Explanation: The formula used for calculating the bandwidth-delay product is R × d prop The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is d prop = m s seconds. Substitute, “20,000” for “m” and “2.5 ×10 8 ” for “s” The propagation delay of the link is 20000 × 10 3 2

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Answer 1

Expert Solution & Answer

Chapter 1, Problem P25P

a.

Explanation of Solution

The formula used for calculating the bandwidth-delay product is $R × dprop$

The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is $dprop = ms$ seconds.

Substitute, “20,000” for “m” and “2.5 ×10⁸” for “s”

The propagation delay of the link is $20000 × 1032$

b.

Explanation of Solution

The size of the file transmitted from Host A to Host B is 800,000 bits...

c.

Explanation of Solution

The bandwidth-delay produ...

d.

Explanation of Solution

“Yes” the width of the link is longer than the football field.

Reason:

The formula used for calculating the width of a bit present on the link is as follows

$Width of the bit = Length of the linkbandwidth-delay product$

The formula used for calculating the bandwidth-delay product is $R × dprop$

The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is $dprop = ms$ seconds.

Substitute, “20,000” for “m” and “2.5 ×10⁸” for “s”

The propagation delay of the link is $20000 × 1032.5 × 108 = 0$

e.

Explanation of Solution

The expression used for calculating the width of a bit in the link and length of the required link in t...

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Answer 2

Expert Solution & Answer

Chapter 1, Problem P25P

a.

Explanation of Solution

The formula used for calculating the bandwidth-delay product is $R × dprop$

The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is $dprop = ms$ seconds.

Substitute, “20,000” for “m” and “2.5 ×10⁸” for “s”

The propagation delay of the link is $20000 × 1032$

b.

Explanation of Solution

The size of the file transmitted from Host A to Host B is 800,000 bits...

c.

Explanation of Solution

The bandwidth-delay produ...

d.

Explanation of Solution

“Yes” the width of the link is longer than the football field.

Reason:

The formula used for calculating the width of a bit present on the link is as follows

$Width of the bit = Length of the linkbandwidth-delay product$

The formula used for calculating the bandwidth-delay product is $R × dprop$

The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is $dprop = ms$ seconds.

Substitute, “20,000” for “m” and “2.5 ×10⁸” for “s”

The propagation delay of the link is $20000 × 1032.5 × 108 = 0$

e.

Explanation of Solution

The expression used for calculating the width of a bit in the link and length of the required link in t...

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Expert Solution & Answer

Chapter 1, Problem P25P

a.

Explanation of Solution

The formula used for calculating the bandwidth-delay product is $R × dprop$

The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is $dprop = ms$ seconds.

Substitute, “20,000” for “m” and “2.5 ×10⁸” for “s”

The propagation delay of the link is $20000 × 1032$

b.

Explanation of Solution

The size of the file transmitted from Host A to Host B is 800,000 bits...

c.

Explanation of Solution

The bandwidth-delay produ...

d.

Explanation of Solution

“Yes” the width of the link is longer than the football field.

Reason:

The formula used for calculating the width of a bit present on the link is as follows

$Width of the bit = Length of the linkbandwidth-delay product$

The formula used for calculating the bandwidth-delay product is $R × dprop$

The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is $dprop = ms$ seconds.

Substitute, “20,000” for “m” and “2.5 ×10⁸” for “s”

The propagation delay of the link is $20000 × 1032.5 × 108 = 0$

e.

Explanation of Solution

The expression used for calculating the width of a bit in the link and length of the required link in t...

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 1, Problem P25P

a.

Explanation of Solution

The formula used for calculating the bandwidth-delay product is $R × dprop$

The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is $dprop = ms$ seconds.

Substitute, “20,000” for “m” and “2.5 ×10⁸” for “s”

The propagation delay of the link is $20000 × 1032$

b.

Explanation of Solution

The size of the file transmitted from Host A to Host B is 800,000 bits...

c.

Explanation of Solution

The bandwidth-delay produ...

d.

Explanation of Solution

“Yes” the width of the link is longer than the football field.

Reason:

The formula used for calculating the width of a bit present on the link is as follows

$Width of the bit = Length of the linkbandwidth-delay product$

The formula used for calculating the bandwidth-delay product is $R × dprop$

The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is $dprop = ms$ seconds.

