EBK ORGANIC CHEMISTRY
6th Edition
ISBN: 8220103151757
Author: LOUDON
Publisher: MAC HIGHER
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Question
Chapter 1, Problem 1.5P
Interpretation Introduction
(a)
Interpretation:
The formal charges on each atom of the given structure are to be computed. Also, the charge on the entire structure is to be stated.
Concept introduction:
A charge that is assigned to an atom, on the assumption that all the electrons in the
The formal charge on an atom is calculated by the formula,
Interpretation Introduction
(b)
Interpretation:
The formal charges on each atom of the given structure are to be computed. Also, the charge on the entire structure is to be stated.
Concept introduction:
A charge that is assigned to an atom, on the assumption that all the electrons in the chemical bonds are equally shared, is known as the formal charge. The sum of the formal charges on the independent atoms should equal the total charge present on the ion.
The formal charge on an atom is calculated by the formula,
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Students have asked these similar questions
Consider compounds A–D, which contain both a heteroatom and a double bond.
(a) For which compounds are no additional Lewis structures possible?
(b) When two or more Lewis structures can be drawn, draw all additional resonance structures.
Draw Lewis structures for each of the following compounds. In each case, specify the number of valence electrons surrounding the central atom. (Assign lone pairs and radical electrons where appropriate.)
(Assume the central atom does not contain an expanded octet.)
(a) bromine dioxide (BrO2)
(b) beryllium bromide (BeBr2)
(c) phosphorus pentafluoride (PF5)
The molecular ion S3N, has the cyclic structure
'N
All S-N bonds are equivalent.
(a) Give six equivalent resonance hybrid Lewis diagrams
for this molecular ion.
(b) Compute the formal charges on all atoms in the
molecular ion in each of the six Lewis diagrams.
(c) Determine the charge on each atom in the polyatomic
ion, assuming that the true distribution of electrons is
the average of the six Lewis diagrams arrived at in
parts (a) and (b).
(d) An advanced calculation suggests that the actual
charge resident on each N atom is –0.375 and on
each S atom is +0.041. Show that this result is consis-
tent with the overall +1 charge on the molecular ion.
Z-S
Chapter 1 Solutions
EBK ORGANIC CHEMISTRY
Ch. 1 - Prob. 1.1PCh. 1 - Prob. 1.2PCh. 1 - Prob. 1.3PCh. 1 - Prob. 1.4PCh. 1 - Prob. 1.5PCh. 1 - Prob. 1.6PCh. 1 - Prob. 1.7PCh. 1 - Prob. 1.8PCh. 1 - Prob. 1.9PCh. 1 - Prob. 1.10P
Ch. 1 - Prob. 1.11PCh. 1 - Prob. 1.12PCh. 1 - Prob. 1.13PCh. 1 - Prob. 1.14PCh. 1 - Prob. 1.15PCh. 1 - Prob. 1.16PCh. 1 - Prob. 1.17PCh. 1 - Prob. 1.18PCh. 1 - Prob. 1.19PCh. 1 - Prob. 1.20PCh. 1 - Prob. 1.21APCh. 1 - Prob. 1.22APCh. 1 - Prob. 1.23APCh. 1 - Prob. 1.24APCh. 1 - Prob. 1.25APCh. 1 - Prob. 1.26APCh. 1 - Prob. 1.27APCh. 1 - Prob. 1.28APCh. 1 - Prob. 1.29APCh. 1 - Prob. 1.30APCh. 1 - Prob. 1.31APCh. 1 - Prob. 1.32APCh. 1 - Prob. 1.33APCh. 1 - Prob. 1.34APCh. 1 - Prob. 1.35APCh. 1 - Prob. 1.36APCh. 1 - Prob. 1.37APCh. 1 - Prob. 1.38APCh. 1 - Prob. 1.39APCh. 1 - Prob. 1.40APCh. 1 - Prob. 1.41APCh. 1 - Prob. 1.42APCh. 1 - Prob. 1.43APCh. 1 - Prob. 1.44APCh. 1 - Prob. 1.45APCh. 1 - Prob. 1.46APCh. 1 - Prob. 1.47APCh. 1 - Prob. 1.48APCh. 1 - Prob. 1.49AP
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