General, Organic, and Biological Chemistry - 4th edition
General, Organic, and Biological Chemistry - 4th edition
4th Edition
ISBN: 9781259883989
Author: by Janice Smith
Publisher: McGraw-Hill Education
Question
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Chapter 10, Problem 22P
Interpretation Introduction

(a)

Interpretation:

The following table of isotopes should be completed:

  General, Organic, and Biological Chemistry - 4th edition, Chapter 10, Problem 22P , additional homework tip  1

Concept Introduction:

Isotopes are the compounds having the same atomic number but different atomic mass.

To write an isotope symbol atomic number (Z) is written on the lower left side and atomic mass (A) is written on the upper left side of an element.

Expert Solution
Check Mark

Answer to Problem 22P

The complete table for isotopes symbol is represented as follows:

Atomic number(Z)Mass number(A)Number of protonsNumber of neutronsIsotope symbol
Sodium-2411241113
1124Na

Explanation of Solution

The atomic number is equal to the number of protons in an element.

Mass number = Number of protons + Number of neutrons

The atomic number for sodium is 11 and the mass number is 24.

Since atomic number = number of protons

Thus, the number of protons in sodium is 11 and the number of neutrons in sodium can be calculated by simply subtracting the number of protons from the mass number as follows:

  Mass number = Number of protons + Number of neutrons24=11+ Number of neutronsNumber of neutrons=2411=13

Therefore, the isotope symbol for Sodium is 1124Na.

Interpretation Introduction

(b)

Interpretation:

The following table of isotopes should be completed:

  General, Organic, and Biological Chemistry - 4th edition, Chapter 10, Problem 22P , additional homework tip  2

Concept Introduction:

Isotopes are the compounds having the same atomic number but different atomic mass.

To write an isotope symbol atomic number (Z) is written on the lower left side and atomic mass (A) is written on the upper left side of an element.

Expert Solution
Check Mark

Answer to Problem 22P

The complete table for isotopes symbol is represented as follows:

Atomic number(Z)Mass number(A)Number of protonsNumber of neutronsIsotope symbol
b. Strotium-8938893851
3889Sr

Explanation of Solution

The formula to determine the mass number is:

  Mass number = Number of protons + Number of neutrons

Rearranging:

  Number of protons = Mass number Number of neutrons

Substituting the values:

  Number of protons = 89 51Number of protons = 38

Since atomic number = number of protons

Thus, the element with atomic number 38 is strontium, Sr.

Therefore, the isotope symbol for strontium is 3889Sr.

Interpretation Introduction

(c)

Interpretation:

The following table of isotopes should be completed:

  General, Organic, and Biological Chemistry - 4th edition, Chapter 10, Problem 22P , additional homework tip  3

Concept Introduction:

Isotopes are the compounds having the same atomic number but different atomic mass.

To write an isotope symbol atomic number(Z) is written on the lower left side and atomic mass(A) is written on the upper left side of an element.

Expert Solution
Check Mark

Answer to Problem 22P

The complete table for isotopes symbol is represented as follows:

Atomic number(Z)Mass number(A)Number of protonsNumber of neutronsIsotope symbol
c. Iron-5926592633
2659Fe

Explanation of Solution

The mass number of element is 59.

Since atomic number = number of protons

So, the atomic number of the isotope is 26 thus, the element is iron, Fe.

Thus, the number of protons for this element is 26 and the number of neutrons in iron can be calculated by simply subtracting the number of protons from the mass number as follows:

  Mass number = Number of protons + Number of neutrons59=26+ Number of neutronsNumber of neutrons=5926=33

Therefore, the isotope symbol for iron is 2659Fe.

Interpretation Introduction

(d)

Interpretation:

The following table of isotopes should be completed:

  General, Organic, and Biological Chemistry - 4th edition, Chapter 10, Problem 22P , additional homework tip  4

Concept Introduction:

Isotopes are the compounds having the same atomic number but different atomic mass.

To write an isotope symbol atomic number(Z) is written on the lower left side and atomic mass(A) is written on the upper left side of an element.

