APPLIED STAT.IN BUS.+ECONOMICS
6th Edition
ISBN: 9781259957598
Author: DOANE
Publisher: RENT MCG
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 10, Problem 83CE
In preliminary tests of a vaccine that may help smokers quit by reducing the “rush” from tobacco, 64 subjects who wanted to quit smoking were given either a placebo or the vaccine. Of the 32 in the placebo group, only 3 quit smoking for 30 days (the U.S. Food and Drug Administration’s criterion for smoking cessation) compared with 11 for the vaccine group. (a) Assuming equal sample sizes, find the 95 percent confidence interval for the difference in proportions. What does it suggest? (b) Why is the
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The typical reaction of asthmatics to eating food containing sulfites is a sudden increase in asthma symptoms. Studies are performed to estimate the percentage of the nation's 10 million asthmatics who are allergic to sulfites. In one survey, 38 of 500 randomly selected U.S. asthmatics were found to be allergic to sulfites. Using the One-Proportion z-Interval Procedure, find a 90% confidence interval for the proportion p of all U.S. asthatics who are allergic to sulfites and interpret your results.
For an ANOVA comparing three treatment conditions, what is stated by alternate hypothesis (H1)?
a. There are no differences between any of the population means.
b. At least one of the three population means is different from another mean.
c. All three of the population means are different from each other.
d. None of the other choices is correct
In an engineering class, students want to determine the difference in the mean strength between two different types of building materials—Type A, which is relatively inexpensive, and Type B, which is slightly more expensive. The students take a random sample of 60 of the Type A building material and a random sample of 27 of the Type B building material. Given the mean strength for each sample, the students construct a 95% confidence interval for the difference in population means.
(a) Determine the degrees of freedom for the conservative approach for finding the t critical value.
(b) Find the t critical value associated with 95% confidence. (Use a table or SALT. Round your answer to two decimal places.)
Chapter 10 Solutions
APPLIED STAT.IN BUS.+ECONOMICS
Ch. 10.2 - Do a two-sample test for equality of means...Ch. 10.2 - Repeat the previous exercise, assuming unequal...Ch. 10.2 - Is there a difference in the average number of...Ch. 10.2 - Prob. 4SECh. 10.2 - Prob. 5SECh. 10.2 - Prob. 6SECh. 10.2 - Prob. 7SECh. 10.2 - On a random basis, Bob buys a small take-out...Ch. 10.2 - For a marketing class term project, Bob is...Ch. 10.3 - A special bumper was installed on selected...
Ch. 10.3 - In trials of an experimental internet-based method...Ch. 10.3 - Construct a 95 percent confidence interval for the...Ch. 10.4 - (a) At = .05, does the following sample show that...Ch. 10.4 - An experimental surgical procedure is being...Ch. 10.4 - Blue Box is testing a new half price on Tuesday...Ch. 10.4 - The U.S. governments Cash for Clunkers program...Ch. 10.4 - Prob. 17SECh. 10.4 - Below is a random sample of shoe sizes for 12...Ch. 10.4 - A newly installed automatic gate system was being...Ch. 10.5 - Calculate the test statistic and p-value for a...Ch. 10.5 - Prob. 21SECh. 10.5 - Prob. 22SECh. 10.5 - Prob. 23SECh. 10.5 - Prob. 24SECh. 10.5 - Prob. 25SECh. 10.5 - A survey of 100 mayonnaise purchasers showed that...Ch. 10.5 - Prob. 27SECh. 10.5 - Prob. 28SECh. 10.5 - When tested for compliance with Sarbanes-Oxley...Ch. 10.5 - Prob. 30SECh. 10.5 - From a telephone log, an executive finds that 36...Ch. 10.5 - Prob. 32SECh. 10.6 - The American Bankers Association reported that, in...Ch. 10.6 - A study showed that 36 of 72 cell phone users with...Ch. 10.6 - Prob. 35SECh. 10.7 - Which samples show unequal variances? Use = .10...Ch. 10.7 - Prob. 37SECh. 10.7 - Prob. 38SECh. 10.7 - A manufacturing process drills holes in sheet...Ch. 10.7 - Examine the data below showing the weights (in...Ch. 10 - (a) Explain why two samples from the same...Ch. 10 - (a) In a two-sample