Understanding Our Universe
Understanding Our Universe
3rd Edition
ISBN: 9780393614428
Author: PALEN, Stacy, Kay, Laura, Blumenthal, George (george Ray)
Publisher: W.w. Norton & Company,
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Chapter 10, Problem 33QAP

(a)

To determine

The reason why star 2 has a smaller orbit than star 1.

(b)

To determine

The sketch of binary star system for case when star 1 has a very low mass.

(c)

To determine

The sketch of binary star system for case when mass of star 1 and star 2 is equal.

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The Algol binary system consists of a 3.7 Msun star and a 0.8 Msun star with an orbital period of 2.87 days.  Using Newton’s version of Kepler’s Third Law, calculate the distance, a, between the two stars.  Compare that to the size of Betelgeuse (you’ll need to look that up).   Newton’s Version of Kepler’s Law:    (M1 + M2) P2 = (4p2 /G) a3                     Rearrange the equation to solve for a. Pi, p, is equal to 3.14. IMPORTANT NOTE: Google the value of G (the Universal Gravitational Constant) or look it up in your text.  NOTICE THE UNITS.  You must convert every distance and time in your equation to the same units, otherwise, you’ll get an incorrect answer.  That means you must convert distances to meters, solar masses to kilograms, and time to seconds.   When you compare your value to the size of Betelgeuse, it will also help that they are in the same units.
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(Astronomy) Binary Pulsar. Part A: Use the orbital period 27 min for the binary pulsar (two neutron stars orbit each other) to find the orbital separation of the pair in AU and solar radii. Assume a neutron star's mass is 3 solar masses. (Hints: Use the version of Kepler's third law for binary stars.) Part B: Is this system orbiting closer or further than Mercury is to the Sun?
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