Expert Solution
Check Mark

Answer to Problem 22P

The complete table for isotopes symbol is represented as follows:

Atomic number(Z)Mass number(A)Number of protonsNumber of neutronsIsotope symbol
d.Samarium-153621536291
62153Sm

Explanation of Solution

The mass number of element is 153.

The atomic number of samarium is 62.

Since atomic number = number of protons

Thus, the number of protons for this element is 62 and the number of neutrons in samarium can be calculated by simply subtracting the number of protons from the mass number as follows:

  Mass number = Number of protons + Number of neutrons153=62+ Number of neutronsNumber of neutrons=15362=91

Therefore, the isotope symbol for Samarium is 62153Sm.

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Chapter 10 Solutions

General, Organic, and Biological Chemistry - 4th edition

Ch. 10.2 - Prob. 10.3PPCh. 10.2 - Prob. 10.9PCh. 10.2 - Prob. 10.10PCh. 10.2 - Prob. 10.11PCh. 10.3 - Prob. 10.4PPCh. 10.3 - Prob. 10.12PCh. 10.3 - Prob. 10.13PCh. 10.3 - Prob. 10.14PCh. 10.4 - To treat a thyroid tumor, a patient must be given...Ch. 10.4 - A sample of iodine-131 (t1/2=8.0 days) has an...Ch. 10.4 - Prob. 10.15PCh. 10.5 - Prob. 10.16PCh. 10.5 - Prob. 10.17PCh. 10.5 - Prob. 10.18PCh. 10.6 - Prob. 10.7PPCh. 10.6 - Prob. 10.8PPCh. 10 - Prob. 19PCh. 10 - Prob. 20PCh. 10 - Prob. 21PCh. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - Prob. 24PCh. 10 - Prob. 25PCh. 10 - Prob. 26PCh. 10 - Prob. 27PCh. 10 - Prob. 28PCh. 10 - Prob. 29PCh. 10 - Prob. 30PCh. 10 - Prob. 31PCh. 10 - Prob. 32PCh. 10 - Prob. 33PCh. 10 - Prob. 34PCh. 10 - Prob. 35PCh. 10 - Prob. 36PCh. 10 - Prob. 37PCh. 10 - Prob. 38PCh. 10 - Prob. 39PCh. 10 - Prob. 40PCh. 10 - Prob. 41PCh. 10 - Prob. 42PCh. 10 - Prob. 43PCh. 10 - Prob. 44PCh. 10 - Prob. 45PCh. 10 - Prob. 46PCh. 10 - Prob. 47PCh. 10 - Prob. 48PCh. 10 - Prob. 49PCh. 10 - Prob. 50PCh. 10 - Prob. 51PCh. 10 - Prob. 52PCh. 10 - Prob. 53PCh. 10 - Prob. 54PCh. 10 - Prob. 55PCh. 10 - Prob. 56PCh. 10 - Prob. 57PCh. 10 - Prob. 58PCh. 10 - Prob. 59PCh. 10 - Prob. 60PCh. 10 - Prob. 61PCh. 10 - Prob. 62PCh. 10 - Prob. 63PCh. 10 - Prob. 64PCh. 10 - Prob. 65PCh. 10 - Prob. 66PCh. 10 - Prob. 67PCh. 10 - Prob. 68PCh. 10 - Prob. 69PCh. 10 - Prob. 70PCh. 10 - Prob. 71PCh. 10 - Prob. 72PCh. 10 - Prob. 73PCh. 10 - Prob. 74PCh. 10 - Prob. 75PCh. 10 - Prob. 76PCh. 10 - Prob. 77PCh. 10 - Prob. 78PCh. 10 - Prob. 79PCh. 10 - Prob. 80PCh. 10 - Prob. 81PCh. 10 - Prob. 82PCh. 10 - Prob. 83PCh. 10 - Prob. 84PCh. 10 - Prob. 85PCh. 10 - Prob. 86PCh. 10 - Prob. 87PCh. 10 - Prob. 88PCh. 10 - Prob. 89CPCh. 10 - Prob. 90CP
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