test of proportions, what is a...Ch. 10 - List the three cases for a test comparing two...Ch. 10 - Consider Case 1 (known variances) in the test...Ch. 10 - Consider Case 2 (unknown but equal variances) in...Ch. 10 - Consider Case 3 (unknown and unequal variances) in...Ch. 10 - Why is it a good idea to use a computer program...Ch. 10 - (a) Explain why the paired t test for dependent...Ch. 10 - Explain how a difference in means could be...Ch. 10 - (a) Why do we use an F test? (b) When two...Ch. 10 - (a) In an F test for two variances, explain how to...Ch. 10 - Prob. 41CECh. 10 - In an early home game, an NBA team made 66 of...Ch. 10 - Prob. 43CECh. 10 - A recent study found that 202 women held board...Ch. 10 - A study of the Fortune 100 board of director...Ch. 10 - Prob. 46CECh. 10 - How many full-page advertisements are found in a...Ch. 10 - eShopNet, an online clothing retailer, is testing...Ch. 10 - After John F. Kennedy Jr. was killed in an...Ch. 10 - A ski company in Vail owns two ski shops, one on...Ch. 10 - At a University of Colorado womens home basketball...Ch. 10 - A ski resort tracks the proportion of seasonal...Ch. 10 - Does a follow-up reminder increase the renewal...Ch. 10 - A study revealed that the 30-day readmission rate...Ch. 10 - In a marketing class, 44 student members of...Ch. 10 - In San Francisco, a sample of 3,200 wireless...Ch. 10 - Prob. 57CECh. 10 - Prob. 58CECh. 10 - Prob. 59CECh. 10 - Prob. 60CECh. 10 - Prob. 61CECh. 10 - Prob. 62CECh. 10 - In a 15-day survey of air pollution in two...Ch. 10 - Prob. 64CECh. 10 - Do male and female school superintendents earn the...Ch. 10 - The average take-out order size for Ashoka Curry...Ch. 10 - Cash withdrawals from a college credit union for a...Ch. 10 - In Mini Case 10.2, we found that the mean methane...Ch. 10 - A ski company in Vail owns two ski shops, one on...Ch. 10 - A ski company in Vail owns two ski shops, one on...Ch. 10 - Emergency room arrivals in a large hospital showed...Ch. 10 - Concerned about graffiti, mayors of nine suburban...Ch. 10 - A certain company will purchase the house of any...Ch. 10 - Nine homes are chosen at random from real estate...Ch. 10 - Prob. 75CECh. 10 - Prob. 76CECh. 10 - Prob. 77CECh. 10 - Is there a difference between the variance in ages...Ch. 10 - A survey of 100 mayonnaise purchasers showed that...Ch. 10 - A 20-minute consumer survey mailed to 500 adults...Ch. 10 - One group of accounting students used simulation...Ch. 10 - Advertisers fear that users of DVRs (digital video...Ch. 10 - In preliminary tests of a vaccine that may help...Ch. 10 - Prob. 84CECh. 10 - Male and female students in a finance class were...Ch. 10 - Prob. 86CECh. 10 - A retailer compared the frequency of customer...Ch. 10 - Streeling University surveyed a random sample of...Ch. 10 - The Fischer Theatre compared attendance at its...Ch. 10 - Random samples of tires being replaced by a car...Ch. 10 - Count the number of two-door vehicles among 50...Ch. 10 - Which statement is not correct? Explain. a. The...Ch. 10 - Match each statement to the correct property of an...Ch. 10 - Concerning confidence intervals, which statement...Ch. 10 - Prob. 4ERQCh. 10 - Prob. 5ERQCh. 10 - Prob. 6ERQCh. 10 - Prob. 7ERQCh. 10 - Prob. 8ERQCh. 10 - The process that produces Sonora Bars (a type of...Ch. 10 - Prob. 10ERQCh. 10 - Prob. 11ERQCh. 10 - Last month, 85 percent of the visitors to the...Ch. 10 - Weights of 12 randomly chosen Sonora Bars (a type...Ch. 10 - In a random sample of 200 Colorado residents, 150...Ch. 10 - Five students in a large lecture class compared...Ch. 10 - Prob. 16ERQCh. 10 - Prob. 17ERQ
