Concept explainers
To calculate minimum, lower quartile, median, upper quartile and maximum
Answer to Problem 5PPS
Median is 73, lower quartile is 66, upper quartile is 82, minimum is 62and maximum is 99
Explanation of Solution
Given information:
City art museum’s annual gala event attendance for last 9 years,
68, 99, 73, 65, 67, 62, 80, 81, 83.
Formula used:
Median is,
Lower quartile is,
Upper quartile is,
Minimum is the smallest value of the data set.
Maximum is the largest value of the data set.
Calculation:
Arranging the data in an ascending order,
62, 65, 67, 68, 73, 80, 81, 83, 99
For median,
Substituting the values in median formula,
So,
On solving,
Substituting the value.
Hence, median is 73
For lower quartile,
Substituting the values in lower quartile formula,
So,
On solving,
Calculating the average of 2nd and 3rd observation. Substituting the value of 2nd and 3rd observation,
So,
On solving,
Hence, Lower quartile is 66
For upper quartile,
Substituting the values in lower quartile formula,
So,
On solving,
Hence, substituting the value of 7th and 8th observations,
So,
On solving,
Hence, Upper quartile is 82
Minimum is the smallest value of the data set. Substituting the value,
Hence, minimum is 62
Maximum is the largest value of the data set. Substituting the value,
Hence, maximum is 99.
Chapter 10 Solutions
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
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