Glencoe Algebra 2 Student Edition C2014
Glencoe Algebra 2 Student Edition C2014
1st Edition
ISBN: 9780076639908
Author: McGraw-Hill Glencoe
Publisher: MCG
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Question
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Chapter 0.6, Problem 17E

(a)

To determine

Probability for student is a freshman has not attended a game.

(a)

Expert Solution
Check Mark

Answer to Problem 17E

Probability that student is a freshman has not attended a game is approx. 0.79.

Explanation of Solution

Given information:

Number of students who have attended a football game at North Coast High School:

    ClassFreshmanSophomoreJuniorSenior
    attended4890224254
    not attended182141368

Calculations:

According to the conditional probability,

  P(B|A)=P(AB)P(A)=P(AandB)P(A)

Calculate the table total:

    ClassFreshmanSophomoreJuniorSeniorTotal
    attended4890224254616
    not attended182141368367
    Total230231260262983

Note that

The information about 983 students is provided in the table.

Thus,

The number of possible outcomes is 983.

Also note that

In the table, 182 freshman students of the 983total students not attended the class.

Thus,

The number of favorable outcomes is 182.

When the number of favorable outcomes is divided by the number of possible outcomes, we get the probability.

  P(FreshmanandNotattended)=NumberoffavourableoutcomesNumberofpossibleoutcomes=182983

Now,

Note that

In the table, 230 of 983 students are freshman.

In this case, the number of favorable outcomes is 230 and number of possible outcomes is 983.

  P(Freshman)=NumberoffavourableoutcomesNumberofpossibleoutcomes=230983

Apply the conditional probability:

  P(Notattended|Freshman)=P(FreshmanandNotattended)P(Freshman)=182983230983=182230=911150.79

Thus,

The conditional probability for student is a freshman has not attended a game is approx. 0.79.

(b)

To determine

Probability for student has attended a game is an upperclassman (a junior or a senior).

(b)

Expert Solution
Check Mark

Answer to Problem 17E

Probability that student has attended a game is an upperclassman is approx. 0.78.

Explanation of Solution

Given information:

Number of students who have attended a football game at North Coast High School:

    ClassFreshmanSophomoreJuniorSenior
    attended4890224254
    not attended182141368

Calculations:

According to the conditional probability,

  P(B|A)=P(AB)P(A)=P(AandB)P(A)

In this case, table becomes

    ClassFreshmanSophomoreUpperclassmanTotal
    attended4890478616
    not attended18214144367
    Total230231522983

Note that

The information about 983 students is provided in the table.

Thus,

The number of possible outcomes is 983.

Also note that

In the table calculated above, 478 of the 983 students attended the class are upperclassman.

Thus,

The number of favorable outcomes is 478.

When the number of favorable outcomes is divided by the number of possible outcomes, we get the probability.

  P(AttendedandUpperclassman)=NumberoffavourableoutcomesNumberofpossibleoutcomes=478983

Now,

Note that

In the table, 616 of 983 students attended the class.

In this case, the number of favorable outcomes is 616 and number of possible outcomes is 983.

  P(Attended)=NumberoffavourableoutcomesNumberofpossibleoutcomes=616983

Apply the conditional probability:

  P(Upperclassman|Attended)=P(AttendedandUpperclassman)P(Attended)=478983616983=478616=2393080.78

Thus,

The conditional probability for student has attended a game is an upperclassman isapprox. 0.78.

