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Chapter 1 Solutions
Chemistry: Principles and Reactions
- Gold leaf, which is used for many decorative purposes, is made by hammering pure gold into very thin sheets. Assuming that a sheet of gold leaf is 1.27 105 cm thick, how many square feet of gold leaf could be obtained from 28.35 g gold? The density of gold is 19.3 g/cm3.arrow_forwardA solution is prepared by dissolving table salt, sodium chloride, in water at room temperature. a Assuming there is no significant change in the volume of water during the preparation of the solution, how would the density of the solution compare to that of pure water? b If you were to boil the solution for several minutes and then allow it to cool to room temperature, how would the density of the solution compare to the density in part a? c If you took the solution prepared in part a and added more water, how would this affect the density of the solution?arrow_forwardA 15.5 g sample of sodium carbonate is added to a solution of acetic acid weighing 19.7 g. The two substances react, releasing carbon dioxide gas to the atmosphere. After reaction, the contents of the reaction vessel weigh 28.7 g. What is the mass of carbon dioxide given off during the reaction?arrow_forward
- 1.87 A solution of ethanol in water has a volume of 54.2 mL and a mass of 49.6 g. what information would you need to look up and how would you determine the percentage of ethanol in this solution?arrow_forwardA sample of a bright blue mineral was weighed in air, then weighed again while suspended in water. An object is buoyed up by the mass of the fluid displaced by the object. In air, the mineral weighed 7.35 g; in water, it weighed 5.40 g. The densities of air and water are 1.205 g/L and 0.9982 g/cm3, respectively. What is the density of the mineral?arrow_forwardExpress the measurements to the requested number of significant figures. (a) 96,485 J/C to three significant figures (b) 2.9979 g/cm3 to three significant figures (c) 0.0597 mL to one significant figure (d) 6.626 1034 kg to two significant figuresarrow_forward
- The label on a bale of mulch indicates a volume of 1.45 ft3. The label also states that the mulch in the bale will cover an area of a garden 6 ft 6 ft to a depth of 1 in. Account for the discrepancy in the given volumes.arrow_forwardmol A chemist must prepare 875. mL of 10.0 mM aqueous calcium sulfate (CaSO) working solution. He'll do this by pouring out some 0.0110 aqueous L calcium sulfate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the calcium sulfate stock solution that the chemist should pour out. Be sure your answer has the correct number of significant digits. mL x10arrow_forwardA chemist prepares a solution of silver perchlorate (AgCIO4) by weighing out 253.2 g of silver perchlorate into a 50. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in g/L of the chemist's silver perchlorate solution. Be sure your answer has the correct number of significant digits. g x10 ?arrow_forward
- A chemist must dilute 28.6 mL of 801. mM aqueous aluminum sulfate (Al₂(SO4)3) solution until the concentration falls to 183. mM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Round your answer to 3 significant digits. 0 x10 X S ?arrow_forwardTUMS is a popular remedy for acid indigestion. A typical TUMS tablet contains calcium carbonate plus some inert substances. When ingested, it reacts with the gastric juice (hydrochloric acid) in the stomach to give off carbon dioxide gas. When a 1.371 g tablet reacted with 40.00 mL of hydrochloric acid (density 1.140 ), carbon dioxide gas was given off, and the resulting solution weighed 46.699 g. Calculate the number of liters of carbon dioxide gas ml released if its density is 1.81 Be sure your answer has the correct number of significant digits. Save For Later Submit A Check ©2021 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center 82 F PType here to search 199+arrow_forwardA chemist must dilute 15.5 mL of 5.62 M aqueous sodium chloride (NaCl) solution until the concentration falls to 2.00 M. He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Be sure your answer has the correct number of significant digits. I mL x10 ?arrow_forward
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