (N. Baxter, M. Goldwasser, et al., Annals of Internal Medicine, 2009:1–8) reports that in a sample of 10,292 people diagnosed with colorectal cancer, 7.0% had previously had a colonoscopy, and in a sample of 51,460 people without colorectal cancer, 9.8% had previously had a colonoscopy. Can you conclude that the percentage of people who have had colonoscopies is greater in those without colorectal cancer?
A pathological video game user (PVGU) is a video game user that averages 31 or more hours a week of gameplay. According to the article “Pathological Video Game Use among Youths: A Two-Year Longitudinal Study” (Pediatrics, Vol. 127, No. 2, pp. 319–329) by D. Gentile et al., in 2011, about 9% of children in grades 3–8 were PVGUs. Suppose that, today, five youths in grades 3–8 are randomly selected. Let X represent the number of youths who are PVGUs.
n =
p =
1 – p =
Prepare the probability distribution for the random variable X. Complete the following table. Round your answers to 4 decimal places e.g. 0.XXXX or .XXXX.
X = x
P(X=x)
0
1
2
3
4
5
∑=1.0000∑=1.0000
Calculate the probability that EXACTLY three youths are PVGUs. Round your answers to 4 decimal places e.g. 0.XXXX or .XXXX.
P(X = 3) =
Calculate the probability that AT LEAST two youths are PVGUs. Round your answers to 4 decimal places e.g. 0.XXXX or .XXXX.
P(X ≥ 2) =
Calculate the…
Chapter 10 Solutions
Introduction To Statistics And Data Analysis
Ch. 10.1 - Explain why the statement x=50 is not a legitimate...Ch. 10.1 - For the following pairs, indicate which do not...Ch. 10.1 - To determine whether the pipe welds in a nuclear...Ch. 10.1 - According to an article in Science Daily (Still No...Ch. 10.1 - A press release about a paper that appeared in The...Ch. 10.1 - CareerBuilder.com conducted a survey to learn...Ch. 10.1 - A national survey of 1012 adult Americans...Ch. 10.1 - A researcher speculates that because of...Ch. 10.1 - A county commissioner must vote on a resolution...Ch. 10.1 - A cruise ship charges passengers 3 for a can of...
Ch. 10.1 - The article Facebook Use and Academic Performance...Ch. 10.2 - Researchers at Bostons Childrens Hospital and...Ch. 10.2 - The paper Breast MRI as an Adjunct to Mammography...Ch. 10.2 - Medical personnel are required to report suspected...Ch. 10.2 - How accurate are DNA paternity tests? By comparing...Ch. 10.2 - A television manufacturer claims that (at least)...Ch. 10.2 - A manufacturer of hand-held calculators receives...Ch. 10.2 - Water specimens are taken from water used for...Ch. 10.2 - Suppose that for a particular hypothesis test, the...Ch. 10.2 - Suppose that you arc an inspector for the Fish and...Ch. 10.2 - The paper Living Near Nuclear Power Plants and...Ch. 10.2 - An automobile manufacturer is considering using...Ch. 10.3 - Use the definition of the P-value to explain the...Ch. 10.3 - For which of the following P-values will the null...Ch. 10.3 - Pairs of P-values and significance levels, , are...Ch. 10.3 - Pairs of P-values and significance levels are...Ch. 10.3 - Let p denote the proportion of students at a...Ch. 10.3 - Assuming a random sample from a large population,...Ch. 10.3 - In a survey conducted by CareerBuilder.com,...Ch. 10.3 - In a survey of 1000 women age 22 to 35 who work...Ch. 10.3 - The paper Debt Literacy, Financial Experiences and...Ch. 10.3 - Most Like it Hot is the title of a press release...Ch. 10.3 - In a survey of 1005 adult Americans, 46% indicated...Ch. 10.3 - The article Euthanasia Still Acceptable to Solid...Ch. 10.3 - The report Digital Democracy Survey (Deloitte...Ch. 10.3 - The article How to Block Nuisance Calls (The...Ch. 10.3 - The article Facebook Use and Academic Performance...Ch. 10.3 - The article Public Acceptability in the UK and the...Ch. 10.3 - The article Cops Get Screened for Digital Dirt...Ch. 10.3 - Refer back to the previous exercise. The actual...Ch. 10.3 - The report 2007 Electronic Monitoring ...Ch. 10.3 - The United States Elections Project...Ch. 10.4 - Give as much information as you can about the...Ch. 10.4 - Give as much information as you can about the...Ch. 10.4 - Give as much information as you can about the...Ch. 10.4 - Paint used to paint lines on roads must reflect...Ch. 10.4 - A certain pen has been designed so that actual...Ch. 10.4 - Prob. 48ECh. 10.4 - The paper Playing Active Video Games Increases...Ch. 10.4 - A study of fast-food intake is described in the...Ch. 10.4 - Refer to the study and hypothesis test of the...Ch. 10.4 - The report 2016 Salary Survey Executive Summary...Ch. 10.4 - The Economist collects data each year on the price...Ch. 10.4 - The report Majoring in Money: How American College...Ch. 10.4 - The