Chapter 0 Solutions

Glencoe Algebra 2 Student Edition C2014

Ch. 0.1 - Prob. 11ECh. 0.1 - Prob. 12ECh. 0.2 - Prob. 1ECh. 0.2 - Prob. 2ECh. 0.2 - Prob. 3ECh. 0.2 - Prob. 4ECh. 0.2 - Prob. 5ECh. 0.2 - Prob. 6ECh. 0.2 - Prob. 7ECh. 0.2 - Prob. 8ECh. 0.2 - Prob. 9ECh. 0.2 - Prob. 10ECh. 0.2 - Prob. 11ECh. 0.2 - Prob. 12ECh. 0.2 - Prob. 13ECh. 0.2 - Prob. 14ECh. 0.2 - Prob. 15ECh. 0.2 - Prob. 16ECh. 0.2 - Prob. 17ECh. 0.2 - Prob. 18ECh. 0.3 - Prob. 1ECh. 0.3 - Prob. 2ECh. 0.3 - Prob. 3ECh. 0.3 - Prob. 4ECh. 0.3 - Prob. 5ECh. 0.3 - Prob. 6ECh. 0.3 - Prob. 7ECh. 0.3 - Prob. 8ECh. 0.3 - Prob. 9ECh. 0.3 - Prob. 10ECh. 0.3 - Prob. 11ECh. 0.3 - Prob. 12ECh. 0.3 - Prob. 13ECh. 0.3 - Prob. 14ECh. 0.3 - Prob. 15ECh. 0.3 - Prob. 16ECh. 0.3 - Prob. 17ECh. 0.3 - Prob. 18ECh. 0.3 - Prob. 19ECh. 0.3 - Prob. 20ECh. 0.3 - Prob. 21ECh. 0.3 - Prob. 22ECh. 0.3 - Prob. 23ECh. 0.3 - Prob. 24ECh. 0.4 - Prob. 1ECh. 0.4 - Prob. 2ECh. 0.4 - Prob. 3ECh. 0.4 - Prob. 4ECh. 0.4 - Prob. 5ECh. 0.4 - Prob. 6ECh. 0.4 - Prob. 7ECh. 0.4 - Prob. 8ECh. 0.4 - Prob. 9ECh. 0.4 - Prob. 10ECh. 0.4 - Prob. 11ECh. 0.4 - Prob. 12ECh. 0.4 - Prob. 13ECh. 0.4 - Prob. 14ECh. 0.4 - Prob. 15ECh. 0.4 - Prob. 16ECh. 0.4 - Prob. 17ECh. 0.4 - Prob. 18ECh. 0.4 - Prob. 19ECh. 0.5 - Prob. 1ECh. 0.5 - Prob. 2ECh. 0.5 - Prob. 3ECh. 0.5 - Prob. 4ECh. 0.5 - Prob. 5ECh. 0.5 - Prob. 6ECh. 0.5 - Prob. 7ECh. 0.5 - Prob. 8ECh. 0.5 - Prob. 9ECh. 0.5 - Prob. 10ECh. 0.6 - Prob. 1ECh. 0.6 - Prob. 2ECh. 0.6 - Prob. 3ECh. 0.6 - Prob. 4ECh. 0.6 - Prob. 5ECh. 0.6 - Prob. 6ECh. 0.6 - Prob. 7ECh. 0.6 - Prob. 8ECh. 0.6 - Prob. 9ECh. 0.6 - Prob. 10ECh. 0.6 - Prob. 11ECh. 0.6 - Prob. 12ECh. 0.6 - Prob. 13ECh. 0.6 - Prob. 14ECh. 0.6 - Prob. 15ECh. 0.6 - Prob. 16ECh. 0.6 - Prob. 17ECh. 0.7 - Prob. 1ECh. 0.7 - Prob. 2ECh. 0.7 - Prob. 3ECh. 0.7 - Prob. 4ECh. 0.7 - Prob. 5ECh. 0.7 - Prob. 6ECh. 0.7 - Prob. 7ECh. 0.7 - Prob. 8ECh. 0.7 - Prob. 9ECh. 0.7 - Prob. 10ECh. 0.7 - Prob. 11ECh. 0.7 - Prob. 12ECh. 0.8 - Prob. 1ECh. 0.8 - Prob. 2ECh. 0.8 - Prob. 3ECh. 0.8 - Prob. 4ECh. 0.8 - Prob. 5ECh. 0.8 - Prob. 6ECh. 0.8 - Prob. 7ECh. 0.8 - Prob. 8ECh. 0.8 - Prob. 9ECh. 0.8 - Prob. 10ECh. 0.8 - Prob. 11ECh. 0.8 - Prob. 12ECh. 0.8 - Prob. 13ECh. 0.8 - Prob. 14ECh. 0.8 - Prob. 15ECh. 0.8 - Prob. 16ECh. 0.8 - Prob. 17ECh. 0.8 - Prob. 18ECh. 0.9 - Prob. 1ECh. 0.9 - Prob. 2ECh. 0.9 - Prob. 3ECh. 0.9 - Prob. 4ECh. 0.9 - Prob. 5ECh. 0.9 - Prob. 6ECh. 0.9 - Prob. 7ECh. 0.9 - Prob. 8ECh. 0.9 - Prob. 9ECh. 0.9 - Prob. 10ECh. 0.9 - Prob. 11ECh. 0 - Prob. 1PRCh. 0 - Prob. 2PRCh. 0 - Prob. 3PRCh. 0 - Prob. 4PRCh. 0 - Prob. 5PRCh. 0 - Prob. 6PRCh. 0 - Prob. 7PRCh. 0 - Prob. 8PRCh. 0 - Prob. 9PRCh. 0 - Prob. 10PRCh. 0 - Prob. 11PRCh. 0 - Prob. 12PRCh. 0 - Prob. 13PRCh. 0 - Prob. 14PRCh. 0 - Prob. 15PRCh. 0 - Prob. 16PRCh. 0 - Prob. 17PRCh. 0 - Prob. 18PRCh. 0 - Prob. 19PRCh. 0 - Prob. 20PRCh. 0 - Prob. 21PRCh. 0 - Prob. 22PRCh. 0 - Prob. 23PRCh. 0 - Prob. 24PRCh. 0 - Prob. 25PRCh. 0 - Prob. 26PRCh. 0 - Prob. 27PRCh. 0 - Prob. 28PRCh. 0 - Prob. 29PRCh. 0 - Prob. 30PRCh. 0 - Prob. 1POCh. 0 - Prob. 2POCh. 0 - Prob. 3POCh. 0 - Prob. 4POCh. 0 - Prob. 5POCh. 0 - Prob. 6POCh. 0 - Prob. 7POCh. 0 - Prob. 8POCh. 0 - Prob. 9POCh. 0 - Prob. 10POCh. 0 - Prob. 11POCh. 0 - Prob. 12POCh. 0 - Prob. 13POCh. 0 - Prob. 14POCh. 0 - Prob. 15POCh. 0 - Prob. 16POCh. 0 - Prob. 17POCh. 0 - Prob. 18POCh. 0 - Prob. 19POCh. 0 - Prob. 20POCh. 0 - Prob. 21POCh. 0 - Prob. 22POCh. 0 - Prob. 23POCh. 0 - Prob. 24POCh. 0 - Prob. 25POCh. 0 - Prob. 26POCh. 0 - Prob. 27POCh. 0 - Prob. 28POCh. 0 - Prob. 29POCh. 0 - Prob. 30PO
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