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Concept explainers
To calculate mean, median, mode, rangeand standard deviation after multiplying the given constant.
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Answer to Problem 13PPS
Mean is 28.6.
Median is 27.2.
Mode is 29.6.
Standard deviation is 3.47
Range is10.4
Explanation of Solution
Given information:
Frequency: 33,37,38,29,35,37,27,40,28,31
Constant to be multiplied= 0.8
Formula used:Mean formula is,
ˉX=∑fXN
Where, f is frequency
N is total number of items
X is item.
Median formula is,
median=(n2)thterm+(n2+1)thterm2
Where, N cumulative frequency
Mode is the item with the maximum frequency.
Standard deviation is,
SD=√∑(x−ˉx)2n
Where, SD= standard deviation,
x = value
The Range is the difference between the lowest and highest values.
Calculation:
According to question,
Multiplying 0.8 to all the frequency values,
New frequency:
26.4,29.6,30.4,23.2,28,29.6,21.6,32,22.4,24.8
Sorting the frequency
21.6, 22.4, 23.2, 24.8, 26.4, 28, 29.6, 29.6, 30.4,32
For Mean,
Substituting the values in mean formula,
=26.4+29.6+30.4+23.2+28+29.6+21.6+32+22.4+24.810
So,
=28610
On solving,
=28.6
Hence, Mean is 28.6
For median,
Substituting values,
=(102)thterm+(102+1)thterm2
On solving,
=(5)thterm+(6)thterm2
Substituting the values,
=26.4+282
On solving,
=27.2
Hence, Median is 27.2.
For mode,
Mode is the item with the maximum frequency which is 29.6.
For standard deviation,
Substituting values,
SD=√(21.6−28.6)2+(22.4−28.6)2+(23.2−28.6)2+(24.8−28.6)2+(26.4−28.6)2+(28−28.6)2+(29.6−28.6)2+(29.6−28.6)2+(30.4−28.6)2+(32−28.6)210
So,
SD=√(−5.2)2+(−4.4)2+(−3.6)2+(−2)2+(−0.4)2+(1.2)2+(2.8)2+(2.8)2+(−3.6)2+(5.2)210
On solving,
SD=3.473
Hence, Standard deviation is 3.473
For Range,
Range is the difference between the lowest and highest values.
range=max−min
Substituting values,
=32−21.6
On solving,
=10.4
Hence, range is 10.4
Chapter 10 Solutions
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
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