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- What is an experiment?arrow_forwardIn an August 2012 Gallup survey of 1,012 randomly selected U.S. adults (age 18 and over), 53% said that they were unhappy with the quality of education students receive in kindergarten through grade 12. Suppose you want to estimate the proportion of local adults who are unhappy with the education students receive in kindergarten through grade 12 with 95% confidence and a 5% margin of error. If you suspect that local adults won't differ drastically from those Gallup used, how many people should you sample? 4 80 125 382 383arrow_forwardA hospital reported that the normal death rate for patients with extensive burns (more than 40% of skin area) has been significantly reduced by the use of new fluid plasma compresses. Before the new treatment, the mortality rate for extensive burn patients was about 60%. Using the new compresses, the hospital found that only 42 of 89 patients with extensive burns died. Use a 1% level of significance to test the claim that the mortality rate has dropped. What are we testing in this problem? single proportionsingle mean (a) What is the level of significance? State the null and alternate hypotheses. H0: p = 0.6; H1: p ≠ 0.6 H0: μ = 0.6; H1: μ ≠ 0.6 H0: μ = 0.6; H1: μ < 0.6 H0: μ = 0.6; H1: μ > 0.6 H0: p = 0.6; H1: p < 0.6 H0: p = 0.6; H1: p > 0.6 (b) What sampling distribution will you use? What assumptions are you making? The standard normal, since np > 5 and nq > 5. The Student's t, since np < 5 and nq < 5. The Student's t, since np > 5 and nq…arrow_forward
- A hospital reported that the normal death rate for patients with extensive burns (more than 40% of skin area) has been significantly reduced by the use of new fluid plasma compresses. Before the new treatment, the mortality rate for extensive burn patients was about 60%. Using the new compresses, the hospital found that only 42 of 89 patients with extensive burns died. Use a 1% level of significance to test the claim that the mortality rate has dropped. What are we testing in this problem? single proportionsingle mean (a) What is the level of significance?State the null and alternate hypotheses. H0: ? = 0.6; H1: ? < 0.6H0: p = 0.6; H1: p ≠ 0.6 H0: p = 0.6; H1: p < 0.6H0: ? = 0.6; H1: ? > 0.6H0: p = 0.6; H1: p > 0.6H0: ? = 0.6; H1: ? ≠ 0.6 (b) What sampling distribution will you use? What assumptions are you making? The Student's t, since np < 5 and nq < 5.The standard normal, since np < 5 and nq < 5. The Student's t, since np > 5 and nq >…arrow_forwardA manufacturing manager reports to the CEO that 5% of products that come off the assembly line are defective. A study is performed to investigate this claim. In a random sample of 250 products that come off the assembly line, 14 are found to be defective. The CEO wants to know if the data provide convincing evidence that the true proportion of defective products differs from 0.05. Are the conditions for inference met? Yes, the conditions for inference are met. No, the 10% condition is not met. No, the Large Counts Condition is not met. No, the randomness condition is not met.arrow_forwardA study investigated the effectiveness of meditation training in reducing trait anxiety. The study evaluated subjects trait anxiety levels before and after the study subjects participated in an 8 week training course in meditation. The difference in the pre-training and post-training trait anxiety levels were calculated for each participant. For the 27 people in the study, the mean reduction in anxiety was 4.7, and the standard deviation of the reductions was 6.8. In USE SALT (a) Find a 99% confidence interval for the population mean. (Round your answers to one decimal place.) to (b) Draw a picture similar to Figure 11.9 illustrating the confidence intervals you found in part (a). On the basis of the interval that you found in part (a) and/or the picture you drew, what can you conclude about the population mean reduction in anxiety? In the graph, the lower bound is ---Select--- 0 and the upper bound of the interval is ---Select--- 0. Therefore, we ---Select--- v conclude that the…arrow_forward