authors of the paper Changes in Quantity,...Ch. 10.4 - Medical research has shown that repeated wrist...Ch. 10.4 - A comprehensive study conducted by the National...Ch. 10.4 - In a study of media use, each person in a large...Ch. 10.4 - Refer to the study description and sample...Ch. 10.4 - The paper titled Music for Pain Relief (The...Ch. 10.4 - Many consumers pay careful attention to stated...Ch. 10.4 - Much concern has been expressed regarding the...Ch. 10.5 - The power of a test is influenced by the sample...Ch. 10.5 - Water specimens are taken from water used for...Ch. 10.5 - Prob. 65ECh. 10.5 - Let denote the mean lifetime (in hours) for a...Ch. 10.5 - The city council in a large city has become...Ch. 10.5 - The amount of shaft wear after a fixed mileage was...Ch. 10.5 - Optical fibers are used in telecommunications to...Ch. 10.5 - Let denote the mean diameter for bearings of a...Ch. 10.5 - Use the information given in the previous exercise...Ch. 10.6 - In 2006, Boston Scientific sought approval for a...Ch. 10.6 - The article Boy or Girl: Which Gender Baby Would...Ch. 10.7 - We are only beginning to learn about the long-term...Ch. 10.7 - A study of hospitalized patients who develop...Ch. 10.7 - Prob. 76ECh. 10.7 - Prob. 77ECh. 10.7 - Prob. 78ECh. 10.7 - Prob. 79ECh. 10.8 - Prob. 80ECh. 10.8 - Prob. 81ECh. 10.8 - Prob. 83ECh. 10.8 - Prob. 84ECh. 10 - The report A Crisis in Civic Education (American...Ch. 10 - In a national survey of 2013 adults, 1590...Ch. 10 - Students at the Akademia Podlaka conducted an...Ch. 10 - Prob. 89CRCh. 10 - People in a random sample of 236 students enrolled...Ch. 10 - According to a large national survey conducted by...Ch. 10 - In a representative sample of adult Americans age...Ch. 10 - The article Facebook Use and Academic Performance...Ch. 10 - A number of initiatives on the topic of legalized...Ch. 10 - Duck hunting in populated areas faces opposition...Ch. 10 - Past experience has indicated that the response...Ch. 10 - An automobile manufacturer who wishes to advertise...Ch. 10 - A student organization uses the proceeds from a...Ch. 10 - A hot tub manufacturer advertises that with its...Ch. 10 - Prob. 1CRECh. 10 - Prob. 2CRECh. 10 - Prob. 3CRECh. 10 - Prob. 4CRECh. 10 - Prob. 5CRECh. 10 - The article Should Canada Allow Direct-to-Consumer...Ch. 10 - Prob. 7CRECh. 10 - It probably wouldnt surprise you to know that...Ch. 10 - The article Doctors Cite Burnout in Mistakes (San...Ch. 10 - The National Geographic Society conducted a study...Ch. 10 - Heinz Plays Catch-up After Under-Filling Ketchup...Ch. 10 - In a survey conducted by Yahoo Small Business,...Ch. 10 - In an AP-AOL sports poll (Associated Press,...Ch. 10 - The article titled 13% of Americans Dont Use the...Ch. 10 - A survey of teenagers and parents in Canada...Ch. 10 - The same survey referenced in the previous...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- A pathological video game user (PVGU) is a video game user that averages 31 or more hours a week of gameplay. According to the article “Pathological Video Game Use among Youths: A Two-Year Longitudinal Study” (Pediatrics, Vol. 127, No. 2, pp. 319–329) by D. Gentile et al., in 2011, about 9% of children in grades 3–8 were PVGUs. Suppose that, today, five youths in grades 3–8 are randomly selected. Let X represent the number of youths who are PVGUs. Calculate the probability that EXACTLY three youths are PVGUsarrow_forwardRecent incidents of food contamination have caused great concern among consumers. The article “How Safe Is That Chicken?” (Consumer Reports, Jan. 2010: 19–23) reported that 35 of 80 randomly selected Perdue brand broilers tested positively for either campylobacter or salmonella (or both), the leading bacterial causes of food-borne disease, whereas 66 of 80 Tyson brand broilers tested positive. If the true proportions of non-contaminated chickens for the Perdue and Tyson brands are .50 and .25, respectively, how likely is it that the null hypothesis of equal proportions will be rejected when a .01 significance level is used and the sample sizes are both 80?arrow_forwardAccording to a certain government agency for a large country, the proportion of fatal traffic accidents in the country in which the driver had a positive blood alcohol concentration (BAC) is 0.34. Suppose a random sample of 106 traffic fatalities in a certain region results in 48 that involved a positive BAC. Does the sample evidence suggest that the region has a higher proportion of traffic fatalities involving a positive BAC than the country at the a= 0.01 level of significance? .... Because npo (1- Po) =| 10, the sample size is 5% of the population size, and the sample the requirements for testing the hypothesis satisfied. (Round to one decimal place as needed.) What are the null and alternative hypotheses? versus H1: Ho: (Type integers or decimals. Do not round.) Find the test statistic, zo. Zo = (Round to two decimal places as needed.) Find the P-value. P-value = (Round to three decimal places as needed.) %3D Determine the conclusion for this hypothesis test. Choose the correct…arrow_forward