Substitute, “20,000” for “m” and “2.5 ×10⁸” for “s”

The propagation delay of the link is $20000 × 1032.5 × 108 = 0$

e.

Explanation of Solution

The expression used for calculating the width of a bit in the link and length of the required link in t...

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 1, Problem P25P

a.

Explanation of Solution

The formula used for calculating the bandwidth-delay product is $R × dprop$

The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is $dprop = ms$ seconds.

Substitute, “20,000” for “m” and “2.5 ×10⁸” for “s”

The propagation delay of the link is $20000 × 1032$

b.

Explanation of Solution

The size of the file transmitted from Host A to Host B is 800,000 bits...

c.

Explanation of Solution

The bandwidth-delay produ...

d.

Explanation of Solution

“Yes” the width of the link is longer than the football field.

Reason:

The formula used for calculating the width of a bit present on the link is as follows

$Width of the bit = Length of the linkbandwidth-delay product$

The formula used for calculating the bandwidth-delay product is $R × dprop$

The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is $dprop = ms$ seconds.

Substitute, “20,000” for “m” and “2.5 ×10⁸” for “s”

The propagation delay of the link is $20000 × 1032.5 × 108 = 0$

e.

Explanation of Solution

The expression used for calculating the width of a bit in the link and length of the required link in t...

Answer 8

Chapter 1, Problem P25P

a.

Explanation of Solution

The formula used for calculating the bandwidth-delay product is $R × dprop$

The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is $dprop = ms$ seconds.

Substitute, “20,000” for “m” and “2.5 ×10⁸” for “s”

The propagation delay of the link is $20000 × 1032$

Answer 9

Chapter 1, Problem P25P

a.

Explanation of Solution

The formula used for calculating the bandwidth-delay product is $R × dprop$

The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is $dprop = ms$ seconds.

Substitute, “20,000” for “m” and “2.5 ×10⁸” for “s”

The propagation delay of the link is $20000 × 1032$

Answer 10

b.

Explanation of Solution

The size of the file transmitted from Host A to Host B is 800,000 bits...

Answer 11

b.

Explanation of Solution

The size of the file transmitted from Host A to Host B is 800,000 bits...

Answer 12

c.

Explanation of Solution

The bandwidth-delay produ...

Answer 13

c.

Explanation of Solution

The bandwidth-delay produ...

Answer 14

d.

Explanation of Solution

“Yes” the width of the link is longer than the football field.

Reason:

The formula used for calculating the width of a bit present on the link is as follows

$Width of the bit = Length of the linkbandwidth-delay product$

The formula used for calculating the bandwidth-delay product is $R × dprop$

The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is $dprop = ms$ seconds.

Substitute, “20,000” for “m” and “2.5 ×10⁸” for “s”

The propagation delay of the link is $20000 × 1032.5 × 108 = 0$

Answer 15

d.

Explanation of Solution

“Yes” the width of the link is longer than the football field.

Reason:

The formula used for calculating the width of a bit present on the link is as follows

$Width of the bit = Length of the linkbandwidth-delay product$

The formula used for calculating the bandwidth-delay product is $R × dprop$

The expression used for calculating the propagation delay in terms of meters (m) and seconds (s) is $dprop = ms$ seconds.

Substitute, “20,000” for “m” and “2.5 ×10⁸” for “s”

The propagation delay of the link is $20000 × 1032.5 × 108 = 0$

Answer 16

e.

Explanation of Solution

The expression used for calculating the width of a bit in the link and length of the required link in t...

Answer 17

e.

Explanation of Solution

The expression used for calculating the width of a bit in the link and length of the required link in t...

Answer 18

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Answer 19

Ch. 1 - What is the difference between a host and an end...Ch. 1 - The word protocol is often used to describe...Ch. 1 - Why are standards important for protocols?Ch. 1 - Prob. R4RQ Ch. 1 - Prob. R5RQ Ch. 1 - Prob. R6RQ Ch. 1 - Prob. R7RQ Ch. 1 - Prob. R8RQ Ch. 1 - Prob. R9RQ Ch. 1 - Prob. R10RQ

Explanation of Solution

Explanation of Solution

The size of the file transmitted from Host A to Host B is 800,000 bits...

Explanation of Solution

The bandwidth-delay produ...

Explanation of Solution

Explanation of Solution

The expression used for calculating the width of a bit in the link and length of the required link in t...

Want to see the full answer?

Chapter 1 Solutions