- According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this percent is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. Suppose we want to calculate a 99% confidence interval for the difference between the proportions of Californians and Oregonians who are sleepdeprived. 1. State the critical value for the interval (3 decimal places): 2. State the difference between the sample proportions, POregon-PCalifornia (3 decimal places): 3. State the standard error of the difference between the proportions (3 decimal places): 4. State the confidence interval being sure to use proper notation (3 decimal places each):arrow_forwardA company manufacturing some medicine tablets with the Average weight of 500 mg and population variance of 36 mg. A quality officer in a company wants to investigate whether the weight of Paracetamol tablets is differed from 500 mg. To investigate He taken 50 tablets at the time of manufacturing and find that the average weight of 50 tablets is 504.5 mg. Make the hypothesis test that the average weight of tablets is differ from or not at 95% confidence level. INSTRUCTIONS:You can perform this exercise in Minitab? the exercise is already solved! But I just want to see how to do it in Minitab, please! Note: the exercise is already solved! as seen in the image I attached, I just want to see it solved in minitab! (with pictures, or sreenshots) however, but I want to see the procedure :)arrow_forwardWhite blood cell counts are helpful for assessing liver disease, radiation, bone marrow failure, and infectious diseases. Listed below are white blood cell counts found in a simple random sample of men and women (based on data from the Third National Health and Nutrition Examination Survey). Set up your data file so Female = 2; Male = 1. Using a .01 significance level, test the claim that men and women have different white blood cell counts. Based on the 95% confidence interval, what conclusions can be drawn about the mean difference between men and women? Female: 8.9 6.5 9.45 9.65 6.4 5.15 16.6 5.75 11.6 5.90 9.30 8.55 10.8 4.85 4.90 8.75 6.90 9.75 4.05 9.05 5.05 6.4 4.05 7.60 4.95 3.00 9.10 Male 5.25 5.95 10.05 5.45 5.30 5.55 6.85 6.65 6.3 6.40…arrow_forward
- A researcher wishes to determine whether people with high blood presssure can lower their blood pressure by performing yoga exercises. A treatment group and a control group are selected. The sample statistics are given below. Construct a 90% confidence interval for the difference between the two population means, u1-u2. Would you recommend using yoga exercises? Treatment Group n1= 100 x= 178 s1=35 Control Group n2= 100 x2= 193 s2= 37arrow_forwardIt is hard to persuade consumers to abandon a product with which they are familiar. One experiment gave consumers free samples of new laundry detergent and also a standard detergent. After some time, ask the subjects which detergent they prefer. Here are the data. User Nonuser Prefer new product 19 31 Prefer standard product 29 27 a. Calculate a 90% confidence interval for the difference in proportions between nonusers and users of the standard detergent that prefer the new detergent. b. Based on the confidence interval in (a), can we conclude that a significant difference exists between the proportion of nonusers of the standard detergent who prefer the new detergent and the proportion of users of the standard detergent who prefer the new detergent? Explain.arrow_forwardComparison between two diets in obese children, one low-fat and one low-carb 8 week intervention with the outcome of weight loss. Based on a similar study in adults, 20% of the children will not complete the study. For a 95% confidence interval with a margin of error of no more than 3 lbs., how many children should be recruited? In the adult trial, the low-fat and low-carb groups had a standard deviations of 8.4 and 7.7, respectively and each group had 100 participants. A. Calculate the pooled standard deviation (Sp). B. Calculate the number of children will need to be recruited for the trial if all finish the study use the Sp calculated for the standard deviation? C. How many children would be needed to account for 20% attrition.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill
College Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage Learning
Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill
College Algebra (MindTap Course List)
Algebra
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:Cengage Learning
Introduction to experimental design and analysis of variance (ANOVA); Author: Dr. Bharatendra Rai;https://www.youtube.com/watch?v=vSFo1MwLoxU;License: Standard YouTube License, CC-BY