A tensile load of 190 kN is applied to a round metal bar with a diameter of 16 mm and a gage length of 50 mm. Under this load the bar elastically deforms so that the gage length increases to 50.1349 mm and the diameter decreases to 15.99 mm. Determine the modulus of elasticity and Poisson’s ratio for this metal.
Learn your wayIncludes step-by-step video
Chapter 1 Solutions
Pearson eText for Materials for Civil and Construction Engineers -- Instant Access (Pearson+)
Additional Engineering Textbook Solutions
Problem Solving with C++ (10th Edition)
BASIC BIOMECHANICS
Introduction To Programming Using Visual Basic (11th Edition)
Starting Out with Programming Logic and Design (5th Edition) (What's New in Computer Science)
Starting Out with Java: From Control Structures through Data Structures (4th Edition) (What's New in Computer Science)
Java: An Introduction to Problem Solving and Programming (8th Edition)
- The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.arrow_forwardA tensile test was performed on a metal specimen having a circular cross section with a diameter of 1 2 inch. The gage length (the length over which the elongation is measured) is 2 inches. For a load 13.5 kips, the elongation was 4.6610 3 inches. If the load is assumed to be within the linear elastic rang: of the material, determine the modulus of elasticity.arrow_forward3. The distribution of stress in an aluminum machine component is given (in megapascals) by Ox = y + z? Oy = x + z Oz = 3x + y Txy = 3z2 Tyz = x Txz = %3D Calculate the state of strain at a point positioned at (1,2,4). Use E=70 GPa and v = 0.3arrow_forward
- The following figure shows the tensile stress-strain curve for a plain-carbon steel. 600 80 500 MPa 600 10 psi 60 80 400 400 60- 300 40 40 200 200 20 20 100 0.005 0.05 0.10 0.15 Strain (a) What is this alloy's tensile strength? MPа (b) What is its modulus of elasticity? GPa (c) What is the yield strength? i MPa Stress (MPa) Stress (10 psi)arrow_forwardThe shown figure represents the stress-strain relations of metals A and B during tension tests until fracture.Determine the following for the two metals (show all calculations and units):a. Proportional limitb. Yield stress at an offset strain of 0.002 in./in.c. Ultimate strengthd. Modulus of resiliencee. Toughnessf. Which metal is more ductile? Why?arrow_forwardThe stress-strain diagram for a steel alloy having an original diameter of 0.5 in. and a gage length of 2 in. is given in the figure. If the specimen is loaded until it is stressed to 70 ksi, determine the approximate amount of elastic recovery and the increase in the gage length after it is unloaded. o (ksi) 80 70 60 50 40 30 20 10 e (in./in.) 0 04 0.08 0.12 0.16 0.20 0.24 0.28 0 0005 0.0010.0015 0.002 0.0025 0.0030.0035arrow_forward
- Solid mechanicsarrow_forwardA 19-mm reinforcing steel bar and a gauge length of 75 mm was subjected to ten- sion, with the results shown in Table P3.27. Using a computer spreadsheet pro- gram, plot the stress-strain relationship. From the graph, determine the Young's modulus of the steel and the deformation corresponding to a 150-kN load. TABLE P3.27 Load, kN Deformation, mm 54 0.084 163 0.168 284 0.336 330 1.428 366 3.360arrow_forward1. The following data were obtained during a tension test of an aluminum alloy. The initial diameter of the test specimen was 0.505 in., and the gage length was 2.0 in. Load ( Ib) Elongation (in.) Load ( Ib) Elongation (in.) 14000 0.020 2310 0.0022 14400 0.025 4640 0.0044 14 500 0.060 6950 0.0066 14600 0.080 9290 0.0088 14800 0.100 I1 600 0.0110 14600 0.120 13000 0.01 50 13600 Fracture Plot the stress-strain diagram and determine the following mechanical properties: a. proportional limit þ. modulus of elasticity S. vield stress at 0.2% offset d. ultimate stress e. nominal rupture stress.arrow_forward
- Problem 6arrow_forwardA force of 100,000 N is applied to an iron bar with a cross-sectional area of 10 mm × 20mm and having a yield strength of 400 MPa and a tensile strength of 480 MPa,Determinea. whether the bar will plastically deform; andb. whether the bar will experience neckingarrow_forwardA tensile load of 150kN is applied to a round metal bar with a diameter of 16mm and a gage length of 80mm. Under this load, the bar elastically deforms so that the gage length increases to 80.1192mm and the diameter decreases to 15.89mm. a.) Modulus of elasticity (MPa)b.) Poisson's ratio for this metalarrow_forward
- Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage LearningMaterials Science And Engineering PropertiesCivil EngineeringISBN:9781111988609Author:Charles GilmorePublisher:Cengage Learning