- A study was made of 1,057 cases of poisoning in children treated as inpatients at Milwaukee Children's Hospital from 1962 through 1968. Data on date of occurrence, age and sex of the child, and type of agent involved were recorded and analyzed by standard statistical methods. Poisoning was due to ingestion of aspirin in 35 per cent of the children studied and to the ingestion of hydrocarbon distillates in 18 per cent. A statistically significant male dominance was found for ingestion of hydrocarbons; age-specific peaks were found for some categories. Trends as to the relative and absolute frequencies of each specific poison from one year to the next were noted; possible reasons for increasing or decreasing trends are discussed. Is this study descriptive or inferential? Explain your answer. What are the variables used in the study? In your opinion, what level of measurement was used to obtain the data from the variables? Does the article define the population? If so, how is it…arrow_forwardThe Joint Commission on Accreditation of Healthcare Organizations mandated that hospitals ban smoking by 1994. To study the effects of this ban on smoking behaviors, subjects were randomly selected from two different populations: those from hospitals with the ban and those from hospitals without the ban. Investigators were interested in determining if this smoking ban had any impact on the proportion of smokers employed at each hospital that then quit smoking. Among 843 smoking employees of hospitals with the smoking ban, 56 quit smoking during the study period. Among 703 smoking employees from workplaces without the smoking ban, 27 quit smoking during the study period. Below is the Stata output that was run to determine if there was a statistically significant difference between these two proportions at the α=0.05 level. A. What is the estimate of the proportion of smokers from the hospitals that implemented the ban that quit smoking (the blank labeled "C" in the above output)?…arrow_forwardRosiglitazone is the active ingredient in the controversial type 2 diabetes medicine Avandia and has been linked to an increased risk of serious cardiovascular problems such as stroke, heart failure, and death. A common alternative treatment is pioglitazone, the active ingredient in a diabetes medicine called Actos. In a nationwide retrospective observational study of 22,757 Medicare beneficiaries aged 65 years or older, it was found that 259 of the 6,759 patients using rosiglitazone and 539 of the 15,998 using pioglitazone had serious cardiovascular problems. These data are summarized in the contingency table below. Rosiglitazone Pioglitazone Total Cardiovascular problems Yes No 259 539 a) Write a set of hypotheses comparing the rates for cardiovascular problems for the two treatments. Ho: Pr-Pp ? 8 HA: P-Pp? B Total 6,500 6,759 15,459 15,998 798 21,959 22,757 b) Compute the point estimate, the observed difference in rates for cardiovascular problems in the two treatments. Pr-Pp= c)…arrow_forward
- An experiment was conducted for better understanding of the effectiveness of a particular type of drug for reducing bad cholesterol (LDL) level. The purpose of the experiment was to determine whether different dosages used have significant different outcomes in average LDL reduction. Twenty subjects with LDL at around 250 to 300 mg/dL had participated in the study and were randomly divided into four groups. Each group was given a specific level of dosage of the drug each day for one month, with a control group that only provided with placebo. The reduction in LDL was recorded and showed in the following table. Positive number indicates reduction and negative numbers indicates increasing in DLD. Use statistical software to analyze the data and answer the following question. Control Light Dosage Level Medium Dosage Level Heavy Dosage Level 7 25 73 81 -3 17 60 71 6 22 55 79 5 21 41 60 15 12 36 85 Perform a One-way…arrow_forwardA recent study 41 compared 298 children with autism spectrum disorder to 1507 randomly selected control children without the disorder. Of the children with autism 20 of the mothers and used antidepressants drugs during the year before pregnancy or the first trimester