The label on a bale of mulch indicates a volume of 1.45 ft3. The label also states that the mulch in the bale will cover an area of a garden 6 ft 6 ft to a depth of 1 in. Account for the discrepancy in the given volumes.

A sample of a bright blue mineral was weighed in air, then weighed again while suspended in water. An object is buoyed up by the mass of the fluid displaced by the object. In air, the mineral weighed 7.35 g; in water, it weighed 5.40 g. The densities of air and water are 1.205 g/L and 0.9982 g/cm3, respectively. What is the density of the mineral?

A person weighed 15 pennies on a balance and recorded the following masses: 3.112 g 3.109 g 3.059 g 2.467 g 3.079 g 2.518 g 3.129 g 2.545 g 3.050 g 3.053 g 3.054 g 3.072 g 3.081 g 3.131 g 3.064 g Curious about the results, he looked at the dates on each penny. Two of the light pennies were minted in 1983 and one in 1982. The dates on the 12 heavier pennies ranged from 1970 to 1982. Two of the 12 heavier pennies were minted in 1982. a. Do you think the Bureau of the Mint changed the way it made pennies? Explain. b. The person calculated the average mass of the 12 heavy pennies. He expressed this average as 3.0828 g 0.0482 g. What is wrong with the numbers in this result, and how should the value be expressed?

For these questions, be sure to apply the rules for significant figures. a You are conducting an experiment where you need the volume of a box; you take the length, height, and width measurements and then multiply the values together to find the volume. You report the volume of the box as 0.310 m1. If two of your measurements were 0.7120 m and 0.52145 m, what was the other measurement? b If you were to add the two measurements from the first part of the problem to a third length measurement with the reported result of 1.509 m, what was the value of the third measurement?

How many significant figures would this calculation have if it were completed: (9.04 - 8.23 + 21.954 + 81.0) × 3.1416

Perform the calculations below and give the results with correct significant figures. 27.8 g + 5.461 g − 3.89 g = 2.13 in × 0.96 in × 4.508 in = (1.751 × 42.2) − (8.02 × 103 ÷ 764) =  g  in3

When adding or dividing measured numbers, we don’t count significant figures. Instead, we look at the precision of the measured numbers. The answer can only be as precise as the least precise measurement.

A thief plans to steal a gold sphere with a radius of 28.4 cm from a museum. If the gold has a density of 19.3 g/cm^3, what is the mass of the sphere in pounds? [The volume of a sphere is V=(4/3)πr^3]. Express your answer in pounds to 3 significant figures.

Express each answer with the correct significant digits, and the proper units AND write it in scientific notation number, units. Note: Input derived units as unit power, for example mm^2 represents mm? (2.456 x 10° Ibs - 8.34 x 10 Ibs)/1.22 x 10 in? x 10