of pregnancy. Of the control children, 50 of the mothers had used the drugs.a. is there a significant association between prenatal exposure to antidepressants medicine and the risk of autism?. Test whether tge results are significant at the 5%level. b.can we conclude that prenatal exposure antidepressants medicine increases the risk of autism in the child? why or why not? c. the article describing the study contains the sentence " No increase in risk was found for mothers with a history of mental health treatment in the absence of prenatal Exposure to selective serotonin reuptake inhibitors [antidepressants]. why did the researchers conduct this extra analysisarrow_forwardBenzene is a pollutant that, according to studies, can be associated with health problems. Benzene is found in air, water, and soil and comes from both industrial and natural sources. Benzene levels in indoor air are generally higher than outdoors. The main source of benzene in indoor air appears to be tobacco smoke, thus the combustion of tobacco is a major source of pollution. Benzene levels are measured in a random sample of 36 bars in a city, obtaining an average benzene level of 19.2 mg / m3, with a standard deviation of 2.1 mg / m3. Estimate the mean benzene level in bars in this city using a 95% confidence interval. (do your calculations to 4 decimal places) (need the process can be by hand ,Excel or R.) a)Other solution b)[18.48946, 19.91054] c)[19.0950, 19.3050] d)[18.5140, 19.8859] e)[18.6243, 19.7757] f)[18.4315, 19.7936]arrow_forward
- The Joint Commission on Accreditation of Healthcare Organizations mandated that hospitals ban smoking by 1994. To study the effects of this ban on smoking behaviors, subjects were randomly selected from two different populations: those from hospitals with the ban and those from hospitals without the ban. Investigators were interested in determining if this smoking ban had any impact on the proportion of smokers employed at each hospital that then quit smoking. Let px be the proportion of smokers from hospitals that implemented the ban who quit smoking during the study period. Let py be the proportions of smokers from hospitals without the ban who quit smoking during the study period. Please select the appropriate hypotheses. H0: px = 0.50 HA: px ≠ 0.50 H0: px-py ≥ 0 HA: px-py H0: px-py ≤ 0 HA: px-py > 0 H0: px-py = 0 HA: px-py ≠ 0arrow_forwardAccording to a certain government agency for a large country, the proportion of fatal traffic accidents in the country in which the driver had a positive blood alcohol concentration (BAC) is 0.35. Suppose a random sample of 106 traffic fatalities in a certain region results in 50 that involved a positive BAC. Does the sample evidence suggest that the region has a higher proportion of traffic fatalities involving a positive BAC than the country at the a = 0.01 level of significance? Because npo (1- Po) 10, the sample size is 5% of the population size, and the sample the requirements for testing the hypothesis satisfied. (Round to one decimal place as needed.)arrow_forwardKava is a beverage or extract that is made from Piper methysticum, a plant native to the western Pacific islands. Suppose that, in a randomized comparative experiment to determine if taking kava daily can reduce insomnia, a group of participants with insomnia were randomly assigned to take kava (treatment group) or a placebo (control group). After six weeks, the participants were interviewed to see if they experienced a decrease in insomnia. The table shows the results from the sample. The counts are the number of people in each group who experienced a decrease in insomnia. Group Description Population proportion Sample size Sample count Sample proportion 1 Treatment (kava) P1 n₁ = 402 x1 = 213 P₁ = 0.5299 2 Control (placebo) P2 n₂ = 521 x₂ = 121 P2 = 0.2322 Compute the standard error estimate, SE, of the difference in the sample proportions. Give your answer to at least four decimal places. 0.0438 SE = Incorrect Determine the value of the two-sample z-statistic for the difference in…arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Holt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGAL
Holt Mcdougal Larson Pre-algebra: Student Edition...
Algebra
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Hypothesis Testing using Confidence Interval Approach; Author: BUM2413 Applied Statistics UMP;https://www.youtube.com/watch?v=Hq1l3e9pLyY;License: Standard YouTube License, CC-BY
Hypothesis Testing - Difference of Two Means - Student's -Distribution & Normal Distribution; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=UcZwyzwWU7o;License: Standard Youtube License